Answer:

**Answer:**

**Step-by-step explanation:**

Hello, let's do it step by step and see what we can find.

We assume that M is different from 0, otherwise we could find several different solutions I would think.

It means that S + M is greater than 10, otherwise the number of digit of the result would have been 4 and not 5.

The only possible number for M is then 1. **M = 1**

But then, S can only by 9, otherwise S + 1 < 10. **S = 9**

S + 1 = 10 + O if there is no carry over, so S = 9 + O

1 + S + 1 = 10 + O if there is a carry, so S = 8 + O

So O = 0 or O = 1. Wait !? M is already equal to 1 so O must be 0

E cannot be equal to N so 1 + E = N, meaning that there must be a carry over from column second from the right.

and E < 9 as we know that there is no carry over from column 3 from the right.

N + R = 10 + E => 1 + E + R = 10 + E => R = 9, impossible, as S=9

or 1 + N + R = 10 + E => 1 + 1 + E + R = 10 + E => **R = 8**

And there is a carry over from the column 1 from the right, so:

Y cannot be 0 or 1, as already used so D + E > 11

8 and 9 are already taken so we could have 7 + 5 = 12, 7 + 6 = 13 and that's it.

It means that E is 7 or D is 7.

If E is 7 then E+1=9=N, impossible, so **D = 7**

Then, E is 5 or 6

if E = 6 E + 1 = N = 7, impossible, so **E = 5** and **N = 6**.

And 7 + 5 = 12 so **Y = 2**.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Suppose a professor splits their class into two groups: students whose last names begin with A-K and students whose last names begin with L-Z. If p1 and p2 represent the proportion of students who have an iPhone by last name, would you be surprised if p1 did not exactly equal p2? If we conclude that the first initial of a student's last name is NOT related to whether the person owns an iPhone, what assumption are we making about the relationship between these two variables?

20 POINTS! You are planning to use a ceramic tile design in your new bathroom. The tiles are equilateral triangles. You decide to arrange the tiles in a hexagonal shape as shown. If the side of each tile measures 9 centimeters, what will be the exact area of each hexagonal shape?

Please help me on this

Type your response in the box.Janet and Patrick are buying stuffed frogs each month to give to a charity. Pattern 1 describes Janet's collection overthe first three months. Pattern 2 describes Patrick's collection. Study both patterns, and fill in the table based onyour observations.

The table shows the distances and times that four people ran. Without making any calculations, who ran the fastest?

20 POINTS! You are planning to use a ceramic tile design in your new bathroom. The tiles are equilateral triangles. You decide to arrange the tiles in a hexagonal shape as shown. If the side of each tile measures 9 centimeters, what will be the exact area of each hexagonal shape?

Please help me on this

Type your response in the box.Janet and Patrick are buying stuffed frogs each month to give to a charity. Pattern 1 describes Janet's collection overthe first three months. Pattern 2 describes Patrick's collection. Study both patterns, and fill in the table based onyour observations.

The table shows the distances and times that four people ran. Without making any calculations, who ran the fastest?

O y = -5x²

O y = 2x²

O y = - 3x²

Answer:

y = 2x^2

Step-by-step explanation:

**Answer:**

2x²

**Step-by-step explanation:**

**Answer:**

**0.1719**

**Step-by-step explanation:**

Given that:

A quiz contains 20 questions and 10 questions have been answered rightly

We are to determine the probability of getting a total quiz score of 85%

i.e 0.85 (20) = 17

Let's not forget that 10 is correctly answered out of 17. that implies that we only have 7 more questions to make a decision on.

where;

n = 10,

p + q = 1, 0.5 + q = 1

q = 1 - 0.5

q = 0.5

Let X be the random variable that follows the binomial distribution. Then ;

where x = 7

P(X ≥ 7) = **0.1719**

26*37=962sqft

Add 4 ft to both numbers (2ft per side)

30*41=1230sqft

Subtract out the garden area

1230-962=268sqft

The path is 268 sq ft

Add 4 ft to both numbers (2ft per side)

30*41=1230sqft

Subtract out the garden area

1230-962=268sqft

The path is 268 sq ft

Find the lower quartile and upper quartile of

the data set.

lower quartile: $

upper quartile: S

?

$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80

**Answer:**

Lower quartile: $1.42

Upper quartile: $1.64

**Step-by-step explanation:**

The **median **is the **middle value** when all data values are placed in order of size.

The ordered **data set** is:

$1.39 $1.40 $1.44 $1.50 $1.60 $1.63 $1.65 $1.80

There are** 8 data values** in the data set, so this is an** even data set**.

Therefore, the **median **is the **mean **of the **middle two values**:

Place "||" in the middle of the data set to signify where the median is:

$1.39 $1.40 $1.44 $1.50 ║ $1.60 $1.63 $1.65 $1.80

The** lower quartile **(Q₁) is the **median **of the **data points **to the **left **of the median. As there is an even number of data points to the left of the median, the lower quartile is the mean of the the middle two values:

The** upper quartile **(Q₃) is the **median **of the **data points **to the **right **of the median. As there is an even number of data points to the right of the median, the upper quartile is the mean of the the middle two values:

**Answer:**

to find the lower quartile and upper quartile of the given dataset, we need to first arrange the data in ascending order:

$1.39, 1.40, 1.44, 1.50, 1.60, 1.63, 1.65, 1.80$

The median of the dataset is given as $1.55$. Since there are an even number of data points, the median is the average of the two middle values, which in this case are $1.50$ and $1.60$.

Now, we need to find the lower quartile and upper quartile. The lower quartile is the median of the lower half of the data set, and the upper quartile is the median of the upper half of the data set.

The lower half of the dataset is $1.39, 1.40, 1.44, 1.50$. The median of this half is the average of the middle two values, which are $1.40$ and $1.44$.

Therefore, the lower quartile is $1.42$.

The upper half of the dataset is $1.60, 1.63, 1.65, 1.80$. The median of this half is the average of the middle two values, which are $1.63$ and $1.65$.

Therefore, the upper quartile is $1.64$.

Hence, the lower quartile of the dataset is $1.42$ and the upper quartile is $1.64$.

Yes because 3 home work problems takes 10 min and 10x3 =30 and that’s a half hour

**Answer:**

390 because 78 is the width and 5 is length of the building so you need to 78x5 to get your answer