What change would you expect on the rate of the SN2 reaction of 1-iodo-2-methylbutane with cyanide ion if the nucleophile concentration is halved and the alkyl halide concentration is unchanged ?

Answers

Answer 1
Answer:

Answer:

Rate of reaction will be half of it's initial value

Explanation:

For the given S_(N)2 reaction, the rate law is -

Rate=k[1-iodo-2-methylbutane][CN^(-)]

Where k is rate constant, [1-iodo-2-methylbutane] is concentration of 1-iodo-2-methylbutane and [CN^(-)] is concentration of CN^(-)

Here nucleophile is the CN^(-) ion

Initiallly, (Rate)_(initial)=k* [1-iodo-2-methylbutane]_(initial)* [CN^(-)]_(initial)

When concentration of CN^(-) is halved then-

Rate=k* [1-iodo-2-methylbutane]_(initial)* ([CN^(-)]_(initial))/(2)=((Rate)_(initial))/(2)

So rate of reaction will be half of it's initial value


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Saved Propane burns in air according to the equation C3Ha(g 502lg)3CO2) + 4H20(g) What volume of O2 in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions? Short Answer Toolbar navigation E I E B IUS EA This question will be sent to your Instructor for grading. 20 of 25 l Next > Prev nere to search

Answers

Answer: 75 liters of O_2 in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Lat STP and contains avogadro's number 6.023* 10^(23) of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles of propane}=\frac{\text{Given volume}}{\text{Molar volume}}=(15.0L)/(22.4L)=0.67moles

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

According to stoichiometry:

1 mole of propane combines with = 5 moles of oxygen

Thus 0.67 moles of propane combine with  = (5)/(1)* 0.67=3.35moles

Volume of O_2=moles* {\text {Molar Volume}}=3.35* 22.4L=75L

Thus 75 liters of O_2 in liters would be required if 15.0 L of propane burns, assuming that all of the gases are under the same conditions.

What element is found in all organic compounds?
a.carbon?

Answers

The element that is found in all organic compounds is Carbon

A car travels for 0.5 hours and goes 25 miles. What is the car's speed? (Remember sad + t)

Answers

Answer:

s = 22.352 m/s

Explanation:

Given data:

Time taken = 0.5 hours

Distance cover = 25 miles

Car speed = ?

Solution:

First of all we will convert the units.

1 hour = 3600 sec

0.5 hr ×3600 sec / 1hr = 1800 sec

miles to meter:

25 mi × 1609 m/ 1 mi = 40233.6 m

Formula:

s =  d/t

s = speed

d = distance

t = time

Now we will put the values in formula.

s = 40233.6 m / 1800 sec

s = 22.352 m/s

Final answer:

The speed of the car, calculated by dividing the distance travelled (25 miles) by the time taken (0.5 hours), is 50 miles per hour.

Explanation:

The subject of the question falls under Mathematics, specifically a section of it named rate, time, and distance problems. The problem is asking us to calculate the speed of a car which can be obtained by dividing the distance travelled by the time taken. Given that the distance travelled by the car is 25 miles and the time taken is 0.5 hours, we can calculate the speed as follows.

  1. Denote the Speed as S, the distance as D, and the time as T.
  2. Since Speed = Distance/Time, we substitute our values into this equation
  3. Therefore, Speed = 25 miles / 0.5 hour = 50 miles/hour

So, the speed of the car is 50 miles per hour.

Learn more about Speed Calculation here:

brainly.com/question/35969362

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What is my percent yield of titanium (II) oxide if I react 20 grams of titanium (II) oxide in excess water (that means TiS is my limiting reactant) and my actual yield of titanium (II) oxide is 13 g?

Answers

Answer:

your percent yield Is

Explanation:

1.5384615385

Brainliest plz

For the combustion reaction of C9H12 in O2: how many moles of O2 is required to react with 0.67 mol C9H12?

Answers

Answer:

8.0 mol O₂

Explanation:

Let's consider the complete combustion reaction of C₉H₁₂.

C₉H₁₂ + 12 O₂ → 9 CO₂ + 6 H₂O

The molar ratio of C₉H₁₂ to O₂ is 1:12. The moles of O₂ required to react with 0.67 moles of C₉H₁₂ are:

0.67 mol C₉H₁₂ × (12 mol O₂/1 mol C₉H₁₂) = 8.0 mol O₂

8.0 moles of O₂ are required to completely react with 0.67 moles of C₉H₁₂.

Answer:

To react with 0.67 moles C9H12 we need 8.04 moles of O2

Explanation:

Step 1: Data given

Number of moles C9H12 = 0.67 moles

Step 2: The balanced equation

C9H12 + 12O2 → 9CO2 + 6H2O

Step 3: Calculate moles of O2 required

For 1 mol C9H12 we need 12 moles of O2 to produce 9 moles of CO2 and 6 moles of H2O

For 0.67 moles of C9H12 we need 12 *0.67 = 8.04 moles of O2

To produce 9*0.67 = 6.03 moles of CO2 and 6*0.67 = 4.02 moles H2O

To react with 0.67 moles C9H12 we need 8.04 moles of O2

Which expression correctly describes energy using SI units? A. 1 J=1kg•m^2/s^2 B. 1 J= 1kg•m/s^2 C. 1 J= 1kg• m/s D. 1 J= 1kg•m^2/s

Answers

Answer:

A. 1 J=1kg•m^2/s^2

Explanation:

Energy refers to the capacity to do work. According to the International System of units (SI units), energy is measured in Joules.

Energy is represented by the force applied over a distance. Force is measured in Newton (N) and distance in metres (m). Hence, energy is Newton × metre (N.m)

Newton is derived from the SI units of mass (Kilograms), and acceleration (metres per seconds^2) i.e Kg.m/s^2, since Force = mass × acceleration.

Since; Energy = Newton × metres

If Newton = Kg.m/s^2 and metres = m

Energy (J) will therefore be; Kg.m/s^2 × m

1J = Kg.m^2/s^2