# What is the square root of 1350÷600

Step-by-step explanation:

1350÷600

=2.25

√2.25=1.5

## Related Questions

Hellllllllllllllllllllllllllllllllllpppppppppppppppppppppppp whats the x

Easy buddy....

Subtract the sides of the equation minus68

Divided the sides of the equation by2

So ;

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And we're done.

Thanks for watching buddy good luck.

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Consider a home mortgage of \$250,000 at a fixed APR of 4.5% for 25 years.a. Calculate the monthly payment.
b. Determine the total amount paid over the term of the loan.
c. Of the total amount paid, what percentage is paid toward the principal and what
percentage is paid for interest.
a. The monthly payment is \$
(Do not round until the final answer. Then round to the nearest çent as needed.)

M is the monthly payment.

P is the principal loan amount (in this case, \$250,000).

r is the monthly interest rate (annual rate divided by 12). For an APR of 4.5%,

=

0.045

12

r=

12

0.045

.

n is the total number of payments (number of years multiplied by 12). For 25 years,

=

25

×

12

n=25×12.

Suzanne has purchased a car with a list price of \$23,860. She traded in her previous car, which was a Dodge in good condition, and financed the rest of the cost for five years at a rate of 11.62%, compounded monthly. The dealer gave her 85% of the listed trade-in price for her car. She was also responsible for 8.11% sales tax on the difference between the list price and trade in price, a \$1,695 vehicle registration fee, and a \$228 documentation fee. If Suzanne makes a monthly payment of \$455.96, what was the trade in price of her original car?

The trade in price of her original car was \$11,128.57.

### Prices

Given that Suzanne has purchased a car with a list price of \$23,860, and she traded in her previous car, which was a Dodge in good condition, and financed the rest of the cost for five years at a rate of 11.62%, compounded monthly, and the dealer gave her 85% of the listed trade-in price for her car, and she was also responsible for 8.11% sales tax on the difference between the list price and trade in price, a \$1,695 vehicle registration fee, and a \$228 documentation fee, if Suzanne makes a monthly payment of \$455.96, to determine what was the trade in price of her original car, the following calculation must be made:

• 455.96 x 12 x 5 = 27,357.60
• X x (1 + 0.1162/12)^(12x5) = 27,357.60
• X x 1.009683^60 = 27,357.60
• 1.7828X = 27,357.60
• X = 27,357.60 / 1.7828
• X = 15,345
• 23,860 - 15,345 + (0.0811 x (23,860 - 15,345)) + 1695 + 228 = X
• 23,860 - 15,345 + 690.57 + 1695 + 228 = X
• 11,128.57 = X

Therefore, the trade in price of her original car was \$11,128.57.

Solve the following problem:

Step-by-step explanation:

Given the Quotient Rule of Exponents:, you must subtract the exponents of each exponential expression (in fractions) before applying the Product Rule of Exponents (I will explain in a while what it means).

First, subtract the exponents of the first fraction,

Next, subtract the exponents of the second fraction:

At this point, we have the following exponential expressions: and .

Since the required operation is multiplication, then you can apply the Product Rule of Exponents:

Therefore, the correct answer is .

I believe the correct answer is 18

purchased a toyota 4Runner for \$25,635. promised your daughter the suv will be hers when the car is worth \$10,000. according to the car dealer the suv will depreciate approximately \$3,000 per year,if your daughter is currently 15 years old, how old will she be when the 4Runner will be hers.