Finding second Derivatives In Exercise,find the second derivate.
f(x) = 5e - x - 2e - 5x

Answers

Answer 1
Answer:

Answer: The second derivative would be

f''(x)=5e^(-x)-50e^(-5x)

Step-by-step explanation:

Since we have given that

f(x)=5e^(-x)-2e^(-5x)

We will find the first derivative w.r.t. 'x'.

So, it becomes,

f'(x)=-5e^(-x)+10e^(-5x)

Then, we will find the second derivative w.r.t 'x'.f''(x)=5e^(-x)+10* -5e^(-5x)\n\nf''(x)=5e^(-x)-50e^(-5x)

Hence, the second derivative would be

f''(x)=5e^(-x)-50e^(-5x)


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Suppose you are asked to choose a whole number between 1 and 13, inclusive. (a) What is the probability that it is odd? (b) What is the probability that it is even? (c) What is the probability that it is a multiple of 3?
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What is the goal of a proof by contradicción?

Answers

Answer:

In logic and mathematics, proof by contradiction is a form of proof that establishes the truth or the validity of a proposition, by showing that assuming the proposition to be false leads to a contradiction.

Step-by-step explanation:

Please help!! Need to know ASAP

Answers

Answer:

Quadratic function

Step-by-step explanation:

Hope this helps you. Have a great day and I hope to get a brainliest.

On an intramural softball team, the proportion of hits to at bats for the entire team during the last season was 30% of 300 attempts. Estimate the true proportion of hits using a 90% CI. The answers need to be proportions (not percents) and rounded to the nearest hundredth (two (2) decimal places) to be counted as correct. (For example, if my CI is (0.1002, 0.2159) then they need to be input as 0.10 and 0.22 to be correct. **These are not the answers to this question :-) **)The lower bound is____ and the upper bound is ____

Answers

Answer: The lower bound is 0.26 and the upper bound is 0.34.

Step-by-step explanation:

Formula to find the confidence interval for population proportion (p) is given by :_

\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

, where n= sample size

z* = Critical value. (two-tailed)

\hat{p} = Sample proportion.

Let p be the true population proportion of hits to at bats for the entire team during the last season.

As per given , we have

n= 300

\hat{p}=0.30

By z-table , the critical value for 90% confidence interval : z* = 1.645

Now , 90% confidence interval for the proportion of hits to at bats for the entire team during the last season:

0.30\pm (1.645) \sqrt{(0.30(1-0.30))/(300)}

0.30\pm (1.645) √(0.0007)

0.30\pm (1.645) (0.0264575131106)

\approx0.30\pm0.0435

=(0.30-0.0435,\ 0.30+0.0435)\n\n=(0.2565,\ 0.3435)\approx(0.26,\ 0.34)

The lower bound is 0.26 and the upper bound is 0.34.

When are two angles called complements of one another? a. when together they are equal to 180 degrees c. when together they are equal to an acute angle b. when together they are equal to a right angle d. when together they are equal to an obtuse angle

Answers

hola!

Two angles are said to be complements of one another only when:
→ Makes a right angle
→ They add to 90 degrees

Thus,
According to above. statement!

Option [ B ] :
When together they are equal to a right angle is CORRECT!

hope it helps!
b.) complementary angles add up to 90 degrees

The function​ A(s) given by ​A(s)equals0.328splus50 can be used to estimate the average age of employees of a company in the years 1981 to 2009. Let​ A(s) be the average age of an​ employee, and s be the number of years since​ 1981; that​ is, sequals0 for 1981 and sequals9 for 1990. What was the average age of the employees in 2003 and in​ 2009?

Answers

The average age of the employees in 2003 is 57.216 years. And, the average age of the employees in 2009 is 59.184 years.

Given that;

The function​ A(s) given by ,

A (s) = 0.328s + 50

Now for the average age of employees in 2003 and 2009 using the function A(s) = 0.328s + 50, substitute the values of s into the equation.

For the year 2003,

Since s represents the number of years since 1981,

Hence, subtract 1981 from 2003:

s = 2003 - 1981

s = 22

Now substitute this value of s into the function A(s):

A(22) = 0.328 × 22 + 50

A(22) = 7.216 + 50

A(22) = 57.216

Therefore, the average age of the employees in 2003 is 57.216 years.

Similarly, for the year 2009,

s = 2009 - 1981

s = 28

Substituting this value into the function:

A(28) = 0.328 × 28 + 50

A(28) = 9.184 + 50

A(28) = 59.184

Hence, the average age of the employees in 2009 is 59.184 years.

To learn more about the function visit:

brainly.com/question/11624077

#SPJ12

Final answer:

The mathematical problem involves calculating the average age of employees at a company for the years 2003 and 2009 using the linear function A(s), where 'A(s)' represents the average age and 's' is the number of years since 1981. The calculated average ages for the employees in the years 2003 and 2009 are approximately 57 and 59 years, respectively.

Explanation:

The subject is mathematics, specifically linear functions. Based on the equation A(s) = 0.328s + 50, where 'A(s)' represents the average age of the employees and 's' represents the number of years since 1981. In the year 2003, s would be 22 (2003-1981) and in 2009, s would be 28 (2009-1981).

Substituting these values of 's' into the function gives:

For 2003, A(22) = 0.328*22 + 50 = 57.216

For 2009, A(28) = 0.328*28 + 50 = 59.184

Therefore, the average age of the employees at the company in 2003 and 2009 were approximately 57 and 59 years, respectively.

Learn more about Linear Functions here:

brainly.com/question/31353350

#SPJ11

Every day, you take the elevator from the basement parking lot that is at level-3. The elevator takes twoseconds per level and you find that it takes 46 seconds to reach your floor.
Which floor do you live on?

Answers

23 is the floor which you live on