# The location of Sonia's school and home are plotted on the coordinateplane shown. What are the coordinates (x, y) of her school?

Answer: The coordinates of the school is (8,2)

## Related Questions

The area of a trapezoid is given by the formula A=h/2(a+b) .

Solve the formula for b.

(2A)/h -a =b

Step-by-step explanation:

A= [h(a+b)]/2       I rewrote the formula, because h and a+b are in the numerator.

2A=h(a+b)  Multiply both sides of equation by 2

(2A)/h= a+b Divide both side by h

(2A)/h -a= b Subtract a from both sides

The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 cm, find its area.

width=25/3

Length=75/3

Step-by-step explanation:

Given

Perimeter=50

Let width=x

Length=4x

So perimeter =2(length+width)

2(length+width)=50

2(X+2x)=50

3x=25

X=25/3

So width=25/3

Length=75/3

) of basketball players has a bell shaped distribution with mean 72.5 inches and standard deviation 3.25 inches. A height of 79 inches is at what percentile?

75.5+3.25=75.75÷79of inches
You have to find the z score and that will tell you the percent tile. x - m / S = z, so z = 2

Find the diameter, radius, area and circumference of the circle. Show your work.

Step-by-step explanation:

Diameter:12ft

Area:

circumference:

8.) Out of 600 employees, only 270 are happy with their pay. What percent is this? (Please show your work.) *

For this case we can raise a rule of three:

600 employees -------------> 100%

270 employees -------------> x

Where the variable "x" represents the percentage of employees who are satisfied with their salary. So, we have:

Thus, 45% of employees are satisfied with their salary.

45%

EXPLANATION

The total number of employees is 600.

The number of employees who are happy with their pay is 270.

The percentage of employees who are happy with their pay is the number who are happy with their pay divided by total number of employees times 100%

This simplifies to

Consider the diagram and the proof below.Given: In △ABC, AD ⊥ BC
Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Triangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.

A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.

What is the missing statement in Step 6?

b = c

StartFraction h Over b EndFraction = StartFraction h Over c EndFraction
csin(B) = bsin(C)

bsin(B) = csin(C)