5 23 18 8 4
Order of operations

Answers

Answer 1
Answer:

Answer:

no u

Step-by-step explanation:

Answer 2
Answer:

Answer:

hmm lets see sorry i cant help i wish i could but its been a while

Step-by-step explanation:


Related Questions

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Estimate the quotient for the following problems.a. 608/23=____\_____=_____
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The center of the circle is located (3'8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle

Write the number 31 in tens and ones

Answers

10 + 10 + 10 + 1
or
1 +1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1
;)

The tens digit is 3. There are three of these which makes it to 30. Also, the ones digit of this number is equal to 1. The answer to this item are therefore 30 and 1.

Hope this helps!
tens is 310.000 and ones is 31.000 I think hope it helps

In January of 2003(group 1), 1188 out of 1500 spots were bare ground (no vegetation). Find the sample proportion of bare ground spots.

Answers

Answer:

n= 1500 represent the random sample selected

X= 1188 represent the number of pots that were bare ground (no vegetation

\hat p=(X)/(n)

And replacing we got:

\hat p=(1188)/(1500)= 0.792

So then the sample proportion of bare ground spots is 0.792 for this sample

Step-by-step explanation:

We have the following info given from the problem:

n= 1500 represent the random sample selected

X= 1188 represent the number of pots that were bare ground (no vegetation)

And for this case if we want to find the sample proportion of bare ground spots we can use this formula:

\hat p=(X)/(n)

And replacing we got:

\hat p=(1188)/(1500)= 0.792

So then the sample proportion of bare ground spots is 0.792 for this sample

Final answer:

The sample proportion of bare ground spots is calculated by dividing the number of bare ground spots (successes) by the total number of spots (sample size). Using this method, the sample proportion for this scenario is 0.792 or 79.2%.

Explanation:

The student has asked about finding the sample proportion of bare ground spots. In Statistics, one defines a sample proportion as the number of successes in a sample divided by the number of observations in that sample. In this case, the 'success' is finding a spot of bare ground.

The sample size here is the total number of spots observed, which is 1500 (group 1) and the number of successes is the number of bare ground spots, which is 1188.

To calculate the sample proportion, one uses the formula: p = x/n, where 'x' is the number of successes and 'n' the sample size. So, for this scenario the sample proportion (p) would be: p = 1188/1500 = 0.792.

So, the sample proportion of bare ground spots is 0.792 or 79.2% when expressed as a percentage.

Learn more about Sample Proportion here:

brainly.com/question/32638029

#SPJ11

Use the following to answer Sean takes two 250 mg chewable calcium tablets each day, 6) How many milligrams of calcium will Sean take in a week?
7) How many grams of calcium will Sean take in a week?​

Answers

6. 1,750 mg in a week 7. 1.75 g in a week

Can anyine kindly help please?​

Answers

Answer:

i think it might be C

Step-by-step explanation:

Keith has a bag of Skittles. He is trying to get Jashawn to figer out how many Skittles are in his bag. There are 16 red. 25% of the bag is orange. 1/8 of the skittles are yellow. Tge rest of the skittles are green.If 2/5 of the bag is red,how many skittles are in the bag? How many skittles are orange? How many of the skittles are green?

Answers

Answer:

Total number of skittles in bag are 40

There are 10 orange skittles.

There are are 9 green skittles.

Step-by-step explanation:

Suppose there are "x" number of skittles in the bag.

Given that 2/5 of x = 16

Solving above equations gives , x = 40

That means total numbers of skittles are 40.

2/5 of 40 = 16 red skittles.

25 % of 40 = 10 orange skittles

1/8 of 40 = 5 yellow skittles

40-16-10-5 = 9 green skittles.

According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest. A random sample of 154 executive officers from these companies was selected. What is the probability that more than 20% of this sample is comprised of female employees?

Answers

Using the normal probability distribution and the central limit theorem, it is found that there is a 0.0869 = 8.69% probability that more than 20% of this sample is comprised of female employees.

Normal Probability Distribution

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = (X - \mu)/(\sigma)

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean \mu = p and standard deviation s = \sqrt{(p(1 - p))/(n)}, as long as np \geq 10 and n(1 - p) \geq 10.

In this problem:

  • 16% of executive officers were women with companies that have company headquarters in the Midwest, hence p = 0.16.
  • A random sample of 154 executive officers from these companies was selected, hence n = 154.

The mean and the standard error are given by:

\mu = p = 0.16

s = \sqrt{(p(1 - p))/(n)} = \sqrt{(0.16(0.84))/(154)} = 0.0295

The probability that more than 20% of this sample is comprised of female employees is 1 subtracted by the p-value of Z when X = 0.2, hence:

Z = (X - \mu)/(\sigma)

By the Central Limit Theorem

Z = (X - \mu)/(s)

Z = (0.2 - 0.16)/(0.0295)

Z = 1.36

Z = 1.36 has a p-value of 0.9131.

1 - 0.9131 = 0.0869.

0.0869 = 8.69% probability that more than 20% of this sample is comprised of female employees.

To learn more about the normal probability distribution and the central limit theorem, you can take a look at brainly.com/question/24663213

Answer: 0.0885

Step-by-step explanation:

Given : According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest.

i.e. p= 0.16

Sample size : n= 154

Now, the  probability that more than 20% of this sample is comprised of female employees is given by :-

P(p>0.20)=P(z>\frac{0.20-0.16}{\sqrt{(0.16(1-0.16))/(154)}})

[∵ z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}]

=P(z>1.35)\approx1-P(z\leq1.35)=1-0.9115=0.0885  [Using the standard z-value table]

Hence, the required probability = 0.0885