Answer:

**Answer:**

48 ft

**Step-by-step explanation:**

Choose the expression that completes the equation 33 / 3 + 10=_______1. 2(10+1)2. 10(1+1)3. 3(6+1)4 5(3+5)

I am relay struggling with this someone pls help

Drawing a 3 cards that are all 9 from a deck of cards

find the t values that form the boundaries of the critical region for a two-tailed test with a=.05 for n=6 n=12

Given regular pentagon ABCDE, what are the coordinates of vertex C?a) (b, c)b) (b, -c)c) (-b, c)d) (-b, -c)

I am relay struggling with this someone pls help

Drawing a 3 cards that are all 9 from a deck of cards

find the t values that form the boundaries of the critical region for a two-tailed test with a=.05 for n=6 n=12

Given regular pentagon ABCDE, what are the coordinates of vertex C?a) (b, c)b) (b, -c)c) (-b, c)d) (-b, -c)

4 ft

/60

HINT: Find the height using TRIGONOMETRY. Round to the nearest hundredth.

A =

feet squared

The **area **of the **parallelogram **is given by A = 17.32 feet²

Given data ,

Let the **area **of the **parallelogram **be represented as A

Now , the value of A is

Let the height of the parallelogram be h

where from the **trigonometric **relation , we get

sin 60° = h / 4

On simplifying , we get

h = 4 ( √3/2 )

h = 2√3 feet

Now , the area of **parallelogram **= base x height

A = 2√3 ( 5 ) feet²

A = 10√3 feet²

A = 17.32 feet²

Hence , the **parallelogram **has an area of A = 17.32 feet²

To learn more about **parallelogram **click :

#SPJ1

**Answer:**

may be incorrect but probably not -9

**Step-by-step explanation:**

19 - 28 = -9

The **peregrine **falcon flies in the time it takes the **eagle **to fly 40 miles is 64 miles away.

The **average **speed is the total **distance **traveled by the object in a particular **time interval**.

The **average speed **is a scalar quantity.

The **average **speed of a golden **eagle **is 30 mph and the average speed of a **peregrine falcon **is 48 mph.

The **time** to fly 40 **miles **(that time is x):

miles hours

30 ⇒ 1

40 ⇒ x

We use the ruleof three which is to **multiply **the cross **quantities **on the table and **divide **by the **remaining **quantity:

x = 40(1)/30

x = 4/3 hour

it takes the **eagle **4/3 **flies **to fly 40 miles.

Now we use the **velocity **of the **falcon**: 48mph, which can also be represented as:

miles hours

48 ⇒ 1

and we need the **distance **in miles that the **falcon **flies in 4/3 hours :

miles hours

48 ⇒ 1

x ⇒ 4/3

Again we use the rule of **three **(multiply cross **quantities **and divide by the **remaining****quantity**)

x = (48)× (4/3)

x = 64 miles

Hence, the **peregrine **falcon flies in the time it takes the **eagle **to fly 40 miles is 64 miles away.

Learn more about **average speed **here;

#SPJ2

**Answer:**

64

**Step-by-step explanation:**

64 miles

**Answer:**

f(5) = **35**

**Step-by-step explanation:**

In any function f(x), x is the input and f(x) is the output

__Example:__

f(x) = 2x + 3, find f(a)

That means we need to find value of f(x) at x = a, so substitute x by a

f(a) = 2(a) + 3 = 2a + 3

f(a) = 2a + 3

Let us use the same way to solve our question

∵ **f(x) = x² + 2x**

→ We need to find f(5), so substitute x by 5

∴ f(5) = (5)² + 2(5)

∴ f(5) = 25 + 10

→ Do addition

∴** f(5) = 35**

**Answer:**

**Step-by-step explanation:**

7630 x .023 = 175.49

175.49 + 28 = **$203.49**

We assume you mean

This is solved by writing 16 as a power of 4 and equating exponents.

2 = 3x - 7 . . . . . equate exponents

9 = 3x . . . . . add 7

3 = x . . . . . divide by 3

The solution is x = 3.

This is solved by writing 16 as a power of 4 and equating exponents.

2 = 3x - 7 . . . . . equate exponents

9 = 3x . . . . . add 7

3 = x . . . . . divide by 3

The solution is x = 3.