Mr. Hoya brought 5 watermelons from his grocery store. The watermelons weighed 8.25 pounds, 9.25 pounds, 8.875 pounds, 9.625 pounds and 10.75 pounds. At the party, 153 people each ate a 0.25 pound serving of watermelon. Was the amount of leftover watermelon less than, greater than, or equal to 8.5 pounds? Explain how to solve the problem.

Answers

Answer 1
Answer: The first thing we must do for this case is to find the total weight of the watermelons.
 We have then:
 W = 8.25 + 9.25 + 8.875 + 9.625 + 10.75 W = 46.75 pounds
 We now look for the amount of watermelons that people ate.
 We have then:
 (0.25) * (153) = 38.25 pounds
 Therefore, the amount of watermelon remaining is:
 46.75 - 38.25 = 8.5 pounds
 We note that the amount of watermelon remaining is equal to 8.5 pounds.
 Answer:
 
the amount of leftover watermelon is: equal to 8.5 pounds
Answer 2
Answer: Answer:
The amount of leftover watermelon is equal to 8.5 pounds

Explanation:
1- getting the total weight of the watermelon:
The total weight of the watermelon will be the summation of the weights of the 5 watermelons he bought.
This means that:
Total weight = 8.25 + 9.25 + 8.875 + 9.625 + 10.75
Total weight = 46.75 pounds

2- getting the weight of the eaten watermelon:
We know that at the party, there were 153 people and each ate 0.25 of a pound of watermelon.
This means that:
amount eaten = 153 * 0.25
amount eaten = 38.25 pounds

3- getting the weight of the leftover:
weight of leftover = total weight - amount eaten
We have:
Total weight = 46.75 pounds
amount eaten = 38.25 pounds
Therefore:
weight of leftover = 46.75 - 38.25
weight of leftover = 8.5 pounds

Hope this helps :)

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Answers

The parametric equations are:

x  =  -4  +  5t

y  =  4  +  5t

z  =  -2  - 6t

The given direction vector is:

\bar{V} = 5i + 5j - 6k

The direction vector can also be written as:

\bar{V} = <a, b, c> =  <5, 5, -6>

The point X₀ = (x₀, y₀, z₀) =  (-4, 4, -2)

The parametric equation is of the form:

X = X_(0) + \bar{V}t

This is:

\left[\begin{array}{ccc}x\ny\nz\end{array}\right] = \left[\begin{array}{ccc}x_0\ny_0\nz_0\end{array}\right] + \left[\begin{array}{ccc}a\nb\nc\end{array}\right]t

\left[\begin{array}{ccc}x\ny\nz\end{array}\right] = \left[\begin{array}{ccc}-4\n4\n-2\end{array}\right] + \left[\begin{array}{ccc}5\n5\n-6\end{array}\right]t

The parametric equations are therefore:

x  =  -4  +  5t

y  =  4  +  5t

z  =  -2  - 6t

Learn more here: brainly.com/question/13072659

Answer:

x=5t-4 , y=5t+4 , z=-6t-2

Step-by-step explanation:

So we are going to use (-4,4,-2) as an initial point, p.  

The direction vector is v=5i+5j-6k or <5,5,-6>.

The vector equation is r=vt+p.

That means we have r=<5,5,-6>t       +      <-4,4,-2>.

So the parametric equations are

x=5t-4

y=5t+4

z=-6t-2

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