Answer:

**Answer:**

F = M2 ω^2 R centripetal force of sun on planet

ω = (F / (M2 R))^1/2 = 2 pi f = 2 pi / P where P is the period

P = 2 pi (M2 * R / F)^1/2

F = G M1 M2 / R^2 gravitational force on planet

P = 2 pi {R^3 / (G M1)]^1/2

P = 6.28 [(2.0E11)^3 / (6.67E-11 * 3.0E30)]^1/2

P = 6.28 (8 / 20)^1/2 E7 = 3.9E7 sec

1 yr = 3600 * 24 * 365 = 3.15E7 sec

P = 3.9 / 3.2 = 1.2 years

Which of the following is not a risk associated with using legal drugs without medical supervision

A 50 kg woman and an 80 kg man stand 12.0 m apart on frictionless ice.(a) How far from the woman is their CM?m(b) If each holds one end of a rope, and the man pulls on the rope so that he moves 1.3 m, how far from the woman will he be now?m(c) How far will the man have moved when he collides with the woman?m

Two cylinders with the same mass density rhoC = 713 kg / m3 are floating in a container of water (with mass density rhoW = 1025 kg / m3). Cylinder #1 has a length of L1 = 20 cm and radius r1 = 5 cm. Cylinder #2 has a length of L2 = 10 cm and radius r2 = 10 cm. If h1 and h2 are the heights that these cylinders stick out above the water, what is the ratio of the height of Cylinder #2 above the water to the height of Cylinder #1 above the water (h2 / h1)? h2 / h1 =

For a certain optical medium the speed of light varies from a low value of 1.80 × 10 8 m/s for violet light to a high value of 1.92 × 10 8 m/s for red light. Calculate the range of the index of refraction n of the material for visible light.

Two charged particles are separated by 10 cm. suppose the charge on each particle is doubled. By what factor does the electric force between the particles change?

A 50 kg woman and an 80 kg man stand 12.0 m apart on frictionless ice.(a) How far from the woman is their CM?m(b) If each holds one end of a rope, and the man pulls on the rope so that he moves 1.3 m, how far from the woman will he be now?m(c) How far will the man have moved when he collides with the woman?m

Two cylinders with the same mass density rhoC = 713 kg / m3 are floating in a container of water (with mass density rhoW = 1025 kg / m3). Cylinder #1 has a length of L1 = 20 cm and radius r1 = 5 cm. Cylinder #2 has a length of L2 = 10 cm and radius r2 = 10 cm. If h1 and h2 are the heights that these cylinders stick out above the water, what is the ratio of the height of Cylinder #2 above the water to the height of Cylinder #1 above the water (h2 / h1)? h2 / h1 =

For a certain optical medium the speed of light varies from a low value of 1.80 × 10 8 m/s for violet light to a high value of 1.92 × 10 8 m/s for red light. Calculate the range of the index of refraction n of the material for visible light.

Two charged particles are separated by 10 cm. suppose the charge on each particle is doubled. By what factor does the electric force between the particles change?

**Answer:**

when u learn something new it goes to ur short term memory

**Answer:**

its 45 over 6

**Explanation:the answer is in the question**

**Answer: Only the melted cube's shape changed.**

**Explanation:**

**Answer:**

a) TB = m2 * w^2 * 2*d

b) TA = m1 * w^2 * d + m2 * w^2 * 2*d

**Explanation:**

The tension on the strings will be equal to the centripetal force acting on the boxes.

The centripetal force is related to the centripetal acceleration:

f = m * a

The centripetal acceleration is related to the radius of rotation and the tangential speed:

a = v^2 / d

f = m * v^2 / d

The tangential speed is:

v = w * d

Then

f = m * w^2 * d

For the string connecting boxes 1 and 2:

TB = m2 * w^2 * 2*d

For the string connecting box 1 to the shaft

TA = m1 * w^2 * d + m2 * w^2 * 2*d

To find the time rate of change of **electric flux** between the plates of the capacitor, use the formula \(\frac{d\phi_E}{dt} = \frac{I}{A_\text{plate}}\). The displacement current between the plates can be found using the formula \(I_d = \varepsilon_0 \kappa \frac{d\phi_E}{dt}\).

To find the time rate of change of electric flux between the plates of the** capacitor,** we can use the formula: \(\frac{d\phi_E}{dt} = \frac{I}{A_\text{plate}}\), where \(\frac{d\phi_E}{dt}\) is the time rate of change of electric flux, \(I\) is the current, and \(A_\text{plate}\) is the area of one plate. In this case, the area of each plate is \((0.06 \,\text{m})^2\) and the current is 0.134 A. Thus, the time rate of change of electric flux is \(\frac{0.134 \,\text{A}}{(0.06 \,\text{m})^2}\) V·m/s.

The displacement current between the plates of a capacitor can be found using the formula: \(I_d = \varepsilon_0 \kappa \frac{d\phi_E}{dt}\), where \(I_d\) is the displacement current, \(\varepsilon_0\) is the vacuum permittivity, \(\kappa\) is the **dielectric constant,** and \(\frac{d\phi_E}{dt}\) is the time rate of change of electric flux. In this case, \(\varepsilon_0\) is a constant, \(\kappa\) depends on the material between the plates (not provided), and we found \(\frac{d\phi_E}{dt}\) to be \(\frac{0.134 \,\text{A}}{(0.06 \,\text{m})^2}\) V·m/s. So the displacement current can be calculated once these values are known.

#SPJ12

The time rate of change of **electric flux** can be found using I/ε₀A. The displacement current can be found using ε₀A(dE/dt)

The time rate of change of electric flux between the plates of the capacitor can be found using the formula:

dΦ/dt = I/ε₀A

Where dΦ/dt is the time rate of change of electric flux, I is the **current**, ε₀ is the permittivity of free space, and A is the area of one of the plates.

We are given that the current is 0.134 A and the area of each plate is (0.060 m)² = 0.0036 m². Plugging these values into the equation, we get: the time rate of change of electric flux between the plates is 37.22 V·m/s.

Similarly, the displacement current between the plates can be found using the formula:

Id = ε₀A(dE/dt)

Where Id is the displacement current, ε₀ is the permittivity of free space, A is the area of one of the plates, and dE/dt is the time rate of change of electric field intensity between the plates.

We are given that ε₀ is 8.854 × 10⁻¹² F/m and dΦ E/ dt is 37.22 V·m/s. Plugging these values into the equation, we get:

Id = (8.854 × 10⁻¹² F/m)(37.22 V·m/s) = 3.29 × 10⁻¹⁰ A

Therefore, the displacement current between the plates is 3.29 × 10⁻¹⁰ A.

#SPJ12

**Answer:**

Work done will be equal to 3186.396 J

**Explanation: **

We have mass m = 76.2 kg

Initial velocity u = 5 m/sec

Final velocity v = 10.4 m/sec

We have to find the work done

From work energy theorem work done is equal to change in kinetic energy

w = 3168.396 J

So work done will be equal to 3186.396 J

I assume the graph is looking like in the picture bellow.

North component:

cos(41.5) * 835 = 625.37 km/h

West component of speed:

sin(41.5) * 835 = 553.29 km/h

After 2.2 hours plane will fly:

2.2*625.37 = 1375.81 km north

2.2*553.29 = 1217.23 km west

North component:

cos(41.5) * 835 = 625.37 km/h

West component of speed:

sin(41.5) * 835 = 553.29 km/h

After 2.2 hours plane will fly:

2.2*625.37 = 1375.81 km north

2.2*553.29 = 1217.23 km west

To find the components of the velocity vector, you can use **trigonometry**. The north component is calculated using the sine function and the west component is calculated using the cosine function. After 2.20 hours, the distance traveled north and west can be found by multiplying the velocity components by the time.

To find the components of the velocity vector in the northerly and westerly directions, we can use trigonometry. The velocity vector is 835 km/h and is traveling in a direction 41.5° west of north. To find the north component, we can use the sine function: **North component = velocity * sin(angle)**. To find the west component, we can use the cosine function: **West component = velocity * cos(angle)**.

After 2.20 hours, we can find the distance traveled north and west by multiplying the velocity components by the time: **Distance north = North component * time** and **Distance west = West component * time**.

Let's calculate the values:

- North component = 835 km/h * sin(41.5°)
- West component = 835 km/h * cos(41.5°)
- Distance north = North component * 2.20 h
- Distance west = West component * 2.20 h

#SPJ3