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PLZ HELP I NEED IT ASAP - 1

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Answer 1
Answer:

Answer:

c the hatching of eggs by birds

Explanation:

it is using the same way as the heating


Related Questions

A small family farm has 230 acres of farmland to grow corn . If each acre yields 63 bushels of corn and each bushel can be sold at $9.00, how much does the farm make corn per year?
Which of the following is a fomite?a. a prairie dog infested with fleas infected with the plaue bacteriumb. a river contaminated with the Giardia protozoanc. a doorknob contaminated with the cold virusd. an asymptomatic person infected with HIVe. a mosquito infected with the malaria protozoan
What is one disadvantage of insect stridulation
consider a molecule of the polymer, polyethylene, and a protein molecule as if they were strings of beads. How would the string representing polyethylene differ from that representing a protein
What is an exmaple of a chemical reaction?

From the laboratory exercise, match the plant group to the plant examined. [8 pt] Miniature Parlor Palm Coleus Blue Rabbit’s Foot Fern Geranium Foxtail Fern Tree Fern Boston Fern Spider Plant A. angiosperm (monocot) B. angiosperm (monocot) C. pterophyte (fern) D. angiosperm (eudicot) E. angiosperm (eudicot) F. pterophyte (fern) G. angiosperm (monocot) H. angiosperm (monocot)

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Answer:

Miniature parlor palm- Angiosperm monocot

Coleus- Angiosperm eudicot

Blue rabbit's foot fern- pterophyte

Geranium- Angiosperm eudicot

Foxtail fern- Angiosperm monocot

Tree fern- Angiosperm monocot

Boston fern- pterophyte

Spider plant- Angiosperm monocot

Which statements compare meiosis I and meiosis II? Check all that apply.-The parent cell in meiosis I is diploid and has 2n chromosomes.
-Meiosis I produces two gametes that have exactly the same genetic make up.
-Meiosis II creates four daughter cells that are genetically different from one another.
-After meiosis I, two daughter cells with haploid number of sister chromatids are produced.
-Four gametes with haploid number of chromosomes and single chromatids result after meiosis II.

Answers

Answer:

after meiosis I two daughter cells with haploid number of sister chromatids are produced.

the parent cell in meiosis I is diploid and has 2n chromosomes.

four gametes with haploid number of chromosomes and single chromatids result after meiosis II.

Explanation:

Answer:

Meiosis II creates four daughter cells that are genetically different from one another.

After meiosis I, two daughter cells with haploid number of sister chromatids are produced.

Four gametes with haploid number of chromosomes and single chromatids result after meiosis II.

Explanation:

The pyruvate dehydrogenase complex converts pyruvate to acetyl coenzyme A, abbreviated acetyl CoA, which can then enter metabolic pathways such as the citric acid cycle. Identify the citric acid cycle enzyme that is mechanistically and structurally similar to the pyruvate dehydrogenase complex. Which enzyme or enzyme complex is similar to the pyruvate dehydrogenase complex? isocitrate dehydrogenase fumarase glyceraldehyde 3‑phosphate dehydrogenase α‑ketoglutarate dehydrogenase

Answers

Answer:

α‑ketoglutarate dehydrogenase

Explanation:

This is an enzyme complex ,which is analogous to pyruvate dehydrogenase. . Its catalytic activity is inhibited by it products succinyl Co A,it is also refers to as oxoglutarate dehydrogenase complex.(OGDC).

This enzyme complex  is similar to pyruvate dehydrogenase in  having  the same subunit structure, and using  the same type of co-enzyme.    

Trans fat:a. is found naturally in some animal products
b. has an established daily value that can be followed in a daily menu
c. does not appear to be linked to the development of chronic disease such as diabetes and coronary artery disease
d. a and b
e. none of the above

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I think it's A and B??????? I'm not sure

Based on your knowledge of ocean chemistry, predict the feeding mode and size of organisms found in the deep layers of the ocean, and select the best explanation.

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In the deep layers of the ocean, various distinct kinds of species are found like fangtooth fish and vampire squid, to sea urchins and coffinfish.  

One of the probable adaptation, which is not fully understood in the deep sea is gigantism. This refers to the ability of animals to become highly enormous in size. A well-known illustration is a giant squid, and others, like giant isopod, the kings of herrings selfish, and the colossal squid.  

One of the possible reason of gigantism is the tendency of the species in the deep sea to live for long years, that is, for decades or for even centuries. As food is not abundant in the deep zones, thus deep sea creatures have evolved some interesting mechanisms of feeding.  

In the non-existence of photosynthesis, the majority of food comprises of detritus, that is, the decaying leftovers of algae, microbes, animals, and plants from the upper layers of the ocean. Apart from that, the corpses of large animals, like whales that sink to the bottom give irregular but huge feasts for deep-sea animals.  


How many hydrogen bonds will be involved in base pairing in a DNA molecule of 50 base pairs that contains 15 cytosine bases

Answers

Answer:

The number of hydrogen bonds involved will be 39

Explanation:

There are 4 types of bases that exist in a DNA, which are adenine, thymine, guanine and cytosine. Double stranded DNA molecules have these bases attaching specifically to one another; adenine only binds to thymine and vice versa while guanine only binds to cytosine and vice versa. These two bases bonding together are referred to as base pairs and the type of bond here is the hydrogen bond. There are double bonds between the adenine and thymine base pair while there are triple bonds between the guanine and cytosine base pairs.

Thus, when there are 13 cytosine bases in a DNA molecule, the number of hydrogen bonds present in the resulting base pairs will be 13 × 3 (because cytosine binds with a triple bond to guanine).

13 × 3 = 39

The number of hydrogen bonds involved will be 39

Final answer:

So, in a DNA molecule of 50 base pairs that contains 15 cytosine (C) bases, there would be a total of 115 hydrogen bonds involved in base pairing.

Explanation:

In DNA, base pairing occurs between complementary nitrogenous bases. Adenine (A) pairs with thymine (T), and cytosine (C) pairs with guanine (G). Each base pair is connected by hydrogen bonds.

In a DNA molecule of 50 base pairs with 15 cytosine (C) bases, you can determine the number of hydrogen bonds involved in base pairing as follows:

1. Each adenine (A) pairs with thymine (T) and forms two hydrogen bonds.

2. Each cytosine (C) pairs with guanine (G) and forms three hydrogen bonds.

So, for the 15 cytosine (C) bases, you would have 15 pairs of C-G base pairs, and for the remaining 35 bases, you would have 35 pairs of A-T base pairs.

Total hydrogen bonds involved in base pairing:

(15 pairs of C-G base pairs * 3 hydrogen bonds per pair) + (35 pairs of A-T base pairs * 2 hydrogen bonds per pair)

= (15 * 3) + (35 * 2)

= 45 + 70

= 115 hydrogen bonds.

So, in a DNA molecule of 50 base pairs that contains 15 cytosine (C) bases, there would be a total of 115 hydrogen bonds involved in base pairing.

Learn more about Hydrogen bonds in DNA base pairing here:

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