Why or why not the following materials will make good candidates for the construction of a) Turbine blade for a jet turbine and
b) Thermal barrier coating. Cement, aluminum, engineering ceramic, super alloy, steel and glass

Answers

Answer 1
Answer:

Answer:

Answer explained below

Explanation:

3.] a] A turbine blade is the individual component which makes up the turbine section of a gas turbine. The blades are responsible for extracting energy from the high temperature, high pressure gas produced by the combustor.

The turbine blades are often the limiting component of gas turbines. To survive in this difficult environment, turbine blades often use exotic materials like superalloys and many different methods of cooling, such as internal air channels, boundary layer cooling, and thermal barrier coatings. The blade fatigue failure is one of the major source of outages in any steam turbines and gas turbines which is due to high dynamic stresses caused by blade vibration and resonance within the operating range of machinery.

To protect blades from these high dynamic stresses, friction dampers are used.

b] Thermal barrier coatings (TBC) are highly advanced materials systems usually applied to metallic surfaces, such as on gas turbine or aero-engine parts, operating at elevated temperatures, as a form ofexhaust heat management.

These 100μm to 2mm coatings serve to insulate components from large and prolonged heat loads by utilizing thermally insulating materials which can sustain an appreciable temperature difference between the load-bearing alloys and the coating surface.

In doing so, these coatings can allow for higher operating temperatures while limiting the thermal exposure of structural components, extending part life by reducing oxidation and thermal fatigue.

In conjunction with active film cooling, TBCs permit working fluid temperatures higher than the melting point of the metal airfoil in some turbine applications.

Due to increasing demand for higher engine operation (efficiency increases at higher temperatures), better durability/lifetime, and thinner coatings to reduce parasitic weight for rotating/moving components, there is great motivation to develop new and advanced TBCs.


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Karen just checked her bank balance and the balance was 1111.11. She is kind of freaking out and saved the receipt, thinking that it must mean something. Karen is probably just suffering from

Answers

Answer:

chronic stoner syndrome

Explanation:

"the universe just sends us messages sometimes mannnn, you just have to be ready to listen to them" lol

What is the answer What two totally normal things become really weird if you do them back to back?

Answers

Answer: i like the way you scream

In this type of projection, the angles between the three axes are different:- A) Isometric B) Axonometric C) Trimetric D) Dimetnic

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Answer:

The correct answer is C) Trimetric

Explanation:

The most suitable answer is a trimetric projection because, in this type of projection, we see that the projection of the three angles between the axes are not equal. Therefore, to generate a trimetric projection of an object, it is necessary to have three separate scales.

The sports car has a weight of 4500-lb and a center of gravity at G. If it starts from rest it causes the rear wheels to slip as it accelerates. Determine how long it takes for it to reach a speed of 10 ft/s. Also, what are the normal reactions at each of the four wheels on the road? The coefficients of static and kinetic friction at the road are us=0.5 and uk=0.3, respectively. Neglect the mass of the wheels.

Answers

Answer:

Time=2.72 seconds

Front wheel reactions= 1393 lb

Rear wheel reactions= 857 lb

Explanation:

The free body diagram is assumed to be the one attached here

The mass, m of the car is  

M=\frac {W}{g} where W is weight and g is acceleration due to gravity

Taking g as 32.2 ft/s^(2) then  

M=\frac {4500}{32.2}=139.75 lbm

Considering equilibrium in x-axis

Ma_G-f=0

Ma_G-(\mu_g* 2N_B)=0

139.75* a_G-(0.3* 2* N_B)=0

0.6N_B=139.75a_g

N_B=232.92a_g

At point A using the law of equilibrium, the sum of moments is 0 hence

-2N_B(6)+4500(2)=-Ma_G(2.5)

-12N_B+9000=-139.75a_G* 2.5

-12(232.92a_G)+900=-349.375a_G

a_g\approx 3.68 ft/s^(2)

The normal reaction at B is therefore

N_B=232.92a_G=232.92* 3.68\approx 857 lb

Consider equilibrium in y-axis

4500-2N_A-2N_B=0

N_A+N_B=2250

N_A+857=2250

N_A=1393 lb

To find time that the car takes to a speed of 10 ft/s

Using kinematic equation

V=u+at

10=0+3.68t

t=\frac {10}{3.68}\approx 2.72 s

Which statement best describes how power and work are related?O A. Power is the ability to do more work with less force.
O B. Power is a measure of how quickly work is done.
O C. Power and work have the same unit of measurement
O D. Power is the amount of work needed to overcome friction.
Pls answer quick

Answers

B

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