Answer:
### Final answer:

### Explanation:

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The maximum frictional force acting on the object is 28 newtons.

The maximum frictional force acting on an object can be calculated using the formula:

Frictional force = coefficient of static friction x normal force

Given that the coefficient of static friction is 0.35 and the normal force is 80 newtons, we can calculate the maximum frictional force as follows:

Maximum frictional force = 0.35 x 80 = **28 newtons**

Some radar systems detect the size and shape of objects such as aircraft and geological terrain. What is the frequency of such a system which can detect objects as small as 19.1 cm?

A truck’s suspension spring each have a spring constant of 769 N/m. If the potential energy of the right front spring is 250 J, how far is the spring compressed?

Every few years, winds in Boulder, Colorado, attain sustained speeds of 45.0 m/s (about 100 mi/h) when the jet stream descends during early spring. show answer No Attempt Approximately what is the force due to the Bernoulli effect on a roof having an area of 205 m2? Typical air density in Boulder is 1.14 kg/m3 , and the corresponding atmospheric pressure is 8.89 × 104 N/m2 . (Bernoulli’s principle assumes a laminar flow. Using the principle here produces only an approximate result, because there is significant turbulence.)

A 2.00 kg cart on a frictionless track is pulled by force of 3.00 N. What is the acceleration of the cart?

A swimmer heads directly across a river, swimming at 1.00 m/s relative to still water. He arrives at a point 41.0 m downstream from the point directly across the river, which is 73.0 m wide. What is the speed of the river current?

A truck’s suspension spring each have a spring constant of 769 N/m. If the potential energy of the right front spring is 250 J, how far is the spring compressed?

Every few years, winds in Boulder, Colorado, attain sustained speeds of 45.0 m/s (about 100 mi/h) when the jet stream descends during early spring. show answer No Attempt Approximately what is the force due to the Bernoulli effect on a roof having an area of 205 m2? Typical air density in Boulder is 1.14 kg/m3 , and the corresponding atmospheric pressure is 8.89 × 104 N/m2 . (Bernoulli’s principle assumes a laminar flow. Using the principle here produces only an approximate result, because there is significant turbulence.)

A 2.00 kg cart on a frictionless track is pulled by force of 3.00 N. What is the acceleration of the cart?

A swimmer heads directly across a river, swimming at 1.00 m/s relative to still water. He arrives at a point 41.0 m downstream from the point directly across the river, which is 73.0 m wide. What is the speed of the river current?

Distance traveled by the bicycle during the 5 seconds of braking is **22m**

**Explanation:**

initial angular velocity= 2 rev/s

final angular velocity= 0 rev/s

Angular displacement Ф=t

Ф= rev

so the distance travelled= 5(2πr)

distance=5(2π*0.7)

**distance=22m**

The bicycle traveled about **22 m **during the 5.0 seconds of braking

**Centripetal Acceleration **can be formulated as follows:

*a = Centripetal Acceleration ( m/s² )*

*v = Tangential Speed of Particle ( m/s )*

*R = Radius of Circular Motion ( m )*

**Centripetal Force **can be formulated as follows:

*F = Centripetal Force ( m/s² )*

*m = mass of Particle ( kg )*

*v = Tangential Speed of Particle ( m/s )*

*R = Radius of Circular Motion ( m )*

Let us now tackle the problem !

__Given:__

radius of wheel = R = 0.70 m

initial angular speed = ω = 2.0 rev/s = 4π rad/s

final angular speed = ωo = 0 rad/s

time taken = t = 5.0 s

__Asked:__

distance covered = d = ?

__Solution:__

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**Grade: **High School

**Subject: **Physics

**Chapter: **Circular Motion

**Answer:**

The force constant of the spring is 735 N/m.

**Explanation:**

It is given that,

Mass of fruit, m = 1500 g = 1.5 kg

Compression in the scale, x = 0.02 m

We need to find the force constant of the spring on the scale. The force acting on the scale is given by using Hooke's law. So,

Also, F = mg

k is force constant

So, the force constant of the spring is 735 N/m.

**Answer:**

a. 409.5 m/s b. f₁ = 136.5 Hz, f₂ = 409.5 Hz, f₃ = 682.5 Hz

**Explanation:**

**a.** The speed of sound v in a gas is v = √(B/ρ) where B = bulk modulus and ρ = density. Given that on Venus, B = 1.09 × 10⁷ N/m² and ρ = 65.0 kg/m³

So, v = √(B/ρ)

= √(1.09 × 10⁷ N/m²/65.0 kg/m³)

= √(0.01677 × 10⁷ Nm/kg)

= √(0.1677 × 10⁶ Nm/kg)

= 0.4095 × 10³ m/s

= 409.5 m/s

**b.** For a pipe open at one end, the frequency f = nv/4L where n = mode of wave = 1,3,5,.., v = speed of wave = 409.5 m/s and L = length of pipe = 75.0 cm = 0.75 m

Now, for the first mode or frequency, n = 1

f₁ = v/4L

= 409.5 m/s ÷ (4 × 0.75 m)

= 409,5 m/s ÷ 3 m

= 136.5 Hz

Now, for the second mode or frequency, n = 2

f₂ = 3v/4L

= 3 ×409.5 m/s ÷ (4 × 0.75 m)

= 3 × 409,5 m/s ÷ 3 m

= 3 × 136.5 Hz

= 409.5 Hz

Now, for the third mode or frequency, n = 5

f₃ = 5v/4L

= 5 × 409.5 m/s ÷ (4 × 0.75 m)

= 5 × 409,5 m/s ÷ 3 m

= 682.5 Hz

**Answer:**

**115 ⁰C**

**Explanation:**

__ Step 1:__ The heat needed to melt the solid at its melting point will come from the warmer water sample. This implies

-----eqution 1

where,

is the heat absorbed by the solid at 0⁰C

is the heat absorbed by the liquid at 0⁰C

the heat lost by the warmer water sample

Important equations to be used in solving this problem

, where -----equation 2

q is heat absorbed/lost

m is mass of the sample

c is specific heat of water, = **4.18 J/0⁰C**

is change in temperature

Again,

-------equation 3

where,

q is heat absorbed

n is the number of moles of water

tex]\delta {_f_u_s}[/tex] is the molar heat of fusion of water, = **6.01 kJ/mol**

__ Step 2:__ calculate how many moles of water you have in the 100.0-g sample

** Step 3: **calculate how much heat is needed to allow the sample to go from solid at 218⁰C to liquid at 0⁰C

This means that equation (1) becomes

79.13 KJ +

__ Step 4:__ calculate the final temperature of the water

Substitute in the values; we will have,

79.13 kJ + 990.66J* = -1463J*

Convert the joules to kilo-joules to get

79.13 kJ + 0.99066KJ* = -1.463KJ*

collect like terms,

2.45366 = 283.133

**∴ = 115.4 ⁰C**

**Approximately the final temperature of the mixture is 115 ⁰C**

**Answer:**

The power exerted by the mountain lion is **1,472.35 W.**

**Explanation:**

Given;

mass of mountain, m₁ = 21 kg

mass of the cub, m₂ = 3 kg

height jumped by the mountain lion, h = 2 m

time taken for the mountain lion to jump, t = 1 s

Determine the weight of the lions on the top rock;

W = F = (m₁ + m₂)g

F = (21 + 3) x 9.8

F = (24) x 9.8

F = 235.2 N

Determine the final velocity of the mountain rock as it jumped to the top;

v² = u² + 2gh

where;

u is the initial velocity = 0

h is the height jumped = 2 m

v² = 0 + 2 x 9.8 x 2

v² = 39.2

v = √39.2

v = 6.26 m/s

The power exerted by the mountain lion is calculated as;

P = Fv

P = 235.2 x 6.26

P =** 1,472.35 W**

Therefore, the power exerted by the mountain lion is **1,472.35 W.**

2. The earth is heated and its atmosphere is cooled by terrestrial radiation.

3. The earth is cooled and its atmosphere is heated by terrestrial radiation.

4. The earth is heated and its atmosphere is cooled by solar radiation.

Don't answer unless you know for sure. Thank you so much!

Answer: The option 4 is correct answer.

Explanation:

Terrestrial radiation is a long wave electromagnetic radiation. It originates from the earth and its atmosphere.

The sun emits a huge amount of energy. It travels across the space. **The atmosphere is not directly heated by the solar radiation. It is heated by the terrestrial radiation that the planet itself emits. **

When the land is heated then it emits radiation which heats up the atmosphere.

The earth is cooled and its atmosphere is heated by terrestrial radiation.

Therefore, the relationship between the earth, its atmosphere and radiation is correctly compared by statement 4.

The earth is cooled and its atmosphere is heated by terrestrial radiation.