A 2500 kg car traveling to the north is slowed down uniformly from an initial velocity of 27.0 m/s by a 7850 N braking force acting opposite the car’s motion. What is the car's velocity after 2.52s?
How far does the car move during the 2.52 s?
How long does it take the car to come to a complete stop?

Answers

Answer 1
Answer:

Answer:

19.1 m/s

58.1 m

8.60 s

Explanation:

Take north to be positive and south to be negative.

Use Newton's second law to find the acceleration.

∑F = ma

-7850 N = (2500 kg) a

a = -3.14 m/s²

Given:

v₀ = 27.0 m/s

a = -3.14 m/s²

Find: v given t = 2.52 s

v = at + v₀

v = (-3.14 m/s²) (2.52 s) + 27.0 m/s

v = 19.1 m/s

Find: Δx given t = 2.52 s

Δx = v₀ t + ½ at²

Δx = (27.0 m/s) (2.52 s) + ½ (-3.14 m/s²) (2.52 s)²

Δx = 58.1 m

Find: t given v = 0 m/s

v = at + v₀

0 m/s = (-3.14 m/s²) t + 27.0 m/s

t = 8.60 s


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In a charging process, 4 × 1013 electrons are removed from one small metal sphere and placed on a second identical sphere. Initially, both metal spheres were neutral. After the charging process, the electrical potential energy associated with the two spheres is found to be −0.063 J. What is the distance between the two spheres?

Answers

Answer:

The distance between the two spheres is 914.41 X 10³ m

Explanation:

Given;

4 X 10¹³ electrons, and its equivalent in coulomb's is calculated as follows;

1 e = 1.602 X 10⁻¹⁹ C

4 X 10¹³ e = 4 X 10¹³ X 1.602 X 10⁻¹⁹ C = 6.408 X 10⁻⁶ C

V = Ed

where;

V is the electrical potential energy between two spheres, J

E is the electric field potential between the two spheres N/C

d is the distance between two charged bodies, m

V = (K*q)/(d^2)*d = (K*q)/(d)

d = (K*q)/(V)

where;

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

d = (8.99 X 10⁹ X 6.408 X 10⁻⁶)/0.063

d = 914.41 X 10³ m

Therefore, the distance between the two spheres is 914.41 X 10³ m

Water on Earth was (a) transported here by comets; (b) accreted from the solar nebula; (c) produced by volcanoes in the form of steam; (d) created by chemical reactions involving hydrogen and oxygen shortly after Earth formed.

Answers

Answer: Water on Earth was transported here by comets. The correct option is A.

Explanation:

Comets are made up of water with ice, rock and minerals.

Alot of research and hypotheses has been made to prove the origin of water on planet earth. Extraplanetary source such as comets, trans-Neptunian objects, and water-rich meteoroids (protoplanets) are believed to have delivered water to Earth.

Every few years, winds in Boulder, Colorado, attain sustained speeds of 45.0 m/s (about 100 mi/h) when the jet stream descends during early spring. show answer No Attempt Approximately what is the force due to the Bernoulli effect on a roof having an area of 205 m2? Typical air density in Boulder is 1.14 kg/m3 , and the corresponding atmospheric pressure is 8.89 × 104 N/m2 . (Bernoulli’s principle assumes a laminar flow. Using the principle here produces only an approximate result, because there is significant turbulence.)

Answers

Answer:

The force exerted on the roof is F =2.37*10^(5)N

Explanation:

From the question we are told that

      The speed of the wind is v = 45.0 m/s

       The area of the roof is A = 205 m^2

       The air density of Boulder is \rho = 1.14 kg / m^3

        The atmospheric pressure is P_(atm) = 8.89 * 10^(4) N/ m^2

For a laminar flow the Bernoulli’s principle is  mathematically represented as

            P_1 + (1)/(2) \rho v_a ^2 + \rho g h_a = P_2 + (1)/(2)  \rho v_b ^2 + \rho h_b

Where  v_1 is the  speed of air in  the building

             v_b is the speed of air outside the building

             P_1 \ and \ P_2 are the pressure of inside and outside the house

             h_a \ and \ h_b are the height above and  below the roof

Now for  h_a = h_b

            The above equation becomes

                 P_1 + (1)/(2) \rho v_a ^2 = P_2 + (1)/(2) \rho v_b ^2

                 P_1 - P_2 = (1)/(2) \rho (v_b^2 - v_a^2)

Since pressure is mathematically represented as

           P = (F)/(A )

The above equation can be written as

             F  = (1)/(2) \rho ( v_b^2 - v_a ^2 ) A

The initial velocity is 0

    Substituting value  

                F = (1)/(2)  (1.14) [(45^2 - 0^2 ) ](205)

                F =2.37*10^(5)N

                 

Instantaneous speed is...a) A speed of 1000 km/h
b) The speed attained at a particular instant in time.
c) The speed that can be reached in a particular amount of time.

PLEASE HURRY

Answers

Answer:

The speed attained at a particular instant in time.

Explanation:

Instantaneous speed is the speed attained at a particular instant in time.

It is given by :

v=(dx)/(dt)

It is equal to the rate of change of speed.

It can be also defined as when the speed of an object is constantly changing, the instantaneous speed is the speed of an object at a particular moment (instant) in time.

Hence, the correct option is (b).

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Earth revolving around the Sun
OB.
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OC.
a ball falling downward a few seconds after being thrown upward
OD. electrically charged hairs on your head repelling each other and standing up

Answers

Answer:

A bridge suspended by cables

Explanation:

Both objects represent a contact force (in this case, normal force) acting on each other. The force occurs since both objects are in direct physical contact.

Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

Answers

Answer:

Consider a proton travelling due west at a velocity of 5×10^5m/s. Assuming that the rth magnetic field has a strength of 5x10^-5Tand is directed due south calculate li) the magnitude of the force on the proton (q= 1.6x10^-9C)​

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