Answer:

**Answer:**

1) I_ pendulum = 2.3159 kg m², 2) I_pendulum = 24.683 kg m²

**Explanation:**

In this exercise we are asked to calculate the moment of inertia of a physical pendulum, let's start by calculating the center of mass of each elements of the pendulum and then the center of mass of the pendulum

Sphere

They indicate the density of the sphere roh = 37800 kg / m³ and its radius

r = 5 cm = 0.05 m

we use the definition of density

ρ = M / V

M = ρ V

the volume of a sphere is

V = 4/3 π r³

we substitute

M = ρ 4/3 π r³

we calculate

M = 37800 4/3 π 0.05³

M = 19,792 kg

Bar

the density is ρ = 32800 kg / m³ and its dimensions are 1 m,

0.8 cm = 0.0008 m and 4cm = 0.04 m

The volume of the bar is

V = l w h

m = ρ l w h

we calculate

m = 32800 (1 0.008 0.04)

m = 10.496 kg

Now we can calculate the center of mass of the pendulum, we use that the center of mass of the sphere is its geometric center, that is, its center and the center of mass of the bar is where the diagonals intersect, in this case it is a very bar. long and narrow, whereby the center of mass is about half the length. It's mass scepter of the pendulum is

r_cm = 1 / M (M r_sphere + m r_bar)

M = 19,792 + 10,496 = 30,288 kg

r_cm = 1 / 30,288 (10,496 0.5 + 19.792 (1 + 0.05))

r_cm = 1 / 30,288 (5,248 + 20,7816)

r_cm = 0.859 m

This is the center of mass of the pendulum.

1) Now we can calculate the moment of inertia with respect to this center of mass, for this we can use the theorem of parallel axes and that the moments of inertia of the bodies are:

Sphere I = 2/5 M r2

Bar I = 1/12 m L2

parallel axes theorem

I = I_cm + m D²

where m is the mass of the body and D is the distance from the body to the axis of rotation

Sphere

m = 19,792 ka

the distance D is

D = 1.05 -0.85

D = 0.2 m

we calculate

I_sphere = 2/5 19.792 0.05 2 + 19.792 0.2 2 = 0.019792 +0.79168

I_sphere = 0.811472 kg m²

Bar

m = 10.496 kg

distance D

D = 0.85 - 0.5

D = 0.35 m

I_bar = 1/12 10.496 0.5 2 + 10.496 0.35 2 = 0.2186 + 1.28576

I_bar = 1.5044 kg m²

The moment of inertia is a scalar quantity whereby the moment of inertia of the body is the sum of the moment of the parts

I_pendulum = I_sphere + I_bar

I_pendulum = 0.811472 +1.5044

I_ pendulum = 2.3159 kg m²

this is the moment of inertia of the pendulum with respect to its center of mass located at r = 0.85 m

2) The moment is requested with respect to the pivot point at r = 0 m

Sphere

D = 1.05 m

I_sphere = 2/5 M r2 + M D2

I_sphere = 2/5 19.792 0.05 2 + 19.792 1.05 2 = 0.019792 +21.82

I_sphere = 21.84 kg m²

Bar

D = 0.5 m

I_bar = 1/12 10.496 0.5 2 + 10.496 0.5 2 = 0.21866 + 2.624

I_bar = 2,84266 kg m 2

The pendulum moment of inertia is

I_pendulum = 21.84 +2.843

I_pendulum = 24.683 kg m²

This moment of inertia is about the turning point at r = 0 m

A 1500 kg car moving at 25 m/s hits an initially uncompressed horizontal ideal spring with spring constant (force constant) of 2.0 × 106 N/m. What is the maximum distance the spring compresses?

A fully loaded, slow-moving freight elevator has a cab with a total mass of 1200 kg, which is required to travel upward 35 m in 3.5 min, starting and ending at rest. The elevator's counterweight has a mass of only 940 kg, so the elevator motor must help pull the cab upward. What average power is required of the force the motor exerts on the cab via the cable

Ugoing o pri7.) True or False: "Courtney is traveled 5 miles in 3 hours" is an example ofacceleration.TrueFalse

Write a paragraph or two (no more than 1 page) describing the misconception and then explain the correct physics by identifying the forces or physics concepts involved in simple terms, like you are talking to your 3rd grade sibling. Start with a question (will water fall out of the bucket when I stop rotating it?)Give the common answer that is incorrect (what does your intuition tell you should happen?).Explain what happens and why in simple terms (try practicing on an elementary student to make sure they understand).Use diagrams and sketches in your explanation and avoid using physics terms like rotational, centripetal, normal forces, tension, friction, acceleration, velocity, vectors, buoyancy, energy, kinetics, potential, heat capacity, etc.

A firefighting crew uses a water cannon that shoots water at 27.0 m/s at a fixed angle of 50.0 ∘ above the horizontal. The firefighters want to direct the water at a blaze that is 12.0 m above ground level. How far from the building should they position their cannon? There are two possibilities (d1Part A:d1=_____mPart B:d2=______m

A fully loaded, slow-moving freight elevator has a cab with a total mass of 1200 kg, which is required to travel upward 35 m in 3.5 min, starting and ending at rest. The elevator's counterweight has a mass of only 940 kg, so the elevator motor must help pull the cab upward. What average power is required of the force the motor exerts on the cab via the cable

Ugoing o pri7.) True or False: "Courtney is traveled 5 miles in 3 hours" is an example ofacceleration.TrueFalse

Write a paragraph or two (no more than 1 page) describing the misconception and then explain the correct physics by identifying the forces or physics concepts involved in simple terms, like you are talking to your 3rd grade sibling. Start with a question (will water fall out of the bucket when I stop rotating it?)Give the common answer that is incorrect (what does your intuition tell you should happen?).Explain what happens and why in simple terms (try practicing on an elementary student to make sure they understand).Use diagrams and sketches in your explanation and avoid using physics terms like rotational, centripetal, normal forces, tension, friction, acceleration, velocity, vectors, buoyancy, energy, kinetics, potential, heat capacity, etc.

A firefighting crew uses a water cannon that shoots water at 27.0 m/s at a fixed angle of 50.0 ∘ above the horizontal. The firefighters want to direct the water at a blaze that is 12.0 m above ground level. How far from the building should they position their cannon? There are two possibilities (d1Part A:d1=_____mPart B:d2=______m

14 g is the solubility per 100 g water, since it is difficult to read the graph.

Then, in 130 g H20 the solubility would be 14 g KNO3/100 g H2O x 130 g H2O = 18 g KNO3

The question asks how much crystallizes.

Initial 34.0 g minus 18.0 g still dissolved = 16.0 g crystallizes.

Then, in 130 g H20 the solubility would be 14 g KNO3/100 g H2O x 130 g H2O = 18 g KNO3

The question asks how much crystallizes.

Initial 34.0 g minus 18.0 g still dissolved = 16.0 g crystallizes.

KNO3 of **10g** will undergo crystallization at **0 ° **

*Because the heavier the ***KNO3*** mass will require a higher temperature in the dissolution process. *

Potassium nitrate is a nitrate salt compound from potassium with the molecular formula KNO3. Potassium nitrate salt can be made by reacting potassium chloride with sodium nitrate. If the saturated solution each of the solution is mixed with each other, then it will form sodium chloride salt because NaCl in water is small, the salt will settle. By cooling the filtered filtrate KNO3 will undergo crystallization

This compound decomposes with oxygen evolution at 500 ° C according to the reaction equation:

2 NaNO3 (s) -> 2NaNO 2 (s) + O2 (g)

Crystallization is separation by forming crystals so that the mixture can be separated. A gaseous or liquid substance can cool or condense and form crystals because it undergoes a crystallization process. Crystals will also form from a solution that will be saturated with a certain solvent. The more the number of crystals, the better, because the less likely to be polluted by dirt.

Potassium Nitrate has a physical white powder that is easily soluble in water and odorless. Meanwhile, to analyze the structure and characteristics of Potassium Nitrate MM2 data processing is used in the Chemoffice 15.0 application. This data processing is used to determine the shape of compounds, types of bonds in molecular movement compounds and other parts that can not be observed directly by the eye without the aid of tools. And for the form of compounds in 2 dimensions and 3 dimensions used Chemdraw 15.0 and Chem3D 15.0 applications

**Learn more **

Potassium nitrate brainly.com/question/10847775

Crystallization brainly.com/question/2575925

**Details **

Grade: High School

Subject: Chemistry

Keyword: kno3, nitrate, crystallization

**Answer:**

**V= 57.5 V**

**Explanation:**

- If the resistors are in the linear zone of operation, the potential difference across them, must obey Ohm's law:

- For the 6.0 Ω resistor, if the potential difference across it is 15 V, we can find the current flowing through it as follows:

- In a series circuit, the current is the same at any point of it, so the current through the battery is I = 2.5 A
- The equivalent resistance of a series circuit is just the sum of the resistances, so, in this case, we can write the following equation:

- Applying Ohm's Law to the equivalent resistance, we can find the potential difference through it, that must be equal to the potential difference across the battery, as follows:

B. 4F

C. 4F/3

D. 4F/9

E. F/3

**Answer:**

F'= 4F/9

**Explanation:**

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

.....(2)

Dividing equation (1) and (2), we get :

**Hence, the correct option is (d) i.e. " 4F/9"**

The magnitude of the force on the +4Q charge, after replacing one of the original +Q charges and moving the charges three times farther apart, is calculated to be 4F/9 using Coulomb's Law. Therefore, the correct answer is D.

The magnitude of the electrostatic force between two charges can be described by Coulomb's Law, which states that F = k × (q1 × q2) / r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the centers of the two charges. Originally, two objects each with charge +Q exert a force of magnitude F on each other. After one charge is replaced with a +4Q charge and they are moved to be three times as far apart, the force on the +4Q charge can be calculated using the modified version of Coulomb's Law that takes into account the new charges and distance.

Using the original scenario as a reference, where F = k × (Q × Q) / r^2, when the charge is replaced and the distance is tripled, the new force F' = k × (Q × 4Q) / (3r)^2 = 4kQ^2 / 9r^2. By comparing F' with F, we find that F' = (4/9)F. Thus, the magnitude of the force on the +4Q charge is 4F/9.

planet?

A. You would weigh the same on both planets because the planets

are the same size.

B. You would weigh less on planet A because it has less mass than

planet B.

C. You would weigh the same on both planets because your mass

would be the same on both.

D. You would weigh more on planet A because it has less mass than

planet B.

The statement which correctly explains the **weight** you would experience on each **planet** is: B. You would weigh less on planet A because it has less mass than planet B.

**Weight** can be defined as the **force** acting on a body or an object as a result of **gravity**.

Mathematically, the **weight** of an **object** is given by the **formula**;

__Where;__

- m is the
**mass**of the**object**.

- g is the
**acceleration**due to**gravity**.

Hence, we can deduce that the **weight** and **gravity** acting on an object is highly dependent on the **mass** of an object.

Therefore, the **higher** the **mass **in a **planet**, the **higher **the **gravity** existing there.

Read more: brainly.com/question/18320053

**Answer:**

**B**

**Explanation:**

The more mass an object has, the more gravity it has.

A. Consult with a friend and get their feeback

B. Dispute the beliefs by asking if these are true and examining the evidence

C. Seek mental health counseling

D. It is just too hard so let's just forget it.

**Answer:**

i believe the answer is B

**Explanation:**

Seeking the right answer is the best thing to do

The force of gravity that the space shuttle experiences is 9.8 x 10^5 Newtons.

To calculate the force of gravity that the space shuttle experiences, we can use the equation** F = mg, **where F represents the force of gravity, m is the mass of the object, and g is the acceleration due to gravity (approximately 9.8 m/s² on Earth). In this case, the mass of the space shuttle is given as 1.0 x 10^5 kg. However, we need to convert the altitude of the shuttle into meters, so 200.0 km becomes 200,000 meters.

Now we can calculate the force of gravity:

F = (1.0 x 10^5 kg)(9.8 m/s²)

F = 9.8 x 10^5 N

Therefore, the space shuttle experiences a force of gravity of 9.8 x 10^5 Newtons.

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