Which of the following graphs is a function?
Which of the following graphs is a function? - 1


Answer 1



Step-by-step explanation:

because of the line test

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A plant produces 500 units/hour of an item with dimensions of 4” x 6” x 2”. The manager wants to store two weeks of supply in containers that measure 3 ft x 4 ft x 2 ft. (Note: She can store the units in the containers such as that the 4” dimension aligns with either the 3 ft width or the 4 ft length of the box, whichever allows more units to be stored.) A minimum of 2 inches of space is required between adjacent units in each direction. If the containers must be stacked 4-high, and the warehouse ceiling is 9 feet above the floor, then determine the amount of floor space required just for storage.



  564 ft²

Step-by-step explanation:

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

  3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

  (4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

  47 × 12 ft² = 564 ft²

of warehouse floor space required for storage.


The second attachment shows the top view and side view of units packed in a storage box.

16 is what percent of 20?




Step-by-step explanation:

16/20 = 0.8
0.8 * 100 = 80
Solution: 80%

A restaurant offers a dinner special that has 12 choices for entrees, 10 choices for side dishes, and 6 choices for dessert. How many different meals are possible?


there are 720 meal possibilities.

I need help on a question but im kinda in a rush



1) To find out the Lateral Area of this pyramid we need to calculate the area of those three equilateral triangles.

\begin{gathered} Lateral_(Area)=3(s^2\frac{\sqrt[]{3}}{4})=3(16\frac{\sqrt[]{3}}{4}) \n L=3\cdot4\sqrt[]{3} \n L=12\sqrt[]{3} \end{gathered}

2) Hence, the Lateral Area of that pyramid is 12√3

How do you do this question?


Step-by-step explanation:

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

Need help ASAP if y’all could pls help me out that would be great


hi! here’s what i’d put for the sentences to fill in the blanks:

- 1 ten is equal to 10 ones. 1 ten is 10 times the value of 1 one.

- 1 hundred is equal to 10 tens. 1 hundred is 10 times the value of 1 ten.

- 1 thousand is equal to 10 hundreds. 1 thousand is 10 times the value of 1 hundred.

- 1 ten-thousand is equal to 10 thousands. 1 ten-thousand is 10 times the value of 1 thousand.

- 1 hundred-thousand is equal to 10 ten-thousands. 1 hundred-thousand is 10 times the value of 1 ten-thousand.

Place Value Chart:

blank space before 3 is 2

hope this helped!:)