Answer the following questions about the last lesson below. What did we figure out about chain reactions? What did we figure out about fission? Fission produce more energy than a typical fuel sources, chain reaction


Answer 1


(Nothing)-But No answer

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Consider the titration of 25.0 mL of 0.340 M HCl with 0.160 M NaOH. What volume of NaOH is required to reach the equivalence point?
When an ionic compound such as sodium chloride (NaCl) is placed in water, the component atoms of the NaCl crystal dissociate into individual sodium ions (Na⁺) and chloride ions (Cl-). In contrast, the atoms of covalently bonded molecules (e.g. glucose, sucrose, glycerol) do not generally dissociate when placed in aqueous solution. Which of the following solutions would be expected to contain the greatest number of solute particles (molecules or ions)?A) 1 litre of 0.5 M NaClB) 1 litre of 1.0 M NaClC) 1 litre of 1.0 M glucoseD) 1 litre of 1.0 M NaCl and 1 litre of 1.0 M glucose will contain equal numbers of solute particles.

What is the isoelectric point of proteins?


Isoelectric point. The isoelectric point (pI, pH(I), IEP), is the pH at which a particular molecule carries no net electrical charge in the statistical mean. The standard nomenclature to represent the isoelectric point is pH(I), although pI is also commonly seen, and is used in this article for brevity.
The isoelectric point (pI, pH(I),IEP), is the pH at which a particular molecule carries no net electrical charge in the statistical mean.

Draw a well-labelled diagram showing how your body digests food​


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15.2 grams of CO2 = ? molecules of CO2



2.11 molecules of CO₂


Given data:

Mass of CO₂ = 15.2 g

Molecules of CO₂ = ?


Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 15.2 g/ 44 g/mol

Number of moles = 0.35 mol

Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

0.35 mol × 6.022 × 10²³ molecules / 1 mol

2.11 molecules of CO₂

Aqueous solutions of barium chloride and silver nitrate are mixed to form solid silver chloride and aqueous barium nitrate. The complete ionic equation contains which of the following species (when balanced in standard form)? A. NO (aq)
B. 2Ba (aq)
C. 2Ag (aq)
D. CI(aq)



Option C


Consider the ionic equation of this chemical equation. We are given barium chloride and silver nitrate as the reactants, and silver chloride and barium nitrate as the products. We can thus conclude that the ionic equation ( not balanced yet ) should be as follows -

Ba( 2 + ) + Cl ( - ) + Ag ( + ) + NO3 ( - ) ------> AgCl + Ba( 2 + ) + NO3( - )

As you can see these compounds are present in aqueous solutions, and are thus dissociated.


Now let us take a look at the number of elements on the reactant and product sides, and balance this chemical equation out -

Ba( 2 + ) + 2Cl ( - ) + 2Ag ( + ) + 2NO3 ( - ) ------> 2AgCl + Ba( 2 + ) + 2NO3( - )

Solution = Option C!

g What is the typical carbon concentration range for medium-carbon steels? 0.50 wt% - 0.75 wt% C 0.05 wt% - 1.00 wt% C 0.10 wt% - 0.50 wt% C 0.25 wt% - 0.60 wt% C 0.25 wt% - 1.00 wt% C



C 0.25 wt% - 0.60 wt%


The enthalpy of vaporization (ΔH°vap) of benzene is 30.7 kJ/mol at its normal boiling point of 353.3 K. What is ΔS°vap at this temperature? a. 383 J/(mol·K) b. 0.0115 J/(mol·K) c. 86.9 J/(mol·K) d. 0.087 J/(mol·K) e. 11.5 J/(mol·K)


Answer: The correct answer is Option c.


Vaporization is defined as the physical process in which liquid particles get converted to gaseous particles.

Liquid\rightleftharpoons Gas

The value of standard Gibbs free energy is 0 for equilibrium reactions.

To calculate \Delta S^o_(vap) for the reaction, we use the equation:

\Delta S^o_(vap)=(\Delta H^o_(vap))/(T)


\Delta S^o_(vap) = standard entropy change of vaporization

\Delta H^o_(vap) = standard enthalpy change of vaporization = 30.7 kJ/mol = 30700 J/mol    (Conversion factor: 1 kJ = 1000 J)

T = temperature of the reaction = 353.3 K

Putting values in above equation, we get:

\Delta S^o_(vap)=(30700J/mol)/(353.3K)=86.9J/(mol.K)

Hence, the correct answer is Option c.

Final answer:

The change in entropy (ΔS°vap) of benzene at its normal boiling point can be calculated using the enthalpy of vaporization (ΔH°vap) and the temperature (T). The ΔS°vap for benzene at 353.3 K is 0.087 J/(mol·K).


The enthalpy of vaporization (ΔH°vap) of a substance is related to the change in entropy (ΔS°vap) by the equation ΔS°vap = ΔH°vap / T, where T is the temperature in Kelvin. We are given that the enthalpy of vaporization of benzene at its normal boiling point (T = 353.3 K) is 30.7 kJ/mol. Plugging these values into the equation, we can calculate ΔS°vap to be 30.7 kJ/mol / 353.3 K = 0.087 J/(mol·K).

Learn more about Enthalpy of vaporization here: