When using 3 letters to make an angle the middle letter is

Answers

Answer 1
Answer: X? Not sure what the answer choices are but try that

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Find the slope of the line that asses through the pair of oints (17,11) and (21,19)

Answers

Answer:

The slope of the two points is 2. (8/4)

Answer:

The slope of the two points is 2. (8/4)

Step-by-step explanation:

thats it

HELP PLEZ TRIGONOMETRY!

Answers

(2 \sin ^(2) \alpha-1)/(\sin \alpha+\cos \alpha) = sin \alpha - cos \alpha

Solution:

Given that we have to simplify:

(2 \sin ^(2) \alpha-1)/(\sin \alpha+\cos \alpha) ---- eqn 1

We know that,

sin^2 x = 1 - cos^2 x

Substitute the above identity in eqn 1

(2\left(1-\cos ^(2) \alpha\right)-1)/(\sin \alpha+\cos \alpha)

Simplify the above expression

(2-2 \cos ^(2) \alpha-1)/(\sin \alpha+\cos \alpha)

(1-2 \cos ^(2) \alpha)/(\sin \alpha+\cos \alpha) ------- eqn 2

By the trignometric identity,

(sin x + cos x)(sin x - cos x) = 1-2cos^2 x

Substitute the above identity in eqn 2

((\sin \alpha+\cos \alpha)(\sin \alpha-\cos \alpha))/(\sin \alpha+\cos \alpha)

Cancel the common factors in numerator and denominator

((\sin \alpha+\cos \alpha)(\sin \alpha-\cos \alpha))/(\sin \alpha+\cos \alpha)=\sin \alpha-\cos \alpha

Thus the simplified expression is:

(2 \sin ^(2) \alpha-1)/(\sin \alpha+\cos \alpha) = sin \alpha - cos \alpha

Will mark brainliest, 60 points

Answers

Answer:

\boxed{ \bold{ \sf{ \: 1. \:  \:  \:  \:  \: 198}}}

\boxed{ \bold{ \sf{2. \:  \:  \:  \:  \:  - 8}}}

\boxed{ \bold{ \sf{ 3. \:  \:  \:  \:  \: (64)/(343) }}}

Step-by-step explanation:

1. Given, u = 20 , x = 4 , y = 7 , z = 10

\sf{ (u)/(z)  + x {y}^(2) }

\sf{ (20)/(10)  + 4 *  {7}^(2) }

\sf{ (20)/(10)  + 4 * 49}

\sf{ (20)/(10)  + 196}

\sf{ (20 + 196 * 10)/(10) }

\sf{ (20 + 1960)/(10) }

\sf{ (1980)/(10) }

\sf{198}

2. \sf{4( - 2)}

Multiplying or dividing a positive integer by any negative integer gives a negative integer

= -8

3. \sf{( (4)/(7) ) ^(3) }

\sf{( \frac{ {4}^(3) }{ {7}^(3) } })

\sf{ (4 * 4 * 4 )/(7 * 7 * 7)}

\sf{ (64)/(343) }

Hope I helped!

Best regards! :D

Answer:

\Huge \boxed{\mathrm{18. \ \ \ 198}}  \n\n\n \Huge \boxed{\mathrm{19. \ \ \ -8}} \n\n\n \Huge \boxed{\mathrm{20. \ \ \  (64)/(343) }}

\rule[225]{225}{2}

Step-by-step explanation:

18.

\displaystyle (u)/(z) +xy^2

u = 20, x = 4, y = 7, and z = 10.

\Rightarrow \displaystyle (20)/(10) +(4)(7)^2

\Rightarrow \displaystyle 2+(4)(49)

\Rightarrow 2+196

\Rightarrow 198

19.

4(-2)

Rewriting.

\Rightarrow -(4*2)

Multiplying.

\Rightarrow -8

20.

\displaystyle ( (4)/(7) )^3

Distributing the cube sign to the numerator and the denominator.

\Rightarrow  \displaystyle (4^3 )/(7^3 )

\Rightarrow \displaystyle (64)/(343)

\rule[225]{225}{2}

Fling
Find the slope of the line passing through the points (1,5) and (4,-2).

Answers

Subtract x2 from x1 to get -7. After that subtract y2 from y1 to receive 3. That leaves you with -7/3 which simplified is -2.1333*

Helen is building a rectangular garden in her backyard and she wants to have a fence around it.The perimeter of her garden is 20 yards. She is buying wood fence panels that cost $2 per foot. How many feet of fence panels does she need

Answers

Based on the calculations, Helen needs to buy 60 feet of fence panels for her rectangular garden in the backyard

How many feet of fence panels does she need

From the question, we have the following parameters that can be used in our computation:

  • The perimeter of her garden is 20 yards.
  • She is buying wood fence panels that cost $2 per foot

This means that

Perimeter = 20 yards

By metrric unit of conversion, we have

1 yard = 3 feet

So, we have

Perimeter = 20 * 3 feet

Evaluate

Perimeter = 60 feet

Hence, she needs to buy 60 feet of fence panels

Read more about perimeter at

brainly.com/question/19819849

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Given: 44 - 2(3x + 4) = -18Prove: x = 9

Answers

Substitute 9 as x in the given function:
44-2(3(9)+4)=-18
Now check and see if the statement it true and simplify.
44-2(27+4)=-18
44-2(31)=-18
44-62=-18
-18=-18
You can see this is true !!
Show my work to answer this question .