How many times is the volume of the large sphere than the

small sphere?

2

VX

O 4

O 6

O 8

Answer:

**Answer:**

4 times as great

**Step-by-step explanation:**

Compute the two different volumes and then compare them.

Smaller sphere: V = (4/3) · π ·r²

Larger sphere: V = (4/3) · π · (2r)² = (4/3) · π · 4 · r²

Comparing these, one sees immediately that the volume of the larger sphere is **4 times as great** as that of the smaller sphere.

Multiply (4x-3w)(5x-7w)

Ana and Ling are solving |3x + 14| = -6x.Is either of them correct?...............................Explain your reasoning.

If two systems of linear equations have the same solution set (in other words, the two systems are equivalent), then they must have the same number of equations. a. Trueb. False

I'm having trouble with finding the solutions.

Question is in Screenshot/Attachment! Hurry pls.

Ana and Ling are solving |3x + 14| = -6x.Is either of them correct?...............................Explain your reasoning.

If two systems of linear equations have the same solution set (in other words, the two systems are equivalent), then they must have the same number of equations. a. Trueb. False

I'm having trouble with finding the solutions.

Question is in Screenshot/Attachment! Hurry pls.

**Answer:**

k = P - m - n

**Step-by-step explanation:**

The question is asking you to rearrange the equation so that k is alone on one side.

P = k + m + n

P - k = (k + m + n) - k

P - k = m + n

(P - k) - P = m + n - P

-k = m + n - P

-1(-k) = -1 (m + n - P)

k = -m - n + P

The equation is completely simplified so this is your answer.

**Answer:**

The selections are dependent.

Yes, they can be treated as independent (less than 5% of the population).

**Step-by-step explanation:**

Since the selections are made without replacement, each selection affects the outcome of the next selection and, therefore,** the selections are dependent.**

Although they are dependent, the selections can be treated as independent if the sample size is no more than 5% of the total population. In this case, the sample size is 1235 adults out of a population of 15,958,866 adults. The percentage represented by the sample is:

Thus **the selections can be treated as independent for the purposes of calculations.**

Answer: the probability that there are three or fewer calls in one hour is 0.011

Step-by-step explanation:

The formula for poisson distribution is expressed as

P(x = r) = (e^- µ × µ^r)/r!

Where

µ represents the mean of the theoretical distribution.

r represents the number of successes of the event.

From the information given,

µ = 10

For the probability that there are three or fewer calls in one hour, it is expressed as

P(x ≤ 3) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3)

Therefore,

P(x = 0) = (e^- 10 × 10^0)/0! = 0.000045

P(x = 1) = (e^- 10 × 10^1)/1! = 0.00045

P(x = 2) = (e^- 10 × 10^2)/2! = 0.0023

P(x = 3) = (e^- 10 × 10^3)/3! = 0.0077

Therefore,

P(x ≤ 3) = 0.000045 + 0.00045 + 0.0023 + 0.0077 = 0.011

From March 10 to May 12 = 63 days.

63 days / 365 days = 0.1726 years.

Simple interest formula = Interest = Principal X interest rate x time

Interest = 15305.50 - 15000 = 305.50

Principal = 15000

Time = 0.1726 years

Replace the values into the formula:

305.50 = 15000 x Interest rate x 0.1726

Simplify:

305.50 = 2589.041 x interest rate

Solve for interest rate:

interest rate = 305.50 / 2589.041

interest rate = 0.11799 x 100

Rate = 11.80%

**Answer:**

Probability = 0.119

**Step-by-step explanation:**

P (Coronavirus) = P(Person online & corona) or P(Person offline & corona)

(0.70 x 0.02) + (0.30 x 0.35)

0.014 + 0.105

0.119

**Answer:**

To answer the question, we will need to find the 6% (the home runs of the LA Dodgers) of 583 (the entire Major League Baseball home run count).

To do that, first we are going to divide 6% by 100% to convert it to a fraction and get rid of the percentage signs :

Now we can multiply our fraction by the entire Major League Baseball home run count to get the home runs of the Dodgers:

We can conclude that the LA Dodgers hit approximately 35 home runs.

**Step-by-step explanation:**

Yeet

The rest of the **league** hit approximately 583 home runs.

In order to determine the number of home runs hit by the rest of the league, we need to set up a **proportion **using the given information. Let 'x' represent the number of home runs hit by the rest of the league. We can set up the proportion as follows:

35/x = 6/100

Cross-multiplying, we get 100 * 35 = 6 * x.

Simplifying, we have 3500 = 6 * x. Dividing both sides by 6, we find that x = 583.33. Rounding to the nearest whole number, the rest of the league hit approximately 583 home runs.

#SPJ12