To completely neutralize a 0.325 g sample of pure aspirin, 15.50 mL of a sodium hydroxide solution is added. If 16.25 mL of the same sodium hydroxide solution must be added to an aspirin tablet sample during a titration to reach the endpoint, calculate the mass of aspirin in the tableA. 0.310 g
B. 0.288 g
C. 0.392 g
D. 0.450 g
E. 0.341 g

Answers

Answer 1
Answer:

Answer: The correct option is E.

Explanation: The reaction between aspirin (also known as acetylsalicylic acid) and sodium hydroxide is known as acid-base titration reaction.

By applying Unitary method, we get:

15.50mL of NaOH dissolves = 0.325 g of aspirin

So, 16.25 mL of NaOH will dissolve = (0.325g)/(15.5mL)* 16.25mL = 0.341 g

Hence, the correct option is E.


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Thus green house gases affects the solar energy.

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Answer:

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Answer:

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Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4 ( l ) metallic covalent ionic

Answers

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding  

Final answer:

Co(s) forms metallic bonds, CoCl2(s) forms ionic bonds, and CCl4(l) forms covalent bonds.

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The type of bonding within each substance can be identified by understanding the nature of the substances.

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  3. CCl4(l): CCl4 is a molecular compound composed of carbon and chlorine atoms, so it forms covalent bonds.

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