Choose the true statement.
O-2» -3
O -2 = -3


Answer 1
Answer: 0-2>-3 is the answer, because negative 2 is greater than negative 3.

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Can someone help me with this please?

Suppose that a medical test has a 92% chance of detecting a disease if the person has it (i.e., 92% sensi- tivity) and a 94% chance of correctly indicating that the disease is absent if the person really does not have the disease (i.e., 94% specificity). Suppose 10% of the popu- lation has the disease. (a) What is the probability that a randomly chosen per- son will test positive



14.6% probability that a randomly chosen person will test positive

Step-by-step explanation:

We have these following probabilities:

10% probability that a randomly selected person has the disease.

If a person has the disease, 92% probability of testing positive.

100-10 = 90% probability that a person does not have the disease.

If a person does not have the disease, 100-94 = 6% probability of testing positive.

What is the probability that a randomly chosen person will test positive

92% of 10% or 6% of 90%.


p = 0.92*0.1 + 0.06*0.9 = 0.146

14.6% probability that a randomly chosen person will test positive

Find the area of the triangle Please help




Step-by-step explanation:

Area of a triangle is - 1/2 base times hight

two triangels find the srea of both and add them

4x4x1/2 = 16x1/2 = 8m

3x4x1/2 = 12x1/2 = 6m

6m + 8m = 14m

PLEASE HELP!Which is the correct classification of square root of 18?

A. irrational number, non-repeating decimal
B. irrational number, terminating decimal
C. rational number, terminating decimal
D .rational number, non-repeating decimal


The correct classification of the square root of 18 is: A. irrational number, non-repeating decimal.

To determine the classification of the square root of 18, let's break down the steps:

1. Calculate the square root of 18:

  \(√(18) \approx 4.24264068712\)

2. Rational or Irrational?

  The square root of 18 is an irrational number because it cannot be expressed as a fraction of two integers, and it is non-terminating, non-repeating decimal.

Rational numbers can be expressed as fractions, and their decimal representation either terminates (e.g., 1/4 = 0.25) or repeats in a pattern (e.g., 1/3 = 0.333...).

Since \(√(18)\) cannot be expressed as a simple fraction, and its decimal representation continues infinitely without repeating, it is classified as an irrational number, non-repeating decimal.

So, the correct classification is: A. irrational number, non-repeating decimal.

To know more about square root, refer here:



That would be option A,because it's Irrational and non repeating.

Solve this differential Equation by using power series


We're looking for a solution

y=\displaystyle\sum_(n=0)^\infty a_nx^n

which has second derivative

y''=\displaystyle\sum_(n=2)^\infty n(n-1)a_nx^(n-2)=\sum_(n=0)^\infty(n+2)(n+1)a_(n+2)x^n

Substituting these into the ODE gives

\displaystyle\sum_(n=0)^\infty(n+2)(n+1)a_(n+2)x^n-\sum_(n=0)^\infty a_nx^(n+2)=0

\displaystyle\sum_(n=0)^\infty(n+2)(n+1)a_(n+2)x^n-\sum_(n=2)^\infty a_(n-2)x^n=0

\displaystyle2a_2+6a_3x+\sum_(n=2)^\infty(n+2)(n+1)a_(n+2)x^n-\sum_(n=2)^\infty a_(n-2)x^n=0


Right away we see a_2=a_3=0, and the coefficients are given according to the recurrence

\begin{cases}a_0=y(0)\na_1=y'(0)\na_2=0\na_3=0\nn(n-1)a_n=a_(n-4)&\text{for }n\ge4\end{cases}

There's a dependency between terms in the sequence that are 4 indices apart, so we consider 4 different cases.

  • If n=4k, where k\ge0 is an integer, then

k=0\implies n=0\implies a_0=a_0

k=1\implies n=4\implies a_4=(a_0)/(4\cdot3)=\frac2{4!}a_0

k=2\implies n=8\implies a_8=(a_4)/(8\cdot7)=(6\cdot5\cdot2)/(8!)a_0

k=3\implies n=12\implies a_(12)=(a_8)/(12\cdot11)=(10\cdot9\cdot6\cdot5\cdot2)/(12!)a_0

and so on, with the general pattern


  • If n=4k+1, then

k=0\implies n=1\implies a_1=a_1

k=1\implies n=5\implies a_5=(a_1)/(5\cdot4)=(3\cdot2)/(5!)a_1

k=2\implies n=9\implies a_9=(a_5)/(9\cdot8)=(7\cdot6\cdot3\cdot2)/(9!)a_1

k=3\implies n=13\implies a_(13)=(a_9)/(13\cdot12)=(11\cdot10\cdot7\cdot6\cdot3\cdot2)/(13!)a_1

and so on, with


  • If n=4k+2 or n=4k+3, then

a_2=0\implies a_6=a_(10)=\cdots=a_(4k+2)=0

a_3=0\implies a_7=a_(11)=\cdots=a_(4k+3)=0

Then the solution to this ODE is

\boxed{y(x)=\displaystyle\sum_(k=0)^\infty a_(4k)x^(4k)+\sum_(k=0)^\infty a_(4k+1)x^(4k+1)}

What are the integers of 171



56, 57, and 58.

Step-by-step explanation:

Use the Distributive Property to solve the equation.2x - 4(x-3) = -5+2x-3
The solution of the equation is .
(Type the value of x.)




Step-by-step explanation:

2x-4x+12 = -5+2x+3

-2x+12 = -2+2x

-2x-2x = -12-2