Answer:

**Answer:**

Mean = $123

Standard deviation = 10190

Variance = 1698

**Step-by-step explanation:**

Mean=?

= sum of all numbers/ Total numbers

a = 93+173+107+125+56+163+144 / 7 = 861/7 = $123

Standard deviation=?

we know that = Sqareroot [ Sum (y)²] / N

we need deviation:

= x-a = y ; y²

= 93-123 = -30 ; 900

=173-123 = 50 ; 2500

=107-123 = -16 ; 256

=125-123 = 2 ; 4

=56-123 = -67 ; 4489

=163-123 = 40 ; 1600

__ =144-123 = 21 ; 441__

Sum of y² = 10190.

= Square root [ 10190 / 7 ]

= 38.1

Variance = ?

= Sum ( y)² / N-1

= 10190 / ( 7-1)

= 10190 /6

= 1698

PLEASE ANSWER!!!!!!!! Which system of equations does this graph represent? Linear graph and parabola. They intersect at 2, negative 1 and negative 3, 4 (1 point) A. y = x2 − 5 y = −x + 1 B. y = x2 − 5 y = −x − 1 C. y = x2 + 5 y = −x + 1 D. y = x2 + 5 y = −x − 1

A math student has a plan to solve the following system by the elimination method. to eliminate the x-term , he wants to multiply the top equation by 7. what should he multiply the second equation by so that when he adds the equation, the x-term are eliminated ? -3x-7y=-56-7x+10y=-1

Simplify by expressing fractional exponents instead of radicals.

Which of the following algebraic expressions cannot represent the phrase half of a number x

Question: What is 32^2?

A math student has a plan to solve the following system by the elimination method. to eliminate the x-term , he wants to multiply the top equation by 7. what should he multiply the second equation by so that when he adds the equation, the x-term are eliminated ? -3x-7y=-56-7x+10y=-1

Simplify by expressing fractional exponents instead of radicals.

Which of the following algebraic expressions cannot represent the phrase half of a number x

Question: What is 32^2?

Answer: Mass of Lamina is (K/3)

Centre of mass is (3/8, 3pi/16)

Step-by-step explanation:

Find explanation in the attachments

**Answer:**

**account balance at graduation is 674.17**

**Step-by-step explanation:**

**given data **

deposit money P = 500

interest rate = 3 % compounded quarterly

we take time period = 10 year ( 2nd grade to 12 grade)

**solution**

we apply here compound interest formula that is

amount = ..................1

put here value and we get

amount =

amount = 674.174

**so account balance at graduation is 674.17**

**Answer:**

$694.63

**Step-by-step explanation:**

The formula is p(1+r/n)^tn. P, or the principal amount, is 500 dollars. R, or the rate as a decimal, is 0.03. N, or the number of times compounded yearly, is 4. T, or the time in years, is 11, since there are 11 years from grade 2 to grade 12. 12-2+1=11. Now, plug in the information given. 500(1+0.03/4)^4*11 = 500(1.0075)^44 = 694.63 dollars, rounded to the nearest cent.

3X+4Y+5X-2y+10-8

**Answer:**

**Step-by-step explanation:**

8x+2y-2

**Answer:**

x>11

**Step-by-step explanation:**

x needs to be alone so subtract 16 on both sides, making the equation -8x > -88, next simply make x positive amd alone by dividing -8 on both sides, ending in the result of × > 11

Could someone tell me how to solve this?

because both lines are parallel, if you add the 5x+5 to the 115 those would equal 180 degrees

so you have 5x+5 + 115 = 180

combine like terms:

5x + 120 = 180

subtract 120 from both sides

5x = 60

x = 60/5

x = 12

so you have 5x+5 + 115 = 180

combine like terms:

5x + 120 = 180

subtract 120 from both sides

5x = 60

x = 60/5

x = 12

Okay so (5x+5)+115 is going to equal 180.

1.) (5x+5)+115=180

The next steps is to isolate the x.

2.) 5x+120=180

3.) -120=-120

4.) 5x=60

5.) /5=/5

6.) x=12 degrees

Then, you check your work by plugging in the numbers.

7.) 5(12)+5+115=180

8.) 60+5+115=180

9.)180=180

1.) (5x+5)+115=180

The next steps is to isolate the x.

2.) 5x+120=180

3.) -120=-120

4.) 5x=60

5.) /5=/5

6.) x=12 degrees

Then, you check your work by plugging in the numbers.

7.) 5(12)+5+115=180

8.) 60+5+115=180

9.)180=180

Find f(g(x))

**Answer:**

The expression will be 3(2^x) + 5

**Step-by-step explanation:**

In order to find the new expression, you have to let g(x) be the x :