# A 2.4 kg toy oscillates on a spring completes a cycle every 0.56 s. What is the frequency of this oscillation?

Explanation:

The period is defined as the time taken by an object to complete a cycle in a simple harmonic motion. As the frequency of the motion increases, the period decreases. Therefore, they are inversely proportional. The frequency does not depend on the mass of the object.

## Related Questions

A racing car is travelling at 70 m/s and accelerates at -14 m/s2. What would the car’s speed be after 3 s?

### Question:

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?

### Statement:

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.

### Solution:

• Initial velocity (u) = 70 m/s
• Acceleration (a) = -14 m/s^2
• Time (t) = 3 s
• Let the velocity of the car after 3 s be v m/s
• By using the formula,

v = u + at, we have

• So, the velocity of the car after 3 s is 28 m/s.

The car's speed after 3 s is 28 m/s.

Hope it helps

If Earth were completely blanketed with clouds and we couldn’t see the sky, could we learn about the realm beyond the clouds? What forms of radiation might penetrate the clouds and reach the ground?

The definition of waves that propagate through electric fields is called electromagnetic waves. The earth, despite being covered with clouds, can be 'affected' because waves such as sunlight or the moon have the ability to penetrate and be visible to the inhabitants of the earth. Microwaves and radio waves would be less affected by the clouds that cover the Earth.

Through these waves, you can know that there is beyond the clouds.

Ultraviolet light, microwaves and radio waves are the radiations that penetrate through the clouds and reach the Earth's surface.

Therefore, the answer is Yes, ultraviolet light, microwaves and radio waves are the forms of radiation that penetrate and reach the ground.

It is indeed possible to learn about the universe beyond the clouds due to other non-visual forms of radiation, mainly radio waves and gamma rays, which can penetrate through the clouds and reach the earth's surface.

### Explanation:

Yes, even if Earth were completely blanketed with clouds and we could not see the sky, we could still learn about the universe beyond the clouds. This is because, in addition to visible light which would be blocked by the clouds, the universe also emits various other forms of radiation that can penetrate the clouds and reach the ground.

Two major types of radiation that could penetrate the dense clouds are radio waves and gamma rays. Radio waves are a form of electromagnetic radiation used in many areas of science and technology, while gamma rays are highly energetic forms of radiation and are used in fields such as astronomy to get valuable information about distant celestial bodies.

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Two capacitors give an equivalent capacitance of 9.42 pF when connected in parallel and an equivalent capacitance of 1.68 pF when connected in series. What is the capacitance of each capacitor?

Explanation:

Let the two capacitance are

It is given that when capacitors are connected in parallel their equvilaent capacitance is 9.42 pF

So --------EQN 1

And when they are connected in series their equivalent capacitance is 1.68 pF

So

-----EQN

On solving eqn 1 and eqn 2

Explain how ultrasound devices use the Doppler effect to create images of body parts. HELP ME ASAP!! Will give brainliest answer!!

Transmits high-frequency (1 to 5 megahertz) sound pulses into your body using a probe. The sound waves travel into your body and hit a boundary between tissues (e.g. between fluid and soft tissue, soft tissue and bone).

Explanation:

Doppler ultrasound works by measuring sound waves that are reflected from moving objects, such as red blood cells.

The guy above is pretty good

Explanation:

I'd go with that answer, give them brainliest

A steel cable lying flat on the floor drags a 20 kg block across a horizontal, frictionless floor. A 100 N force applied to the cable causes the block to reach a speed of 4.2 m/s in a distance of 2.0 m.What is the mass of the cable?

m_cable = 2,676 kg

Explanation:

For this exercise we must look for the acceleration with the kinematic ce relations

v² = v₀² + 2 a x

since the block starts from rest, its initial velocity is vo = 0

a = v² / 2x

a = 4.2² /(2 2.0)

a = 4.41 m / s²

now we can use Newton's second law

Note that the mass that the extreme force has to drag is the mass of the block plus the mass of the cable.

F = (m + m_cable) a

m_cable  = F / a -m

m_cable = 100 / 4.41 - 20

m_cable = 2,676 kg

Unfortunately, the information given does not provide enough data to determine the mass of the steel cable. This is because the force, acceleration, and distance information given only involve the mass of the block, not the cable.

### Explanation:

The question is requesting the mass of the steel cable. However, given the information in the question, we don't actually have enough data to determine this. The application of the force, the acceleration of the block, and the distance it covers are all connected through Newton's second law (F = ma) and the equations of motion, but these only involve the mass of the block, not the mass of the cable. Even if we assumed the cable applies the entire 100 N force to the block, this would only allow us to solve for the acceleration of the block, not the mass of the cable. Therefore, the mass of the steel cable cannot be determined with the information provided in the question.

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Chuck wants to investigate how gas moleculesmove in a container. Which model would be most