Answer:

**Answer:**

4 m/s^2

**Explanation:**

(0.5m/s * 4)+2 m/s

A reducing elbow in a horizontal pipe is used to deflect water flow by an angle θ = 45° from the flow direction while accelerating it. The elbow discharges water into the atmosphere. The cross- sectional area of the elbow is 150 cm2 at the inlet and 25 cm2 at the exit. The elevation difference between the centers of the exit and the inlet is 40 cm. The mass of the elbow and the water in it is 50 kg. Determine the anchoring force needed to hold the elbow in place. Take the momentum flux correction factor to be 1.03 at both the inlet and outlet.

If the_____of a wave increases, its frequency must decrease.a. period b. energy c. amplitude d. velocity

A certain lightning bolt moves 50.0 c of charge. how many fundamental units of charge (qe) is this?

Kathy tests her new sports car by racing with Stan, an experienced racer. Both start from rest, but Kathy leaves the starting line 1.00 s after Stan does. Stan moves with a constant acceleration of 3.1 m/s2 while Kathy maintains an acceleration of 4.99 m/s. 2 (a) Find the time at which Kathy overtakes Stan. s from the time Kathy started driving (b) Find the distance she travels before she catches him (c) Find the speeds of both cars at the instant she overtakes him. Kathy m/s Stan m/s

A rocket is attached to a toy car that is confined to move in the x-direction ONLY. At time to = 0 s, the car is not moving but the rocket is lit, so the toy car accelerates in the +x-direction at 5.35 m/s2. At t; = 3.60 s, the rocket's fuel is used up, and the toy car begins to slow down at a rate of 1.95 m/s2 because of friction. A very particular physics professor wants the average velocity for the entire trip of the toy car to be +6.50 m/s. In order to make this happen, the physics professor plans to push the car (immediately after it comes to rest by friction) with a constant velocity for 4.50 sec. What displacement must the physics professor give the car (immediately after it comes to rest by friction) in order for its average velocity to be +6.50 m/s for its entire trip (measured from the time the rocket is lit to the time the physics professor stops pushing the car)?

If the_____of a wave increases, its frequency must decrease.a. period b. energy c. amplitude d. velocity

A certain lightning bolt moves 50.0 c of charge. how many fundamental units of charge (qe) is this?

Kathy tests her new sports car by racing with Stan, an experienced racer. Both start from rest, but Kathy leaves the starting line 1.00 s after Stan does. Stan moves with a constant acceleration of 3.1 m/s2 while Kathy maintains an acceleration of 4.99 m/s. 2 (a) Find the time at which Kathy overtakes Stan. s from the time Kathy started driving (b) Find the distance she travels before she catches him (c) Find the speeds of both cars at the instant she overtakes him. Kathy m/s Stan m/s

A rocket is attached to a toy car that is confined to move in the x-direction ONLY. At time to = 0 s, the car is not moving but the rocket is lit, so the toy car accelerates in the +x-direction at 5.35 m/s2. At t; = 3.60 s, the rocket's fuel is used up, and the toy car begins to slow down at a rate of 1.95 m/s2 because of friction. A very particular physics professor wants the average velocity for the entire trip of the toy car to be +6.50 m/s. In order to make this happen, the physics professor plans to push the car (immediately after it comes to rest by friction) with a constant velocity for 4.50 sec. What displacement must the physics professor give the car (immediately after it comes to rest by friction) in order for its average velocity to be +6.50 m/s for its entire trip (measured from the time the rocket is lit to the time the physics professor stops pushing the car)?

**Answer:**

3.6 × 10¹² nanoseconds

**Explanation:**

Hour is the unit of time. Seconds is the SI unit of time.

Hour and seconds are related as:

1 hour = 60 minutes

1 minute = 60 seconds

So,

1 hour = 60 ×60 seconds = 3600 seconds

Thus,

3600 seconds are in one hour

Also,

1 sec = 10⁹ nanoseconds

Thus,

3600 sec = 3600 × 10⁹ nanoseconds = 3.6 × 10¹² nanoseconds

Thus,

**3.6 × 10¹² nanoseconds are in one hour.**

a). The** magnitude **along with the** direction** of the electric field releasing **westward force** of × N would be:

× N/C is **Eastward** Direction

b). The **magnitude **along with the** force of the direction** that this field releases on** proton** would be:

× in **Eastward** Direction

a). **Given** that,

Force × N

As we know,

**Force** Charge × Electric Field

So,

**∵ Electric Field**

× ) ×

×

The direction of the field would be opposite i.e. **Eastward direction** due to the field carrying a **-ve charge.**

b). The **magnitude** carried by the **force** working on the **proton **would be the same with an opposite direction due to **+ve charge.**

**∵ Force** × N in **Eastward direction.**

Learn more about "**Magnitude**" here:

**Explanation:**

(a) E = F/q

E = 4.8×10^-17/1.6×10^-19

E = 300 N/C

(b) same magnitude of electric field is exerted on proton

To solve this problem we need to use the emf equation, that is,

Where E is the induced emf

I the current in the first coil

M the mutual inductance

Solving for a)

Solving for b) we need the FLux through each turn, that is

Where N is the number of turns in the second coil

Answer:

Option C. 4 Hz

Explanation:

To know the correct answer to the question given above, it is important we know the definition of frequency.

Frequency can simply be defined as the number of complete oscillations or circles made in one second.

Considering the diagram given above, the wave passes through the medium over a period of one second.

Thus, we can obtain the frequency by simply counting the numbers of complete circles made during the period.

From the diagram given above,

The number of circles = 4

Thus,

The frequency is 4 Hz

**Answer:**

The S wave arrives 6 sec after the P wave.

**Explanation:**

Given that,

Distance of P = 45 km

Speed of p = 5000 m/s

Speed of S = 3000 m/s

**We need to calculate the time by the P wave**

**Using formula of time **

Where, D = distance

v = speed

t = time

Put the value in to the formula

Now, time for s wave

The required time is

**Hence, The S wave arrives 6 sec after the P wave.**

A.0.41 sec

B.41 sec

C.4.1 sec

D.4 sec

A **horizontal **baseball pitch is **launched **at 44 m/s. The ball will stay for 4.1 sec (approx) in the air. Hence, option C is correct.

The rate at which an object's **position **changes when observed from a specific point of view and when measured against a **specific **unit of time is known as its **velocity**.

Its** SI unit** is represented as** m/s**, and it is a **vector **quantity, it means that it has both magnitude and direction.

According to the question, the given values are :

Initial **Velocity**, u = 44 m/s,

Distance travelled, s = 18 m and,

Final velocity, v = 0.

Use **equation **of motion :

v = u + at

0 = 44 + (-9.8)t

t = 44 / 9.8

t = 4.3 (approx)

Hence, the time for which the ball stay in the air is 4.1 sec (approx).

To get more information about **velocity **:

#SPJ2

**Answer:**

a 0.41

plug number into equation