Answer:

**Answer:**

a

**Step-by-step explanation:**

because of the line test

Given f(x) = -4x - 10 and g(x) = x2 + 1 find f(-2) + g(3).

If two objects travel through space along two different curves, it's often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions for t 0. Do the particles collide? If they collide find t. If not enter NONE.r1(t)=r2(t)=<9t-14,t^2,13t-42>t=

What is (7p + 6) - (9p - 7)?

A company builds a new wing for its east branch and knows that each additional room will gain $1200 of profit. The construction company will cost $44,000 to construct the wing.How many rooms are need to break even? (Hint: You must PAY the fee to the construction company.)If you wanted to make twice as much profit as you spent, how many rooms would need to be built?

The parabola y=x2 is scaled vertically by a factor of 7. What if the equation of the new parabola

If two objects travel through space along two different curves, it's often important to know whether they will collide. (Will a missile hit its moving target? Will two aircraft collide?) The curves might intersect, but we need to know whether the objects are in the same position at the same time. Suppose the trajectories of two particles are given by the vector functions for t 0. Do the particles collide? If they collide find t. If not enter NONE.r1(t)=r2(t)=<9t-14,t^2,13t-42>t=

What is (7p + 6) - (9p - 7)?

A company builds a new wing for its east branch and knows that each additional room will gain $1200 of profit. The construction company will cost $44,000 to construct the wing.How many rooms are need to break even? (Hint: You must PAY the fee to the construction company.)If you wanted to make twice as much profit as you spent, how many rooms would need to be built?

The parabola y=x2 is scaled vertically by a factor of 7. What if the equation of the new parabola

**Answer:**

564 ft²

**Step-by-step explanation:**

To account for the extra space between units, we can add 2" to every unit dimension and every box dimension to figure the number of units per box.

Doing that, we find the storage box dimensions (for calculating contents) to be ...

3 ft 2 in × 4 ft 2 in × 2 ft 2 in = 38 in × 50 in × 26 in

and the unit dimensions to be ...

(4+2)" = 6" × (6+2)" = 8" × (2+2)" = 4"

A spreadsheet can help with the arithmetic to figure how many units will fit in the box in the different ways they can be arranged. (See attached)

When we say the "packing" is "462", we mean the 4" (first) dimension of the unit is aligned with the 3' (first) dimension of the storage box; the 6" (second) dimension of the unit is aligned with the 4' (second) dimension of the storage box; and the 2" (third) dimension of the unit is aligned with the 2' (third) dimension of the storage box. The "packing" numbers identify the unit dimensions, and their order identifies the corresponding dimension of the storage box.

We can see that three of the four allowed packings result in 216 units being stored in a storage box.

If storage boxes are stacked 4 deep in a 9' space, the 2' dimension must be the vertical dimension, and the floor area of each stack of 4 boxes is 3' × 4' = 12 ft². There are 216×4 = 864 units stored in each 12 ft² area.

If we assume that 2 weeks of production are 80 hours of production, then we need to store 80×500 = 40,000 units. At 864 units per 12 ft² of floor space, we need ceiling(40,000/864) = 47 spaces on the floor for storage boxes. That is ...

47 × 12 ft² = **564 ft²**

of warehouse floor space required for storage.

_____

The second attachment shows the top view and side view of units packed in a storage box.

**Answer:**

3.2

**Step-by-step explanation:**

16/20 = 0.8

0.8 * 100 = 80

Solution: 80%

0.8 * 100 = 80

Solution: 80%

there are 720 meal possibilities.

**12√3**

1) To find out the Lateral Area of this pyramid we need to calculate the area of those three equilateral triangles.

2) Hence, the Lateral Area of that pyramid is **12√3** u²

**Step-by-step explanation:**

∫ dt / (cos²(t) ⁹√(1 + tan(t)))

If u = 1 + tan(t), then du = sec²(t) dt.

∫ du / ⁹√u

∫ u^(-1/9) du

9/8 u^(8/9) + C

9/8 (1 + tan(t))^(8/9) + C

hi! here’s what i’d put for the sentences to fill in the blanks:

- 1 ten is equal to 10 ones. 1 ten is 10 times the value of 1 one.

- 1 hundred is equal to 10 tens. 1 hundred is 10 times the value of 1 ten.

- 1 thousand is equal to 10 hundreds. 1 thousand is 10 times the value of 1 hundred.

- 1 ten-thousand is equal to 10 thousands. 1 ten-thousand is 10 times the value of 1 thousand.

- 1 hundred-thousand is equal to 10 ten-thousands. 1 hundred-thousand is 10 times the value of 1 ten-thousand.

Place Value Chart:

blank space before 3 is 2

hope this helped!:)

- 1 ten is equal to 10 ones. 1 ten is 10 times the value of 1 one.

- 1 hundred is equal to 10 tens. 1 hundred is 10 times the value of 1 ten.

- 1 thousand is equal to 10 hundreds. 1 thousand is 10 times the value of 1 hundred.

- 1 ten-thousand is equal to 10 thousands. 1 ten-thousand is 10 times the value of 1 thousand.

- 1 hundred-thousand is equal to 10 ten-thousands. 1 hundred-thousand is 10 times the value of 1 ten-thousand.

Place Value Chart:

blank space before 3 is 2

hope this helped!:)