Answer:

Answer:

a.) Speed V = 29.3 m/s

b.) K.E = 1931.6 J

Explanation: Please find the attached files for the solution

Answer:
### Final answer:

### Explanation:

### Learn more about Conservation of Energy and Rotational Motion here:

The wheel's speed at the bottom of the hill can be found through the conservation of energy equation considering both translational and **rotational kinetic energy, **while the total kinetic energy at the bottom of the hill is a sum of translational and rotational kinetic energy.

These two questions address the physics concepts of conservation of energy, kinetic energy, and rotational motion. To answer the first question, (a) How fast is the wheel moving when it reaches the bottom of the hill if it rolled without slipping all the way down?, we need to consider the potential energy the wheel has at the top of the hill is completely converted into kinetic energy at the bottom. This includes both translational and rotational kinetic energy. Solving for the final velocity, vf, which would be the speed of the wheel, we get **vf = sqrt((2*g*h)/(1+I/(m*r^2))), **where g is the acceleration due to gravity, h is the height of the hill, I is the moment of inertia of the wheel, m is the mass of the wheel, and r is the radius of the wheel.

For the second question, (b) How much total kinetic energy does it have when it reaches bottom of the hill?, we use the formula for total kinetic energy at the bottom of the hill,** K= 0.5*m*v^2+0.5*I*(v/r)^2. **Substituting the value of v found in the first part we find the kinetic energy which we can use the formula provided in the reference information.

#SPJ11

What problem did Katherine face in checking other people’s calculations in the movie ¨Hidden figures¨

The spring is used in a spring gun to project a 10.0 g plastic ball. In the gun, the spring is compressed by 10.0 cm before the gun is fired. How fast is the ball traveling after the gun is fired?

Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the bow back 50 cm and holds it in position with a force of 150N . If the mass of the arrow is 50g and the "spring" is massless, what is the speed of the arrow immediately after it leaves the bow?

What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.

Inductance is usually denoted by L and is measured in SI units of henries (also written henrys, and abbreviated H), named after Joseph Henry, a contemporary of Michael Faraday. The EMF E produced in a coil with inductance L is, according to Faraday's law, given byE=−LΔIΔt.Here ΔI/Δt characterizes the rate at which the current I through the inductor is changing with time t.Based on the equation given in the introduction, what are the units of inductance L in terms of the units of E, t, and I (respectively volts V, seconds s, and amperes A)?What EMF is produced if a waffle iron that draws 2.5 amperes and has an inductance of 560 millihenries is suddenly unplugged, so the current drops to essentially zero in 0.015 seconds?

The spring is used in a spring gun to project a 10.0 g plastic ball. In the gun, the spring is compressed by 10.0 cm before the gun is fired. How fast is the ball traveling after the gun is fired?

Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the bow back 50 cm and holds it in position with a force of 150N . If the mass of the arrow is 50g and the "spring" is massless, what is the speed of the arrow immediately after it leaves the bow?

What is the density of the paint if the mass of a tin containing 5000 cm3 paint is 7 kg. If the mass of the empty tin, including the lid is 0.5 kg.

Inductance is usually denoted by L and is measured in SI units of henries (also written henrys, and abbreviated H), named after Joseph Henry, a contemporary of Michael Faraday. The EMF E produced in a coil with inductance L is, according to Faraday's law, given byE=−LΔIΔt.Here ΔI/Δt characterizes the rate at which the current I through the inductor is changing with time t.Based on the equation given in the introduction, what are the units of inductance L in terms of the units of E, t, and I (respectively volts V, seconds s, and amperes A)?What EMF is produced if a waffle iron that draws 2.5 amperes and has an inductance of 560 millihenries is suddenly unplugged, so the current drops to essentially zero in 0.015 seconds?

**Answer:**

16 cm

**Explanation:**

For protons:

Energy, E = 300 keV

radius of orbit, r1 = 16 cm

the relation for the energy and velocity is given by

So, .... (1)

Now,

Substitute the value of v from equation (1), we get

Let the radius of the alpha particle is r2.

For proton

So, ... (2)

Where, m1 is the mass of proton, q1 is the charge of proton

For alpha particle

So, ... (3)

Where, m2 is the mass of alpha particle, q2 is the charge of alpha particle

Divide equation (2) by equation (3), we get

q1 = q

q2 = 2q

m1 = m

m2 = 4m

By substituting the values

So, r2 = r1 = 16 cm

Thus, the radius of the alpha particle is 16 cm.

**Answer:15.95 cm**

**Explanation:**

Given

Energy=300 kev

radius of Proton=16 cm

mass of alpha particle

mass of proton

charge on alpha particle is twice of proton

radius of Proton is given by

and Kinetic energy

where P=momentum

---1

Radius for Alpha particle is

-----2

Divide 1 & 2 we get

**Answer:**

11.87m/s

**Explanation:**

To solve this problem it is necessary to apply the concepts related to frictional force and centripetal force.

The frictional force of an object is given by the equation

Where,

Friction Coefficient

N = Normal Force, given also as mass for acceleration gravity

In the other hand we have that centripetal force is given by,

The force experienced to stay on the road through friction is equal to that of the centripetal force, therefore

Re-arrange to find the velocity,

Therefore the speed that it is necessaty to slow down the car in order to make the curve without sliding is 11.87m/s

**Given that,**

Power = 60 W

Distance = 1.0 m

Distance between speakers = 1.5 m

**We need to calculate the intensity**

**Using formula of intensity**

Put the value into the formula

**We need to calculate the intensity**

**Using formula of intensity**

Put the value into the formula

**We need to calculate the intensity of the sound waves produced by four speakers**

**Using formula for intensity**

Put the value into the formula

**Hence, The intensity of the sound waves produced by four speakers is 13.78 W/m².**

(B) If the acceleration of object moving along a line is always 0, then its velocity is constant.

(C) It is impossible for the instantaneous velocity at all times a(D) A moving object can have negative acceleration and increasing speed.

Answer:

Explanation:(A)if a body is accelerating then it's velocity can't be constant since an object is said to be accelerating if it is changing velocity (B)if the acceleration of an object moving along a line is 0 then it's velocity will be constant since there is no change in direction or speed(C)No.it is not possible for a moving body to have an instantaneous velocity at all times since instantaneous velocity is the velocity of a body at a certain instant of time..(D)Yes a moving object can have a negative acceleration and increasing speed,it can also have a positive acceleration with decreasing speed.

**Answer:**

What displacement must the physics professor give the car

=** 12.91 METERS**

**Explanation:**

Check the attached file for explanation

As we know that current is defined as rate of flow of charge

so by rearranging the equation we can say

here we know that

here we will substitute it in the above equation

now here limits of time is from t = 0 to t = 1/180s

so here it will be given as

so total charge flow will be 0.44 C

**Answer:**

The total charge passing a given point in the conductor is 0.438 C.

**Explanation:**

**Given that,**

**The expression of current is**

....(I)

**We need to calculate the total charge**

**On integrating both side of equation (I)**

**Hence, The total charge passing a given point in the conductor is 0.438 C.**