Answer:
The diameter would be 267km speed suction i think

A power plant burns natural gas to supply heat to a heat engine which rejects heat to the adjacent river. The power plant produces 800 MW of electrical power and has a thermal efficiency of 38%. Determine the heat transfer rates from the natural gas and to the river, in MW.

List the RTL (Register Transfer Language) sequence of micro-operations needed to execute the instruction STORE X from the MARIE instruction set architecture. Then write the corresponding signal sequence to perform these micro-operations and to reset the clock cycle counter. You may refer to the provided "MARIE Architecture and Instruction Set" file in the Front Matter folder.

___________ are used in an automotive shop and can be harmful to the environment if not disposed of properly.Oil filtersFluorescent lampsMercury-containing lampsAll of the above

The process in which the system pressure remain constant is called a)-isobaric b)-isochoric c)-isolated d)-isothermal

A 120-volt fluorescent ballast has an input current of 0.34 ampere and an input power rating of 22 watts. The power factor of the ballast is ____.

List the RTL (Register Transfer Language) sequence of micro-operations needed to execute the instruction STORE X from the MARIE instruction set architecture. Then write the corresponding signal sequence to perform these micro-operations and to reset the clock cycle counter. You may refer to the provided "MARIE Architecture and Instruction Set" file in the Front Matter folder.

___________ are used in an automotive shop and can be harmful to the environment if not disposed of properly.Oil filtersFluorescent lampsMercury-containing lampsAll of the above

The process in which the system pressure remain constant is called a)-isobaric b)-isochoric c)-isolated d)-isothermal

A 120-volt fluorescent ballast has an input current of 0.34 ampere and an input power rating of 22 watts. The power factor of the ballast is ____.

It is called an Cause-and-effect diagram.

Answer: **199.1 kip**

Explanation:

Given that

Outer diameter is Do = 7 in

Inner diameter Di = ( Do - ( 2×0.5)) = 6 in

Length = 5000 ft = 60000 in

Now change in length of the pipe due to temperature difference

SL = L∝ΔT

= 60000 × 6.5×10^-6(140-40)

SL = 39 in

Also

sL = PL/AE

A = cross sectional area of pipe = π/4(Do^2 - Di^2)

so

P = SL×A×E / L

= (39 × π/4(7^2 - 6^2)×30000) / 60000

= **199.1 kip**

compressive load applied by the pipeline on a PLET due to its thermal expansion is **199.1 kip**

_____________refers to scenarios for which a polymer will permanently flow over time in response a constant applied stress.

**Answer:**

**Viscoelastic stress relaxation **

**Viscoelastic creep**

**Explanation:**

- Viscoelastic stress refers to the reduction of tensile stress with the relaxation time that occurs when the body is kept at a certain length under tensile stress. The purpose of this study was to demonstrate viscoelastic stress relaxation
- Therefore, when the viscous tension stress occurs, the pressure decreases due to the steady-state stress of the phases.
- When under constant pressure, the viscoelastic material experiences a time-dependent increase in pressure. This phenomenon is called viscoelastic creep.
- Therefore the phase constant pressure decreases when there is relaxation in the viscoelastic stress

Answer:

The truck will not stop in time. The truck passes the stop sign by about 63.41 ft before it stops.

Explanation:

The distance that the truck starts slowing down = 80 ft from the stop sign

Using equations of motion, we can calculate the distance it will take the truck to stop, then check of it is less than or more than 80 ft.

u = initial velocity of the truck = 40 mph = 58.667 ft/s

v = final velocity of the truck = 0 ft/s (since it comes to a stop eventually)

x = horizontal distance covered during the deceleration

a = Deceleration = -12 ft/s² (it'll have a negative sign, since it is negative acceleration

v² = u² + 2ax

0² = 58.667² + 2(-12)(x)

24x = 3441.816889

x = 143.41 ft

143.41 ft > 80 ft; hence, the truck will not stop in time. The truck passes the stop sign by about 63.41 ft before it stops.

A truck traveling at 40 mph is approaching a stop sign. At time t₀ and at a distance of 80 ft, the truck begins to slow down by decelerating at 12 ft/s2, will the truck be able to stop in time?

The truck will not be able to stop in time.

==> First lets convert all variables to SI units

1 mph = 0.45m/s

40mph = 40 miles per hour = 40 x 0.45 m/s

40mph = 18m/s

1 ft = 0.3048m

80 ft = 80 x 0.3048m

80 ft = 24.38m

Also;

12ft/s² = 12 x 0.3048m/s²

12ft/s² = 3.66m/s²

==> Now, consider one of the equations of motion as follows;

v² = u² + 2as -----------------(i)

Where;

v = final velocity of motion

u = initial velocity of motion

a= acceleration/deceleration of motion

s = distance covered during motion

Using this equation, lets calculate the distance, s, covered during the acceleration;

We know that;

v = 0 [since the truck comes to a stop]

u = 40mph = 18m/s

a = -12ft/s² = -3.66m/s² [the negative sign shows that the truck decelerates]

Substitute these values into equation (i) as follows;

0² = 18² + 2 (-3.66)s

0 = 324 - 7.32s

7.32s = 324

s =

s = 44.26m

The distance from where the truck starts decelerating to where it eventually stops is 44.26m which is past the stop sign (which is at 80ft = 24.38m). This means that the truck stops, 44.26m - 24.38m = 19.88m, after the stop sign. Therefore, the truck will not be able to stop in time.

The **moment **of **force **at the given **slope **about **point C** is **210 ft-lb.**

The given parameters:

*Vertical slope, = 2**Horizontal slope = 3**Clockwise moment = 330 ft-lb**Counterclockwise moment = 420 ft-lb*

The **magnitude **of the **two moments **are in the following **simple ratio**;

330:420 = 11:14 (*divide **through by *** 30**)

- the A coordinate = (0, 5)
- the B-coordinate = (5,0)

The **line **of action of the **force **passes line **AB **at the final following coordinates;

total ratio of 11:14 = 11 + 14 = 25

The **position **of C = (3, 1)

The** resultant position** of point C = (3 - 2.2, 2.8-1) = (0.8, 1.8)

The **moment **of **force **at the given **slope **about **point C** is calculated as;

3(1.8) + 2(0.8) = 7

Recall that this is the **simplest form** of the **moment **produced by the force.

Moment about C = 7 x 30 = **210 ft-lb**

Thus, the **moment **of **force **at the given **slope **about **point C** is **210 ft-lb.**

Learn more about** moment of force** here: brainly.com/question/6278006

Answer:

(a) 1/L∫Vdt; integral t [0,1]

(b) 1/L∫Vdt; integral t [ 1, infinity]

Explanation:

An Inductor current I, flowing through an inductor depends on the voltage, V, across the inductor and the inductance, L, of the inductor. The switch 1, 2 timing varies the voltage V with time t

The expression for inductor current is given as:

I= 1/L∫Vdt,

where I is equal to the current flowing through the inductor, L is equal to the inductance of the inductor, and V is equal to the voltage across the inductor.

The formula can also be written as:

I= I0 + 1/L∫Vdt, where I is inductor current at time t, and io is inductor current at t = 0. Time can be varied by controlling the switch