a. What is the probabilty that a random sample of n = 40 oil changes results in a sample mean time less than 15 minutes?

b. Suppose the manager agrees to pay each employee a $50 bonus if they meet a certain goal. On a typical Saturday, the oil-change facility will perform 40 oil changes between 10 A.M. and 12 P.M. Treating this as a random sample, there

would be a 10% chance of the mean oil-change time being at or below what value? This will be the goal established by the manager.

Answer:

Answer:

(a) Probability that a random sample of n = 45 oil changes results in a sample mean time < 10 minutes i=0.0001.

(b) The mean oil-change time is 15.55 minutes.

Step-by-step explanation:

Let us denote the sample mean time as x

From the Then x = mean time = 16.2 minutes

The given standard deviation = 3.4 minutes

The value of n sample size = 45

CHECK THE ATTACHMENT FOR DETAILED EXPLANATION

Maria bought bought 1 2/5 pounds of lunch meat for $3.36.How much would 2 3/4 pounds of lunch meat cost?Enter your answer in the box.$_______

-14/5 times (-51/69)

Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly selected individual has the disease. Suppose n individuals are independently selected for testing. One way to proceed is to carry out a separate test on each of the n blood samples. A potentially more economical approach, group testing, was introduced during World War II to identify syphilitic men among army inductees. First, take a part of each blood sample, combine these specimens, and carry out a single test. If no one has the disease, the result will be negative, and only the one test is required. If at least one individual is diseased, the test on the combined sample will yield a positive result, in which case the n individual tests are then carried out. [The article "Random Multiple-Access Communication and Group Testing"† applied these ideas to a communication system in which the dichotomy was active/idle user rather than diseased/nondiseased.] If p = 0.15 and n = 5, what is the expected number of tests using this procedure? (Round your answer to three decimal places.)

Consider the diagram and the proof below.Given: In △ABC, AD ⊥ BCProve: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFractionTriangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.What is the missing statement in Step 6?b = cStartFraction h Over b EndFraction = StartFraction h Over c EndFractioncsin(B) = bsin(C)bsin(B) = csin(C)

NEEd help quickly please!!! The basketball game had 500 people in attendance. If the ratio of Pioneer fans to Lion fans is 15:5, how many MORE Pioneer fans were there? Pls use tape diagram.

-14/5 times (-51/69)

Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly selected individual has the disease. Suppose n individuals are independently selected for testing. One way to proceed is to carry out a separate test on each of the n blood samples. A potentially more economical approach, group testing, was introduced during World War II to identify syphilitic men among army inductees. First, take a part of each blood sample, combine these specimens, and carry out a single test. If no one has the disease, the result will be negative, and only the one test is required. If at least one individual is diseased, the test on the combined sample will yield a positive result, in which case the n individual tests are then carried out. [The article "Random Multiple-Access Communication and Group Testing"† applied these ideas to a communication system in which the dichotomy was active/idle user rather than diseased/nondiseased.] If p = 0.15 and n = 5, what is the expected number of tests using this procedure? (Round your answer to three decimal places.)

Consider the diagram and the proof below.Given: In △ABC, AD ⊥ BCProve: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFractionTriangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.What is the missing statement in Step 6?b = cStartFraction h Over b EndFraction = StartFraction h Over c EndFractioncsin(B) = bsin(C)bsin(B) = csin(C)

NEEd help quickly please!!! The basketball game had 500 people in attendance. If the ratio of Pioneer fans to Lion fans is 15:5, how many MORE Pioneer fans were there? Pls use tape diagram.

How many apples are there in the bowl? Show your work!

**Answer:**

6 apples

**Step-by-step explanation:**

3+2+1 = 6 and 6 × 2 is 12 therefore half of the fruit is 6 so six apples (if that makes sense HAHA)

Mskskdkskekekdbsn nkfjrjrmrnrrr

B t= 0.4G

C g=2.5t

D t=2.5g

E g= 2/5 t

The **correct **options are (A), (D) and (E).

A **linear equation **in two **variable **has the **general form** as y = ax + by + c, where a, b and c are integers and a, b ≠ 0.

It can be represented as a **straight line** on a **graph**.

Given that,

The** time taken **to fill 2 gallon **bucket **is 5 seconds.

Suppose the number of **gallons **be g.

And, the **time **in seconds is t.

The given options are **considered **one by one for the given **case **as,

(A) g = 0.4 t

Substitute g = 2 and t =5 in the above **expression** to get,

LHS = 2

RHS = 0.4 × 5

= 2

Since LHS = RHS, the given option **represent** the proportional **relationship**.

(B) t= 0.4g

Substitute g = 2 and t =5 in the above expression to get,

LHS = 5

RHS = 0.4 × 2

= 0.8

Since LHS ≠ RHS, the given option does not represent the proportional relationship.

(C) g=2.5t

Substitute g = 2 and t =5 in the above expression to get,

LHS = 2

RHS = 2.5 × 5

= 12.5

Since LHS ≠ RHS, the given option does not represent the proportional relationship.

(D) t = 2.5g

Substitute g = 2 and t =5 in the above expression to get,

LHS = 5

RHS = 2.5 × 2

= 5

Since LHS = RHS, the given option represents the proportional relationship.

(E) g= 2/5 t

Substitute g = 2 and t =5 in the above expression to get,

LHS = 2

RHS = 2/5 × 5

= 2

Since LHS = RHS, the given option represents the proportional relationship.

Hence, the correct **relationship **is **represented **by options (A), (D) and (E).

To know more about** linear equation** click on,

#SPJ5

**Answer:**

**I beleive it should be **

A. g = 0.4t

And

D. t = 2.5g

Sorry if i'm wrong though! Let me know if is correct!

**Answer: It's 22.85 East**

**Step-by-step explanation:**

Took the test and got a 100%

**Answer: **22.85

Step-by-step explanation:

if she starts out 8.5 mile WEST of a zoo, and has to go 14.35 miles EAST of the zoo, then add both of those numbers, and you get, 22.85 miles

**Answer:**

11

**Step-by-step explanation:**

**Answer:**

99.065% probability that at least two of the three will be available at any given time.

**Step-by-step explanation:**

**We have these following probabilities:**

99% probability of the first workstation being available

95% probability of the second workstation being available

85% probability of the third workstation being avaiable

**Two being available:**

**We can have three outcomes**

First and second available, third not. So

0.99*0.95*0.15 = 0.141075

First and third available, second not. So

0.99*0.05*0.85 = 0.042075

Second and third available, first not. So

0.01*0.95*0.85 = 0.008075

**Adding them all**

P(2) = 0.141075 + 0.042075 + 0.008075 = 0.191225

**Three being available:**

P(3) = 0.99*0.95*0.85 = 0.799425

**What is the probability that at least two of the three will be available at any given time?**

P = P(2) + P(3) = 0.191225 + 0.799425 = 0.99065

99.065% probability that at least two of the three will be available at any given time.

The probability that at least two out of the three workstations are available is **0.967.**

We can find the probability that at least two out of the three workstations are available using the concept of complementary events. The probability of at least two workstations being available is equal to 1 minus the probability of none or only one workstation being available.

Let's calculate the probability of none or only one workstation being available:

Probability of none being available: 0.01 * 0.05 * 0.15 = 0.00075

Probability of only one being available: (0.99 * 0.05 * 0.15) + (0.01 * 0.95 * 0.15) + (0.01 * 0.05 * 0.85) = 0.03225

Now, subtracting this from 1:

1 - (0.00075 + 0.03225) = 0.967

Therefore, the probability that at least two out of the three workstations are available at any given time is **0.967.**

#SPJ3

**Answer:**

The answer is

**Step-by-step explanation:**

To find an equation of a line in point slope form when given the slope and a point we use the formula

where

m is the slope

( x1 , y1) is the point

From the question we have the final answer as

Hope this helps you