f(x) = 5e - x - 2e - 5x

Answer:

**Answer: The second derivative would be **

**Step-by-step explanation:**

Since we have given that

We will find the first derivative w.r.t. 'x'.

So, it becomes,

Then, we will find the second derivative w.r.t 'x'.

**Hence, the second derivative would be **

Please answer ASAP. due tomorrow.

8 and 9 pls thx guys

If a new truck costs $43,750 and it depreciates 18% per year, what will the truck be worth in 5 years? 1 SEE ANSWER

Suppose you are asked to choose a whole number between 1 and 13, inclusive. (a) What is the probability that it is odd? (b) What is the probability that it is even? (c) What is the probability that it is a multiple of 3?

60 % of 80 ASAP pls bruuh

8 and 9 pls thx guys

If a new truck costs $43,750 and it depreciates 18% per year, what will the truck be worth in 5 years? 1 SEE ANSWER

Suppose you are asked to choose a whole number between 1 and 13, inclusive. (a) What is the probability that it is odd? (b) What is the probability that it is even? (c) What is the probability that it is a multiple of 3?

60 % of 80 ASAP pls bruuh

**Answer:**

In logic and mathematics, proof by contradiction is a form of proof that establishes the truth or the validity of a proposition, by showing that assuming the proposition to be false leads to a contradiction.

**Step-by-step explanation:**

**Answer:**

Quadratic function

**Step-by-step explanation:**

Hope this helps you. Have a great day and I hope to get a brainliest.

**Answer: The lower bound is ****0.26**** and the upper bound is ****0.34****.**

**Step-by-step explanation:**

Formula to find the confidence interval for population proportion (p) is given by :_

, where n= sample size

z* = Critical value. (two-tailed)

= Sample proportion.

Let p be the true population proportion of hits to at bats for the entire team during the last season.

As per given , we have

n= 300

By z-table , the critical value for 90% confidence interval : z* = 1.645

**Now , 90% confidence interval for the proportion of hits to at bats for the entire team during the last season:**

**The lower bound is ****0.26**** and the upper bound is ****0.34****.**

hola!

Two angles are said to be complements of one another only when:

→ Makes a right angle

→ They add to 90 degrees

Thus,

According to above. statement!

Option [ B ] :

When together they are equal to a right angle is CORRECT!

hope it helps!

Two angles are said to be complements of one another only when:

→ Makes a right angle

→ They add to 90 degrees

Thus,

According to above. statement!

Option [ B ] :

When together they are equal to a right angle is CORRECT!

hope it helps!

b.) complementary angles add up to 90 degrees

The **average age** of the employees in 2003 is 57.216 years. And, the average age of the **employees **in 2009 is 59.184 years.

Given that;

The **function** A(s) given by ,

A (s) = 0.328s + 50

Now for the average age of **employees **in 2003 and 2009 using the function A(s) = 0.328s + 50, substitute the values of s into the equation.

For the year 2003,

Since s represents the number of **years **since 1981,

Hence, subtract 1981 from 2003:

s = 2003 - 1981

s = 22

Now substitute this value of s into the **function **A(s):

A(22) = 0.328 × 22 + 50

A(22) = 7.216 + 50

A(22) = 57.216

Therefore, the **average age **of the employees in 2003 is 57.216 years.

Similarly, for the year 2009,

s = 2009 - 1981

s = 28

Substituting this value into the function:

A(28) = 0.328 × 28 + 50

A(28) = 9.184 + 50

A(28) = 59.184

Hence, the average age of the **employees **in 2009 is 59.184 years.

To learn more about the **function **visit:

#SPJ12

The mathematical problem involves calculating the average age of employees at a company for the years 2003 and 2009 using the linear function A(s), where 'A(s)' represents the average age and 's' is the number of years since 1981. The calculated average ages for the employees in the years 2003 and 2009 are approximately 57 and 59 years, respectively.

The subject is mathematics, specifically linear functions. Based on the equation A(s) = 0.328s + 50, where 'A(s)' represents the average age of the **employees** and 's' represents the number of years since 1981. In the year 2003, s would be 22 (2003-1981) and in 2009, s would be 28 (2009-1981).

Substituting these values of 's' into the function gives:

For 2003, A(22) = 0.328*22 + 50 = 57.216

For 2009, A(28) = 0.328*28 + 50 = 59.184

Therefore, the average age of the employees at the **company** in 2003 and 2009 were approximately 57 and 59 years, respectively.

#SPJ11

Which floor do you live on?

23 is the floor which you live on