B. Oceanic crust is made out of much less dense material than continental crust

C. Continental crust is continually renewed through convection in the earth's mantle

D. Continental crust eats oceanic crust for breakfast

Answer:

**Answer:**

A. Oceanic crust is continually recycled through convection in the earth's mantle

**Explanation:**

The oceanic plate is constantly being recycled through the forces of convection within the earth's mantle.

New oceanic plate are formed mid-oceanic ridge for example. As the magma cools and solidifies, they are moved away continually.

This is not the case for the continental curst.

What does a planet need in order to retain an atmosphere? How does an atmosphere affect the surface of a planet and the ability of life to exist?

A golf ball is dropped from rest from a height of 9.50 m. It hits the pavement, then bounces back up, rising just 9.70 m before falling back down again. A boy catches the ball on the way down when it is 1.20 m above the pavement. Ignoring air resistance calculate the total amount of time the ball is in the air, from drop to catch?

You are exiting a highway and need to slow down on the off-ramp in order to make the curve. It is rainy and the coefficient of static friction between your tires and the road is only 0.4. If the radius of the off-ramp curve is 36 m, then to what speed do you need to slow down the car in order to make the curve without sliding?

A conveyor belt is used to move sand from one place to another in a factory. The conveyor is tilted at an angle of 18° above the horizontal and the sand is moved without slipping at the rate of 2 m/s. The sand is collected in a big drum 5 m below the end of the conveyor belt. Determine the horizontal distance between the end of the conveyor belt and the middle of the collecting drum.

What is it called when a Rock forms due to heat and pressure in the earth?

A golf ball is dropped from rest from a height of 9.50 m. It hits the pavement, then bounces back up, rising just 9.70 m before falling back down again. A boy catches the ball on the way down when it is 1.20 m above the pavement. Ignoring air resistance calculate the total amount of time the ball is in the air, from drop to catch?

You are exiting a highway and need to slow down on the off-ramp in order to make the curve. It is rainy and the coefficient of static friction between your tires and the road is only 0.4. If the radius of the off-ramp curve is 36 m, then to what speed do you need to slow down the car in order to make the curve without sliding?

A conveyor belt is used to move sand from one place to another in a factory. The conveyor is tilted at an angle of 18° above the horizontal and the sand is moved without slipping at the rate of 2 m/s. The sand is collected in a big drum 5 m below the end of the conveyor belt. Determine the horizontal distance between the end of the conveyor belt and the middle of the collecting drum.

What is it called when a Rock forms due to heat and pressure in the earth?

**Answer:**

loyalty

**Explanation:**

**Answer:149.73 ml**

**Explanation:**

Given

change in volume is given by

The volume of the acetone when it cools to 20.0°C is approximately 142.39 mL.

In order to determine the volume of the acetone when it **cools to 20.0°C**, we can use the equation for the volume change caused by a temperature change at constant pressure, known as Charles's law. Charles's law states that the volume of a gas is directly proportional to its temperature in Kelvin. We can use the formula **V2 = V1 * (T2 / T1)** to calculate the volume of the acetone at the lower temperature.

Given that the initial volume of the acetone is 150 mL at a temperature of 34.5°C, we need to convert this temperature to Kelvin by adding 273.15. Therefore, **T1 = 34.5°C + 273.15 = 307.65 K**.

Since the final temperature is 20.0°C, the final temperature in Kelvin will be **T2 = 20.0°C + 273.15 = 293.15 K**. We can now plug these values into the equation to find the volume of the acetone at the lower temperature: **V2 = 150 mL * (293.15 K / 307.65 K) = 142.39 mL**.

#SPJ3

**Answer: **

The 1.5V battery can power the flashlight bulb drawing 0.60A for 83.33 minutes before it is depleted.

**Explanation:**

To determine how long a 1.5V battery can power a flashlight bulb drawing 0.60A, you can use the formula for calculating the energy (in joules) consumed by an electrical device over time:

Energy (Joules) = Power (Watts) × Time (Seconds)

In this case, the power (P) is given by the product of the voltage (V) and current (I):

Power (Watts) = Voltage (Volts) × Current (Amperes)

So, first, calculate the power consumption of the flashlight bulb:

Power (Watts) = 1.5V × 0.60A = 0.90 Watts

Now, you want to find out how long the battery can power the bulb, so rearrange the energy formula to solve for time:

Time (Seconds) = Energy (Joules) / Power (Watts)

Given that the battery stores 4.5 kJ (kilojoules), which is equivalent to 4,500 joules, and the power consumption is 0.90 watts:

Time (Seconds) = 4,500 J / 0.90 W = 5,000 seconds

Now, to express the time in more practical units, convert seconds to minutes:

Time (Minutes) = 5,000 seconds / 60 seconds/minute ≈ 83.33 minutes

So, the 1.5V battery can power the flashlight bulb drawing 0.60A for approximately 83.33 minutes before it is depleted.

Answer:

0.00124 V

Explanation:

Parameters given:

Initial circumference = 162 cm

Rate of decrease of circumference = 14 cm/s

Magnetic field, B = 0.5 T

Time, t = 8 secs

The magnitude of the EMF induced in the loop is given as:

V = (-NBA) / t

Where N = number of turns = 1

B = magnetic field

A = area of loop

t = time taken

First, we need to find the area of the loop.

To do this, we will find the radius after the loop circumference has decreased for 8 secs.

The rate of decrease of the circumference is 14 cm/s and 8 secs has passed, which means after 8 secs, it has decreased by:

14 * 8 = 112 cm

The new circumference is:

162 - 112 = 50 cm = 0.5 m

To get radius:

C = 2 * pi * r

r = C / (2 * pi)

r = 0.5 / (2 * 3.142)

r = 0.0796 m

The area is:

A = pi * r²

A = 3.142 * 0.0796²

A = 0.0199 m²

Therefore, the EMF induced is:

V = (-1 * 0.5 * 0.0199) / 8

V = -0.00124V

This is the EMF induced in the coil.

The magnitude is |-0.00124| V = 0.00124 V.

The **man **can **climb **, before the **ladders **starts to **slip**.

**A** - point at the **top **of the **ladder **

**B** - point at the **bottom **of the **ladder **

**C** - point where the man is **positioned **in the **ladder **

**L**- the **length **of the **ladder **

**α** - **angle **between ladder and ground

**x** - distance between C and B

The **forces **act on the **ladder**,

**Horizontal **reaction **force **(T) of the wall against the ladder

**Vertical **(upward) **reaction **force (R) of ground against the ladder.

**Frictional****horizontal **( to the left ) **force (F)**

**Vertical**( **downwards**) of the man,

mg = 75 Kg x 9.8 m/s² **= 735 N**

in **static conditions**,

∑Fx = T - F = 0 Since, T = F

∑Fy = mg - R = 0 Since, 735 - R = 0,** R = 735**

∑ Torques(b) = 0

In point B the **torque **produced by forces **R **and **F **is **Zero **

Then:

∑Torques(b) = 0

And the arm lever for each **force**,

**mg = 735**

Since, ∑Torques(b) = 0

Since,T = F

** F < μR ** the **ladder **will starts slipping over the ground

**μ(s) = 0.25 **

Therefore, the **man **can **climb **, before the **ladders **starts to **slip**. \

To know more about** Torque,**

**Answer:**

**x (max) = 0,25*L*tanα**

**Explanation:**

**Letá call **

**A: point at the top of the ladder**

**B: the point at the bottom of the ladder**

**C: point where the man is up the ladder**

**L the length of the ladder**

**α angle between ladder and ground**

** "x" distance between C and B**

**Description**

**The following forces act on the ladder**

**Point A: horizontal (to the right) reaction (T) of the wall against the ladder**

**Point B : Vertical (upwards) reaction (R) of ground against the ladder**

** frictional horizontal ( to the left ) force (F) **

**Point C : Weight (vertical downwards)) of the man mg **

**mg = 75 Kg * 9,8 m/s² mg = 735 [N]**

**Then in static conditions:**

**∑Fx = T - F = 0 ⇒ T = F**

**∑Fy = mg - R = 0 ⇒ 735 - R = 0 ⇒ R = 735**

**∑Torques(b) = 0**

**Note: In point B the torque produced by forces R and F are equal to 0**

**Then: **

**∑Torques(b) = 0 **

**And the arm lever for each force is:**

**mg = 735**

**d₁ for mg and d₂ for T**

**cos α = d₁/x then d₁ = x*cosα**

**sin α = d₂ / L then d₂ = L*sinα **

**Then:**

**∑Torques(b) = 0 ⇒ 735*x*cosα - T*L*sinα = 0**

**735*x*cosα = T*L*sinα**

**T = F then 735*x*cosα = F*L*sinα**

**F = (735)*x*cosα/L*sinα cos α / sinα = cotgα = 1/tanα**

**F = (735)*x*cotanα/L or F = (735)*x/L*tanα**

**When F < μ* R the ladder will stars slippering over the ground**

**μ(s) = 0,25 0,25*R = 735*x/L*tanα**

**x = 0,25*R*tanα*L/735**

**But R = mg = 735 then**

**0,25*L*tanα = x**

**Then x (max) = 0,25*L*tanα**

The **energy per second** received by an **eardrum** is

The area should be

Now

The power should be

Learn more about the **energy** here: brainly.com/question/14338287

**Answer:**

Power energy per second will be equal to

**Explanation:**

We have given radius of human eardrum r = 4.15 mm = 0.00415 m

Intensity at threshold of hearing

Area is given by

We know that power is given by

So power energy per second will be equal to