Answer:
### Why does a voltmeter not accurately read voltage?

### Why are there two probes on a voltmeter?

As voltages is a potential in relation to a reference, one probe must be on the reference or "zero" planes and the other must be on the point being **measured**.

because the voltmeter uses some of the main **circuit's **current. Main present in the circuit **diminishes **as a result, and the voltmeter's reading of the potential difference does not correspond to its true value.

Nothing is measured at a specific point by the voltmeter. It **gauges **the voltage (V) differential between two circuit locations. Thus, a **multimeter** has two leads rather than one.

To know more about **measured** visit:

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Calculate the volume of 8.87×10-2 M calcium hydroxide required to neutralize 15.0 mL of a 0.389 M hydrobromic acid solution. mL

What is the potentual energy of 7 kg object, 12 m off the ground?

Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)

A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number of significant figures, and show required steps used to reach your answer.

I need soon this is due at 10:30 pm its curently 6:00 pmWhat is parasitism?

What is the potentual energy of 7 kg object, 12 m off the ground?

Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)

A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number of significant figures, and show required steps used to reach your answer.

I need soon this is due at 10:30 pm its curently 6:00 pmWhat is parasitism?

The **weighted average **(*Avg*) for these **values **has been **5.35.**

The **weighted average **has been an **arithmetic calculation **of the **mean **value for the **percent abundance **of each value.

The **weighted average **(*Avg*) for the **values **has been given by:

The **values **have been given,

The **weighted average **has been given as:

For the **given **set of **values**, the **weighted average **(*Avg*) has been given as:

The **weighted average **(*Avg*) for these **values **has been **5.35.**

Learn more about **weighted average**, here:

**Answer:**

5.35

**Explanation:**

**Value 5.00 6.00 7.00**

**Weight 75.0% 15.0% 10.0 %**

We can determine the weighted average of these values using the following expression.

**Weighted average = ∑ wi × xi**

where,

**w: relative weight**

**x: value**

Weighted average = 5.00 × 0.750 + 6.00 × 0.150 + 7.00 × 0.100

Weighted average = 5.35

**Answer:**

The number of protons in an atom is always equal to the atomic number.

**Explanation:**

**Answer:**

c. CH3CH2CH(CH3)CHO

**Explanation:**

Hello there!

In this case, according to the process for the one-step oxidation of a primary alcohol with a moderately strong oxidizing agent like pyridinium chlorochromate (PCC), whereby an aldehyde is produced, we infer that the corresponding product will be 2-methylbutanal, which matches with the choice c. CH3CH2CH(CH3)CHO according to the following reaction:

Regards!

**Answer:**

When the graduation line denotes the volume contained in the calibrated vessel, the ware is marked “TC”. When the graduation line indicates the volume delivered from the vessel, the ware is marked “TD”.

The **dependence **of the power of the **reaction **rate on the **concentration **is called the order of the reaction. The **order **of the reaction is the **first order**.

The **initial rate **method is the **estimation **of the order of the **reaction **by the initial rates of the **reactants **and products and by performing the **reaction **several times by measuring the rate.

The **reaction **is given as,

The **rate **of **reaction **can be given as:

Here the **variables **x, y and z are **orders** respective to the **reactant concentration **and **k** is the rate constant.

__Value of x with respect to A__:

__Value of y with respect to B__:

__Value of z with respect to C__:

**Substituting **value of **x = 1 **and **y = 2 **in the above **equation**:

Therefore** option b**. with respect to** C = 1,** the order of the reaction is **first-order**.

Learn more about the** order of reaction** here:

**Answer:**

B. First order, Order with respect to C = 1

**Explanation:**

The given kinetic data is as follows:

A + B + C → Products

[A]₀ [B]₀ [C]₀ Initial Rate (10⁻³ M/s)

1. 0.4 0.4 0.2 160

2. 0.2 0.4 0.4 80

3. 0.6 0.1 0.2 15

4. 0.2 0.1 0.2 5

5. 0.2 0.2 0.4 20

**The rate of the above reaction is given as:**

where **x, y and z are the order with respect to A, B and C respectively.**

k = rate constant

[A], [B], [C] are the concentrations

**In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.**

**Order w.r.t A** : **Use trials 3 and 4**

**Order w.r.t B** : **Use trials 2 and 5**

**Order w.r.t C** : **Use trials 1 and 2**

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

z = 1

Therefore, order w.r.t C = 1

**Answer: The empirical formula of compound is .**

**Explanation:**

Mass of Sample= 0.702 g

Mass of = 1.4 g

Mass of = 0.86 g

Mass of = 0.478 g

First we have to calculate moles of, and formed.

1. Moles of

Now , Moles of carbon == Moles of = 0.032

2. Moles of =0.048mol

Now , Moles of hydrogen = Moles of =

3. Moles of mol

Now , Moles of silicon = Moles of = 0.008 moles

Therefore, the ratio of number of moles of C : H : Si is = 0.032 : 0.096 : 0.008

For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C=

For H =

For Si=

Thus, C: H: Si = 4 : 12 : 1

The simplest ratio represent empirical formula.

Hence, the empirical formula of compound is .