Consider the following analogy: You are a hiring manager for a large company. For every job applicant, you must decide whether to hire the applicant based on your assessment of whether he or she will be an asset to the company. Suppose your null hypothesis is that the applicant will not be an asset to the company. As in hypothesis testing, there are four possible outcomes of your decision: (1) You do not hire the applicant when the applicant will not be an asset to the company, (2) you hire the applicant when the applicant will not be an asset to the company, (3) you do not hire the applicant when the applicant will be an asset to the company, and (4) you hire the applicant when the applicant will be an asset to the company. 1. Which of the following outcomes corresponds to a Type I error?
A. You hire the applicant when the applicant will not be an asset to the company.
B. You do not hire the applicant when the applicant will be an asset to the company.
C. You do not hire the applicant when the applicant will not be an asset to the company.
D. You hire the applicant when the applicant will be an asset to the company.
2. Which of the following outcomes corresponds to a Type II error?
A. You hire the applicant when the applicant will not be an asset to the company.
B. You hire the applicant when the applicant will be an asset to the company.
C. You do not hire the applicant when the applicant will be an asset to the company.
D. You do not hire the applicant when the applicant will not be an asset to the company.
As a hiring manager, the worst error you can make is to hire the applicant when the applicant will not be an asset to the company. The probability that you make this error, in our hypothesis testing analogy, is described by:________.

Answers

Answer 1
Answer:

Answer:

1. A. You hire the applicant when the applicant will not be an asset to the company.

2. C. You do not hire the applicant when the applicant will be an asset to the company.

Step-by-step explanation:

1. The type I error happens when the null hypothesis is rejected when it is true, in this way we know that the null hypothesis is that the new employee will not be active for the company, so option B is rejected, because it refers that the Applicant if he will be active or for the company, option C is rejected because the inactive employee is rejected, accepting the null hypothesis, option D is rejected because the contracted applicant if active, so the correct answer is A, in which the inactive applicant is hired.

2.

we know that the type II error occurs when the null hypothesis is accepted, being this false, we know that the null hypothesis is to hire an inactive applicant for the company, so option A is not correct, in which the null hypothesis is accepted taking it as true, option B is rejected, in which the contract is made to an active applicant, so the null hypothesis is false and option D is rejected, in which the null hypothesis is rejected, therefore the correct answer It is the C in which the active applicant is not hired.

Answer 2
Answer:

Answer:

1. Option A

2. Option C

Step-by-step explanation:

The null hypothesis is that the applicant will not be an asset to the company, thus you do not hire such applicant

The alternative hypothesis is that the applicant will be an asset to the company and you then hire such applicant.

A type I error occurs when the researcher rejects the null hypothesis when true.

A type II error occurs when the researcher fails to reject the null hypothesis when it is not true.

1. Type I error:

You hire the applicant when the applicant will not be an asset to the company

2. Type II error:

You do not hire the applicant when the applicant will be an asset to the company.

3. Type I error because you rejected the null hypothesis to not hire when the applicant will not be an asset to the company.


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Please answer this correctly

Simplify the expression 4^4/4^6

Answers

Answer:

1/16

Step-by-step explanation:

(4^(4) )/(4^(6) )

4^(4-6)

4^(-2)

(1)/(4^(2) )

(1)/(16)

Final answer:

By using the rules of exponents, we find that 4^4/4^6simplifies to 1/4^2, which equals 1/16.

Explanation:

The expression you're looking to simplify is 4^4/4^6. In mathematics, when you divide two numbers with the same base, you subtract the exponents. To simplify this expression, subtract the exponent 6 from the exponent 4. This gives us 4^(-2), and any number raised to a negative exponent is 1 divided by the number raised to that exponent. Thus, the simplified form of the expression is 1/4^2 or 1/16.

Learn more about exponents here:

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I NEED HELP, PLEASE!!Two numbers have a distance of 6 units from 0 on a number line. The numbers can be graphed on the number line as points A and B.


Drag and drop the labels to the correct positions on the number line.

Answers

Answer:

You have to put A on -6 and b on 6.

Step-by-step explanation:

IN order to solve tis you just have to take one of the markers, lets say A and move it 6 units to the left all the way to -6, then you just have to move the B marker 6 units to the right from 0 all the way to the 6, that is how you get the two numbers that have a distanceof 6 units from 0 on the number line.

Answer:

See attached image.

Step-by-step explanation:

Start at 0 and count to the right. When you get to 6, place EITHER marker on the point. It doesn't look like it matters whether you use A or B.

Start at 0 and count to the left. When you get to 6, place the other marker on the point.

Consider the following sample data: x 10 7 20 15 18 y 22 15 19 14 15 Click here for the Excel Data File a. Calculate the covariance between the variables. (Negative value should be indicated by a minus sign. Round your intermediate calculations to at least 4 decimal places and final answer to 2 decimal place

Answers

Answer:

a. Covariance between x and y = – 1.25

b. Correlation coefficient = – 0.07

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Consider the following sample data:

x 10 7 20 15 18

y 22 15 19 14 15

Required:

a. Calculate the covariance between the variables. (Negative value should be indicated by a minus sign. Round your intermediate calculations to at least 4 decimal places and final answer to 2 decimal place.

b. Calculate the correlation coefficient (Round your intermediate calculations to at least 4 decimal places and final answer to 2 decimal place.)

The explanation to the answer is now given as follows:

Note: See the attached excel file for the calculations of the sum of x and y, means of x and y, deviations of x and y, multiplications of deviations of x and y, and others.

a. Calculate the covariance between the variables. (Negative value should be indicated by a minus sign. Round your intermediate calculations to at least 4 decimal places and final answer to 2 decimal place.)

In the attached excel file, we have:

N = Number of observations = 5

Mean of x = Sum of x / N = 70 / 5 = 14

Mean of y = Sum of y / N = 85 / 5 = 17

x - Mean of x = Deviations of x = see the attached excel file for the answer of each observation

y - Mean of y = Deviations of y = see the attached excel file for the answer of each observation

Multiplications of the deviations of x and y = (x - Mean of x) * (y - Mean of y) = see the attached excel file for the answer of each observation

Sum of the multiplications of deviations of x and y = Sum of ((x - Mean of x) * (y - Mean of y)) = –5

Since we are using a sample, we use (N – 1) in our covariance between x and y as follows:

Covariance between x and y = Sum of ((x - Mean of x) * (y - Mean of y)) / (N – 1) = –5 / (5 – 1) = –5 / 4 = –1.25

b. Calculate the correlation coefficient (Round your intermediate calculations to at least 4 decimal places and final answer to 2 decimal place.)

The correlation coefficient can be calculated using the following formula:

Correlation coefficient = Covariance between x and y / (Sum of (x - Mean of x)^2 * Sum of  (y - Mean of y)^2)^0.5 ………………… (1)

Where, from the attached excel file;

Covariance between x and y = –5

Sum of (x - Mean of x)^2 = 118

Sum of (y - Mean of y)^2 = 46

Substituting the values into equation (1), we have:

Correlation coefficient = –5 / (118 * 46)^0.5 = –5 / 5,428^0.5 = –5 / 73.6750 = – 0.07

Final answer:

The covariance between two variables can be calculated by first finding the mean of each dataset, subtracting the mean from each data point, multiplying the results for each pair of coordinates, summing these products to obtain the numerator. The denominator is obtained by subtracting one from the number of data points. The covariance is then the numerator divided by the denominator.

Explanation:

The term covariance is one of the key factors for understanding correlation between two variables. To calculate the covariance between the two given variables, we first need to calculate the mean of each set (x and y). After we've gotten the mean, we subtract the mean from each data point and multiply the results for each pair of x and y values. Summing these products will give us the numerator in the covariance calculation. The denominator is calculated by subtracting one from the total number of data points we have (n-1). So, the covariance is the sum we got from the numerator, divided by the denominator. Please don't forget to indicate if the covariance is negative, using a minus sign.

Learn more about Covariance here:

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Delete my son's account and stop billing me

Answers

Answer:

oop

Step-by-step explanation:

Twice the area of a square is 72 square miles. What is the length of each side of the square?

Answers

Answer:

6 miles

Step-by-step explanation:

Let's say the length of the sides of the square is x.

The area of a square is denoted by: A = x².

Here, we're given that twice the area of the square is 72, so we can write this is 2 times the area, which is 2 * x². Set this equal to 72 and solve:

2x² = 72

x² = 36

x = 6

Thus the answer is 6 miles.

Answer:

6 miles

Step-by-step explanation:

2A = 72

A = 72/2

A = 36

Area = s²

36 = s²

s = 6 miles

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. Historical data indicates that 20% of all potential purchasers select a day visit, 50% choose a one-night visit, and 30% opt for a two-night visit. In addition, 10% of day visitors ultimately make a purchase, 30% of onenight visitors buy a unit, and 20% of those visiting for two nights decide to buy. Suppose a visitor is randomly selected and is found to have made a purchase. How likely is it that this person made a day visit? A one-night visit? A two-night visit?

Answers

Answer:

0.087 = 8.7% probability that this person made a day visit.

0.652 = 65.2% probability that this person made a one-night visit.

0.261 = 26.1% probability that this person made a two-night visit.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = (P(A \cap B))/(P(A))

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Made a purchase.

Probability of making a purchase:

10% of 20%(day visit)

30% of 50%(one night)

20% of 30%(two night).

So

p = 0.1*0.2 + 0.3*0.5 + 0.2*0.3 = 0.23

How likely is it that this person made a day visit?

Here event B is a day visit.

10% of 20% is the percentage of purchases and day visit. So

P(A \cap B) = 0.1*0.2 = 0.02

So

P(B|A) = (P(A \cap B))/(P(A)) = (0.02)/(0.23) = 0.087

0.087 = 8.7% probability that this person made a day visit.

A one-night visit?

Event B is a one night visit.

The percentage of both(one night visit and purchase) is 30% of 50%. So

P(A \cap B) = 0.3*0.5 = 0.15

So

P(B|A) = (P(A \cap B))/(P(A)) = (0.15)/(0.23) = 0.652

0.652 = 65.2% probability that this person made a one-night visit.

A two-night visit?

Event B is a two night visit.

The percentage of both(two night visit and purchase) is 20% of 30%. So

P(A \cap B) = 0.2*0.3 = 0.06

Then

P(B|A) = (P(A \cap B))/(P(A)) = (0.06)/(0.23) = 0.261

0.261 = 26.1% probability that this person made a two-night visit.