Find the value of x. Round to the nearest tenth.
Find the value of x. Round to the nearest tenth. - 1

Answers

Answer 1
Answer: 36
i think. hope it helped sorrh if it’s wrong i’m not good at math

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A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven infants is randomly selected, and their weights at birth are recorded as:
9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds.
If Alpha = 0.05,
1. What is the critical t-value?
2. What is the decision for a statistically significant change in average weights at birth at the 5% level of significance?

Answers

Answer:

1. Critical value t=±2.447

2. The null hypothesis is failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the birth weight significantly differs from 6.6 lbs.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the birth weight significantly differs from 6.6 lbs.

Then, the null and alternative hypothesis are:

H_0: \mu=6.6\n\nH_a:\mu\neq 6.6

The significance level is 0.05.

The sample has a size n=7.

The sample mean is M=7.56.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1.18.

The estimated standard error of the mean is computed using the formula:

s_M=(s)/(√(n))=(1.18)/(√(7))=0.446

Then, we can calculate the t-statistic as:

t=(M-\mu)/(s/√(n))=(7.56-6.6)/(0.446)=(0.96)/(0.446)=2.152

The degrees of freedom for this sample size are:

df=n-1=7-1=6

For a two-tailed test with 5% level of significance and 6 degrees of freedom, the critical value for t is ±2.447.

As the test statistic t=2.152 is under 2.447 and over -2.447, it falls in the acceptance region, so the effect is not significant. The null hypothesis is failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the birth weight significantly differs from 6.6 lbs.

Sample mean and standard deviation calculations:

M=(1)/(n)\sum_(i=1)^n\,x_i\n\n\nM=(1)/(7)(9+7.3+6+. . .+6.6)\n\n\nM=(52.9)/(7)\n\n\nM=7.56\n\n\ns=\sqrt{(1)/(n-1)\sum_(i=1)^n\,(x_i-M)^2}\n\n\ns=\sqrt{(1)/(6)((9-7.56)^2+(7.3-7.56)^2+(6-7.56)^2+. . . +(6.6-7.56)^2)}\n\n\ns=\sqrt{(8.32)/(6)}\n\n\ns=√(1.39)=1.18\n\n\n

16. The original price of a tie is $12.50. The new price of the tie is now$7.50. By what percentage was the tie marked down? *

Answers

The tie was marked down by 40%

A swester is 20 dollars and is on ssle for 12 dollars. What percentage off

Answers

12 dolars / 20 dolars

the percentage is

(20-12) / 20

= 8/20

= 40 %

A local animal rescue organization receives an average of 0.55 rescue calls per hour. Use the Poisson distribution to find the probability that during a randomly selected hour, the organization will receive fewer than two calls.A) 0.087B) 0.894
C) 0.317
D) 0.106

Answers

Answer:

B) 0.894

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A local animal rescue organization receives an average of 0.55 rescue calls per hour.

This means that \mu = 0.55

Probability that during a randomly selected hour, the organization will receive fewer than two calls.

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)

P(X = 0) = (e^(-0.55)*(0.55)^(0))/((0)!) = 0.577

P(X = 1) = (e^(-0.55)*(0.55)^(1))/((1)!) = 0.317

P(X < 2) = P(X = 0) + P(X = 1) = 0.577 + 0.317 = 0.894

Solve for x. x - 1
2 = 4

Answers

Answer:

x = 16

Step-by-step explanation:

x - 12 = 4

 + 12 = +12

x = 16

Answer:

16

Step-by-step explanation:

Cody hiked at an average speed of 1 mile per hour for 5 hours on Saturday. He hiked an average speed of 2 miles per hour for 3 hours on Sunday.Which explanation correctly tells how to calculate the total number of miles that Cody hiked in two days?

A.Step 1: Multiply 1 × 5.
Step 2: Multiply 2 × 3.
Step 3: Add the two products.

B.Step 1: Multiply 1 × 5.
Step 2: Multiply 2 × 3.
Step 3: Subtract the two products.


C.Step 1: Divide 1 ÷ 5.
Step 2: Divide 2 ÷ 3.
Step 3: Add the two quotients.

D.Step 1: Divide 1 ÷ 5.
Step 2: Divide 2 ÷ 3.
Step 3: Subtract the two quotients.

Answers

Answer:

  A. Step 1: Multiply 1 × 5.

  Step 2: Multiply 2 × 3.

  Step 3: Add the two products.

Step-by-step explanation:

The total number of miles hiked will be the sum of the numbers of miles hiked each day. Each day, the number of miles hiked can be computed by multiplying time by speed:

  distance = speed × time

So, the total number of miles hiked is ...

  total miles = miles on day 1 + miles on day 2 . . . . . (sum, not a difference—eliminates choice B)

  total miles = (speed on day 1)×(time on day 1) + (speed on day 2)×(time on day 2) . . . . . (sum of products—eliminates choices C and D)

Choice A correctly describes the computation.