Answer:
c=15, (Check) 7(15)=105, 105-7=98; 6(15)=90, 90-8=82. 98+82=180

The expression below is a sum of cubes. 125x3 + 169

A company produces two products, A and B. The sales volume for A is at least 80% of the total sales of both A and B. However, the company cannot sell more than 110 units of A per day. Both products use one raw material, of which the maximum daily availability is 300 lb. The usage rates of the raw material are 2 lb per unit of A, and 4 lb per unit of B The profit units for A and B are $40 and $90, respectively. Determine the optimal product mix for the company

To keep pace with a growing population, approximately _______ jobs must be created each month. A. 100,000 B. 137,000 C. 1 million D. 185,000

Dilution ProblemSamantha needs 115 liters of a solution that has a concentration of 14 g/ml for the manufacture of computer parts. Samantha has an unlimited supply of a solution with a concentration of 21 g/ml.Using the Formula C1×V1 = C2×V2 to answer the following questionsRound answers to the nearest 10th.How many liters of 21 g/ml does Samantha need to equals the amount of soluble in the given solution?(Concentration times Volume = grams of soluble, like salt)

I Need help ASAP!!!

A company produces two products, A and B. The sales volume for A is at least 80% of the total sales of both A and B. However, the company cannot sell more than 110 units of A per day. Both products use one raw material, of which the maximum daily availability is 300 lb. The usage rates of the raw material are 2 lb per unit of A, and 4 lb per unit of B The profit units for A and B are $40 and $90, respectively. Determine the optimal product mix for the company

To keep pace with a growing population, approximately _______ jobs must be created each month. A. 100,000 B. 137,000 C. 1 million D. 185,000

Dilution ProblemSamantha needs 115 liters of a solution that has a concentration of 14 g/ml for the manufacture of computer parts. Samantha has an unlimited supply of a solution with a concentration of 21 g/ml.Using the Formula C1×V1 = C2×V2 to answer the following questionsRound answers to the nearest 10th.How many liters of 21 g/ml does Samantha need to equals the amount of soluble in the given solution?(Concentration times Volume = grams of soluble, like salt)

I Need help ASAP!!!

**Prime **factorization expresses an **integer **in terms of multiples of prime numbers. The **prime factorization** of 20 using exponents can be written as 2²×5¹.

**Factorization **is expressing a mathematical quantity in terms of multiples of smaller units of similar **quantities**.

Prime factorization is when all those factors are prime numbers.

Thus, **prime factorization **expresses an **integer **in terms of multiples of prime numbers.

The **prime **factorization of 20 using **exponents **can be written as,

20 = 1 × 2 × 2 × 5

= 2² × 5¹

Hence, the **prime factorization** of 20 using exponents can be written as 2²×5¹.

Learn more about** prime factorization **here:

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Here you go

2 to the second power times 5

2 to the second power times 5

The sides of the rectangle are aligned with the coordinate axes, so the dimensions of the rectangle are easily determined to be 4 -(-7) = 11 units by 1 -(-1) = 2 units. As with any rectangle, the area is the product of length and width.

The area is 11*2 = 22 square units.

The area is 11*2 = 22 square units.

Analyzing a sample of 14 flights at Denver International Airport, the probability of 10 or more flights arriving on time is 0.3783, and the probability of 11 or more flights arriving on time is 0.2142, which is not considered unusual.

(a) All 12 of the flights were on time.

(b) Exactly 10 of the flights were on time.

(c) 10 or more of the flights were on time.

(d) Would it be unusual for 11 or more of the flights to be on time?

We can use the binomial probability formula to solve this problem. The binomial probability formula is:

P(k successes in n trials) = (n choose k) * *

where:

n is the number of trials

k is the number of successes

p is the probability of success

q is the probability of failure

In this case, n = 14, p = 0.85, and q = 0.15.

(a) To find the probability that all 12 of the flights were on time, we can plug k = 12 into the binomial probability formula:

P(12 successes in 14 trials) = (14 choose 12) * *

Using a calculator, we can find that this probability is approximately 0.0032.

(b) To find the probability that exactly 10 of the flights were on time, we can plug k = 10 into the binomial probability formula:

P(10 successes in 14 trials) = (14 choose 10) * *

Using a calculator, we can find that this probability is approximately 0.1022.

(c) To find the probability that 10 or more of the flights were on time, we can add up the probabilities of 10, 11, 12, 13, and 14 successes:

P(10 or more successes) = P(10 successes) + P(11 successes) + P(12 successes) + P(13 successes) + P(14 successes)

Using a calculator, we can find that this probability is approximately 0.3783.

(d) To determine whether it would be unusual for 11 or more of the flights to be on time, we can find the probability of this event and compare it to a common threshold for unusualness, such as 0.05.

P(11 or more successes) = P(11 successes) + P(12 successes) + P(13 successes) + P(14 successes)

Using a calculator, we can find that this probability is approximately 0.2142. This probability is greater than 0.05, so it would not be considered unusual for 11 or more of the flights to be on time.

This problem can be approached as a **binomial **distribution. The probability of a particular number of flights on time is calculated using the binomial probability formula. Determining 'unusual' can be subjective but normally a probability less than 0.05 is considered unusual.

This problem is a binomial probability problem because we have a **binary **circumstance (flight is either on time or it isn't) and a fixed number of trials (14 flights). The binomial probability formula is P(X=k) = C(n, k) * (p^k) * ((1 - p)^(n - k)) where n is the number of trials, k is the number of successful trials, p is the probability of success on a single trial, and C(n, k) represents the number of **combinations **of n items taken k at a time.

(a) For all 12 **flights **on time, it seems there's a typo; there are 14 flights in the sample. We can't calculate for 12 out of 14 flights without the rest of the information.

(b) For exactly 10 flights, we use n=14, k=10, p=0.85: P(X=10) = C(14, 10) * (0.85^10) * ((1 - 0.85)^(14 - 10)).

(c) For 10 or more flights on time, it's the sum of the probabilities for 10, 11, 12, 13, and 14 flights on time.

(d) For determining whether 11 or more on-time flights is unusual, it depends on the specific context, but we could consider it unusual if the probability is less than 0.05.

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**Answer:**

6

**Step-by-step explanation:**

63-15 =48 48/8 is 6

**Answer:**

x = 6

**Step-by-step explanation:**

8x + 15 = 63

8x = 63 - 15

8x = 48

x = 48/8

x = 6

and

**Answer:**

number x

y = 3x +3

sum = x + y

19 = x + 3x + 3

19 = 4x + 3

19- 3 = 4x

16 = 4x

16/4 = x

x = 4

Note that the first function is f(x) = 4 for x less than 2 and for the second function f(x) = -1 for x greater than or equal to 2

So the limit as x approaches two from the left is 4 and the limit as x approaches 2 from the right is -1.

so looks like you would need the third choice: 4; -1

So the limit as x approaches two from the left is 4 and the limit as x approaches 2 from the right is -1.

so looks like you would need the third choice: 4; -1