Which of the following is true for the quantum mechanical atomic model? A. Atoms absorb or emit electrons from the nucleus when they interact with electromagnetic radiation.

B. Every atom absorbs all wavelengths of light energy or electromagnetic radiation.

C. Electrons give off electromagnetic radiation when they jump from a high to a low energy level.

D. Electrons are perfectly evenly distributed throughout the atom.​​


Answer 1

Answer: C. Electrons give off electromagnetic radiation when they jump from a high to a low energy level.


 Electrons give off electromagnetic radiation when they jump from a high to a low energy level in the quantum mechanical atomic model. This is known as the emission spectrum of an atom, and each element has its unique emission spectrum. This phenomenon was explained by the Bohr model of the atom and is a fundamental concept of the quantum mechanical atomic model.

 Option A is incorrect because atoms cannot absorb or emit electrons from the nucleus when they interact with electromagnetic radiation. Option B is also incorrect because atoms only absorb certain wavelengths of light energy or electromagnetic radiation, which corresponds to the energy difference between electron energy levels. Option D is incorrect because electrons are not evenly distributed throughout the atom in the quantum mechanical atomic model; instead, they occupy specific energy levels or orbitals.

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Hydrochloric acid reacts with sodium hydroxide to produce sodium chloride and water. If 20.6 g of sodium hydroxide reacts with an excess of hydrochloric acid, how many grams of sodium chloride are produced? HCl + NaOH → NaCl + H2O



30.1 g NaCl


Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.

20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl

Which choice(s) include(s) d-orbital contribution in the hybridization scheme: pcl3, no3─, i3─, h2se ?


Among all three PCl₃, NO₃⁻ , I₃⁻, H₂Se only I₃⁻ will involve participation of d-orbitals in hybridization as bonding in I₃⁻ will include, s, p and d orbital as shown in the image attached. there will be sp³d hybridization, there will be presence of three lone pairs and 2 bonds as

I⁻ has 8 valence electrons and 2 neighbours atoms which will need one electron each to satisfy their valency.

so the number of electrons on central atom will be:


That 6 electrons will make 6/2 =3 lone pairs.

(01.04 LC)What phase of matter has particles that are held together but can flow past each
other and takes the shape of a container, filling it from the bottom up? (3 points)
1) Gas
2) Liquid
3) Plasma
4) Solid


the answer is liquid ! hope this helped :)

For your sink at home, the flow rate in is 5000 units/hr. Accumulation is 2500 units. What is the accumulation rate if the out flow is 60 units/min? multiple choicea) 2400 units/hr b) 400 units/hr c)100 units/hr d) 1400 units/hr e) 3400 units/hr

f) other ____________________



  • Option d) 1400 units/hr


Using law of conservation of mass, you can do a mass balance or volume balance:

  • Volume in - Volume out = Volume accumulation

If you divide by time unit, you get flow balance:

  • Volume in / time - Volume out / time = Volume accumulation / time

  • Flow rate in - Flow rate out =  Accumulation rate

Here you have:

  • Flow rate in = 5000 units/h

  • Flow rate out = 60 units/min

        Convert to rate in units/h: (60 units /min) × (60 min/h) = 3600 units/h

        Flow rate out = 3600 units/h


  • Accumulation rate = 5000 units/h - 3600 units/h = 1400 units/h

Draw the structure that corresponds with the name: 3,5-dimethoxybenzaldehyde



              Structure is attached.


                    It is quite simple. The parent compound is benzaldehyde which is a benzene containing CHO functional group.

Now, starting numbering from CHO put methoxy (-OCH₃) groups at position 3 and 5.

A 9.70-g piece of solid CO 2 is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 298 K. What is the pressure of the gas inside the balloon?a. 5.39 atmb. 2.37  102 atmc. 2.52 atmd. 0.186 atme. none of these



a. 5.39 atm


Pressure = ?

Volume = 1 L

Temperature = 298 K

Mass = 9.70g

The formular relating these variables is the ideal gas equation;

PV = nRT

where R = gas constant = 0.082057 L.atm.K-1.mol-1

n can be obtained from the formular below;

n = mass / molar mass = 9.70 / 44

n = 0.2205 mol

P = nRT / V

P = 0.2205 * 0.082057 * 298 / 1

P = 5.392 atm

The correct option is option A.