The radius of the large sphere is double the radius of thesmall sphere.
How many times is the volume of the large sphere than the
small sphere?
2
VX
O 4
O 6
O 8

Answers

Answer 1
Answer:

Answer:

4 times as great

Step-by-step explanation:

Compute the two different volumes and then compare them.

Smaller sphere:  V = (4/3) · π ·r²

Larger sphere:  V = (4/3) · π · (2r)²     = (4/3) · π · 4 · r²

Comparing these, one sees immediately that the volume of the larger sphere is 4 times as great as that of the smaller sphere.


Related Questions

Multiply (4x-3w)(5x-7w)
Ana and Ling are solving |3x + 14| = -6x.Is either of them correct?...............................Explain your reasoning.
If two systems of linear equations have the same solution set (in other words, the two systems are equivalent), then they must have the same number of equations. a. Trueb. False
I'm having trouble with finding the solutions.
Question is in Screenshot/Attachment! Hurry pls.

 any help would be great

Answers

Answer:

k = P - m - n

Step-by-step explanation:

The question is asking you to rearrange the equation so that k is alone on one side.

P = k + m + n

P - k = (k + m + n) - k

P - k = m + n

(P - k) - P = m + n - P

-k = m + n - P

-1(-k) = -1 (m + n - P)

k = -m - n + P

The equation is completely simplified so this is your answer.

There are​ 15,958,866 adults in a region. If a polling organization randomly selects 1235 adults without​ replacement, are the selections independent or​ dependent? If the selections are​ dependent, can they be treated as independent for the purposes of​ calculations? Are the selections independent or​ dependent?

Answers

Answer:

The selections are dependent.

Yes, they can be treated as independent (less than 5% of the population).

Step-by-step explanation:

Since the selections are made without replacement, each selection affects the outcome of the next selection and, therefore, the selections are dependent.

Although they are dependent, the selections can be treated as independent if the sample size is no more than 5% of the total population. In this case, the sample size is 1235 adults out of a population of 15,958,866 adults. The percentage represented by the sample is:

P=(12,345)/(15,958.866)*100\n P=0.077\%

Thus the selections can be treated as independent for the purposes of calculations.

The number of telephone calls that arrive at a phone exchange is often modeled as a Poisson random variable. Assume that on the average there are 10 calls per hour. (a) What is the probability that there are three or fewer calls in one hour

Answers

Answer: the probability that there are three or fewer calls in one hour is 0.011

Step-by-step explanation:

The formula for poisson distribution is expressed as

P(x = r) = (e^- µ × µ^r)/r!

Where

µ represents the mean of the theoretical distribution.

r represents the number of successes of the event.

From the information given,

µ = 10

For the probability that there are three or fewer calls in one hour, it is expressed as

P(x ≤ 3) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3)

Therefore,

P(x = 0) = (e^- 10 × 10^0)/0! = 0.000045

P(x = 1) = (e^- 10 × 10^1)/1! = 0.00045

P(x = 2) = (e^- 10 × 10^2)/2! = 0.0023

P(x = 3) = (e^- 10 × 10^3)/3! = 0.0077

Therefore,

P(x ≤ 3) = 0.000045 + 0.00045 + 0.0023 + 0.0077 = 0.011

I keep getting the same answer and I know I am using the right formula. don't know where I am going wrong.

Answers

From March 10 to May 12 = 63 days.

63 days / 365 days = 0.1726 years.


Simple interest formula = Interest = Principal X interest rate x time


Interest = 15305.50 - 15000 = 305.50

Principal = 15000

Time = 0.1726 years


Replace the values into the formula:

305.50 = 15000 x Interest rate x 0.1726

Simplify:

305.50 = 2589.041 x interest rate

Solve for interest rate:

interest rate = 305.50 / 2589.041

interest rate = 0.11799 x 100

Rate = 11.80%


) At a certain college, students are allowed to choose between online and in-person learning. 70% of the students choose online learning and 30% choose to come to campus for in-person instruction. Assume that the probability that a person studying online will contract the coronavirus is .02 and the probability that a person attending class in-person contracts the virus is .35 . (a) What is the probability that a person attending this college (either online or in-person) will contract the virus

Answers

Answer:

Probability = 0.119

Step-by-step explanation:

P (Coronavirus) = P(Person online & corona) or P(Person offline & corona)

(0.70 x 0.02) + (0.30 x 0.35)

0.014 + 0.105

0.119

The LA dodgers hit the most home runs in 2014. The number of Home runs accounted for 6% of the entire major league baseball home run count. if the dodgers hit 35 home runs, then how many did the rest of the league hit?

Answers

Answer:

To answer the question, we will need to find the 6% (the home runs of the LA Dodgers) of 583 (the entire Major League Baseball home run count).

To do that, first we are going to divide 6% by 100% to convert it to a fraction and get rid of the percentage signs :

Now we can multiply our fraction by the entire Major League Baseball home run count to get the home runs of the Dodgers:

We can conclude that the LA Dodgers hit approximately 35 home runs.

Step-by-step explanation:

Yeet

Final answer:

The rest of the league hit approximately 583 home runs.

Explanation:

In order to determine the number of home runs hit by the rest of the league, we need to set up a proportion using the given information. Let 'x' represent the number of home runs hit by the rest of the league. We can set up the proportion as follows:



35/​x = 6/100



Cross-multiplying, we get 100 * 35 = 6 * ​x.



Simplifying, we have 3500 = 6 * ​x. Dividing both sides by 6, we find that x = 583.33. Rounding to the nearest whole number, the rest of the league hit approximately 583 home runs.

Learn more about proportion here:

brainly.com/question/34018947

#SPJ12