Select the correct answer. Martin runs 100 meters in 15 seconds. What is the equation for d, the distance in meters that Martin covers per second? O A. 15+ d = 100 B. 100 + d = 15 O c. dx 15 = 100 D. d x 100 = 15​

Answers

Answer 1
Answer:

Answer:

C) d*15=100

Step-by-step explanation:

The word problem already gives us the product or the end result “Martin runs 100 meters in 15 seconds. So the 100 has to be equal to the expression.

=100

Per second” this suggests that we should multiply

the most logical answer is d*15=100 or dx15=100


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Find the slope (m) and the y-intercept (b) of the given line on the graph. pls show work/explanation!

Answers

Answer:

m= 1/2

b= (0,6)

Step-by-step explanation:

Slope is rise over run

The y intercept is when x=o or just look at the vertical line

What is the rule for the reflection?A) r y=x (y,x) -> (-y,-x)
B) r y=-x (x,y) -> (-y,-x)
C) r y=x (x,y) -> (y,x)
D) r y=-x (x,y) -> (y,x)

Answers

the rule for the reflection is (B)

Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from the left, or neither. f(x) = x + 4 if x < 0 ex if 0 ≤ x ≤ 1 8 − x if x > 1 x = (smaller value) continuous from the right continuous from the left neither

Answers

Using continuity concepts, it is found that the function is left-continuous at x = 1.

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A function f(x) is said to be continuous at x = a if:

\lim_(x \rightarrow a^(-)) f(x) = \lim_(x \rightarrow a^(+)) f(x) = f(a)

  • If only \lim_(x \rightarrow a^(-)) f(x) = f(a), the function is left-continuous.
  • If only \lim_(x \rightarrow a^(+)) f(x) = f(a), the function is right-continuous.

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The piece-wise definition of the function f(x) is:

x + 4, x < 0

x, 0 \leq x \leq 1

8 - x, x > 1

We have to check the continuity at the points in which the definitions change, that is, x = 0 and x = 1.

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At x = 0:

  • The definition at 0 is f(0) = 0
  • Approaching x = 0 from the left, we have values less than 0, thus:

\lim_(x \rightarrow 0^(-)) f(x) = \lim_(x \rightarrow 0) x + 4 = 0 + 4 = 0

  • Approaching x = 0 from the right, we have values greater than 0, thus:

\lim_(x \rightarrow 0^(+)) f(x) = \lim_(x \rightarrow 0) x = 0

Since the limits are equal, and also equal to the definition at the point, the function is continuous at x = 0.

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At x = 1:

  • The definition at 1 is f(1) = 1
  • Approaching x = 1 from the left, we have values less than 1, thus:

\lim_(x \rightarrow 1^(-)) f(x) = \lim_(x \rightarrow 1) x = 1

  • Approaching x = 1 from the right, we have values greater than 1, thus:

\lim_(x \rightarrow 1^(+)) f(x) = \lim_(x \rightarrow 1) 8 - x = 8 - 1 = 7

To the right, the limit is different, thus, the function is only left continuous at x = 1.

A similar problem is given at brainly.com/question/21447009

Answer:

the function is continuous from the left at x=1 and continuous from the right at x=0

Step-by-step explanation:

a function is continuous from the right , when

when x→a⁺ lim f(x)=f(a)

and from the left when

when x→a⁻ lim f(x)=f(a)

then since the functions presented are continuous , we have to look for discontinuities only when the functions change

for x=0

when x→0⁺ lim f(x)=lim  e^x = e^0 = 1

when x→0⁻ lim f(x)=lim  (x+4) = (0+4) = 4

then since f(0) = e^0=1 , the function is continuous from the right at x=0

for x=1

when x→1⁺ lim f(x)=lim  (8-x) = (8-0) = 8

when x→1⁻ lim f(x)=lim e^x = e^1 = e

then since f(1) = e^1=e , the function is continuous from the left at x=1

The shape of the distribution of the time required to get an oil change at a 15-minute oil-change facility is unknown. However, records indicate that the mean time is 16.2 minutes, and the standard deviation is 3.4 minutes.Requried:
a. What is the probabilty that a random sample of n = 40 oil changes results in a sample mean time less than 15 minutes?
b. Suppose the manager agrees to pay each employee a​ $50 bonus if they meet a certain goal. On a typical​ Saturday, the​ oil-change facility will perform 40 oil changes between 10 A.M. and 12 P.M. Treating this as a random​ sample, there
would be a​ 10% chance of the mean​ oil-change time being at or below what​ value? This will be the goal established by the manager.

Answers

Answer:

(a) Probability that a random sample of n = 45 oil changes results in a sample mean time < 10 ​minutes i=0.0001.

(b) The mean oil-change time is 15.55 minutes.

Step-by-step explanation:

Let us denote the sample mean time as x

From the Then x = mean time = 16.2 minutes

  The given standard deviation = 3.4 minutes

The value of  n sample size = 45

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Which is NOT a multiple of 15?

Answers

Answer:

2, 4, 6, 7, 8, 9, 10, 11, 12, 13, 14, 16 and anything else after 16

Step-by-step explanation:

I can’t see any answer choices so the multiples of 15 are: 15,30,45,60,75,90,105,120,135,150,165,180,195,210,225,240,255,270,285,300,315,330,345,360,375,390,405,420,435,450,465,480,495,510,525,540,555,570,585,600,615,630,645,660,675,690,705,720,735
So I guess anything but those numbers, hope this helps

Suppose that X is a random variable with probability function x 0 1 2 3 4 5 P(x) 0.00032 0.0064 0.0512 0.2048 0.4096 0.32768 and that the random variable Y = 9X2 − 36X + 4. (a) What is the range of Y ? (b) Calculate P{Y = 4}. (c) Calculate P{Y = 0}.

Answers

(a) For each value of X we have:

X=0\quad\Rightarrow\quad Y=4\n\nX=1\quad\Rightarrow\quad Y=-23\n\nX=2\quad\Rightarrow\quad Y=-32\n\nX=3\quad\Rightarrow\quad Y=-23\n\nX=4\quad\Rightarrow\quad Y=4\n\nX=5\quad\Rightarrow\quad Y=49

so the range of Y = {-32, -23, 4, 49}

(b)

P\{Y=4\}=P\{X=0\}+P\{X=4\}=0.00032+0.4096=\boxed{0.40992}

(c)

Y cannot equal 0, so

P\{Y=0\}=0