Answer:
m2=3.2722lbm/s
Explanation:
Hello!
To solve this problem follow the steps below
1. Find water densities and entlapies in all states using thermodynamic tables.
note Through laboratory tests, thermodynamic tables were developed, which allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy, etc.)
through prior knowledge of two other properties, such as pressure and temperature.
D1=Density(Water;T=50;x=0)=62.41 lbm/ft^3
D2=Density(Water;T=120;x=0)=61.71 lbm/ft^3
D3=Density(Water;T=80;x=0)=62.21 lbm/ft^3
h1=Enthalpy(Water;T=50;x=0)=18.05 BTU/lbm
h2=Enthalpy(Water;T=120;x=0)=88 BTU/lbm
h3=Enthalpy(Water;T=80;x=0)=48.03 BTU/lbm
2. uses the continuity equation that states that the mass flow that enters a system is the same as the one that must exit
m1+m2=m3
3. uses the first law of thermodynamics that states that all the flow energy entering a system is the same that must come out
m1h1+m2h2=m3h3
18.05(m1)+88(m2)=48.03(m3)
divide both sides of the equation by 48.03
0.376(m1)+1.832(m2)=m3
4. Subtract the equations obtained in steps 3 and 4
m1 + m2 = m3

0.376m1 + 1.832(m2) =m3

0.624m10.832m2=0
solving for m2
(0.624/0.832)m1=m2
0.75m1=m2
5. Mass flow is the product of density by velocity across the crosssectional area
m1=(D1)(A)(v1)
internal Diameter for 2" Sch 40=2.067in=0.17225ft
m1=(62.41 lbm/ft^3)(0.0233ft^2)(3ft/S)=4.3629lbm/s
6.use the equation from step 4 to find the mass flow in 2
0.75m1=m2
0.75(4.3629)=m2
m2=3.2722lbm/s
Answer:
115 ⁰C
Explanation:
Step 1: The heat needed to melt the solid at its melting point will come from the warmer water sample. This implies
eqution 1
where,
is the heat absorbed by the solid at 0⁰C
is the heat absorbed by the liquid at 0⁰C
the heat lost by the warmer water sample
Important equations to be used in solving this problem
, where equation 2
q is heat absorbed/lost
m is mass of the sample
c is specific heat of water, = 4.18 J/0⁰C
is change in temperature
Again,
equation 3
where,
q is heat absorbed
n is the number of moles of water
tex]\delta {_f_u_s}[/tex] is the molar heat of fusion of water, = 6.01 kJ/mol
Step 2: calculate how many moles of water you have in the 100.0g sample
Step 3: calculate how much heat is needed to allow the sample to go from solid at 218⁰C to liquid at 0⁰C
This means that equation (1) becomes
79.13 KJ +
Step 4: calculate the final temperature of the water
Substitute in the values; we will have,
79.13 kJ + 990.66J* = 1463J*
Convert the joules to kilojoules to get
79.13 kJ + 0.99066KJ* = 1.463KJ*
collect like terms,
2.45366 = 283.133
∴ = 115.4 ⁰C
Approximately the final temperature of the mixture is 115 ⁰C
Given Information:
diameter = d = 15 mm
Length = L = 20 mm
Axial load = P = 300 N
Eₚ = 2.70x10⁹ Pa
vₚ = 0.4
Required Information:
Change in length = ?
Change in diameter = ?
Answer:
Change in length = 0.01257 mm
Change in diameter = 0.003772 mm
Explanation:
Stress is given by
σ = P/A
Where P is axial load and A is the area of the crosssection
A = 0.25πd²
A = 0.25π(0.015)²
A = 0.000176 m²
σ = 300/0.000176
σ = 1697792.8 Pa
The longitudinal stress is given by
εlong = σ/Eₚ
εlong = 1697792.8/2.70x10⁹
εlong = 0.0006288 mm/mm
The change in length can be found by using
δ = εlong*L
δ = 0.0006288*20
δ = 0.01257 mm
The lateral stress is given by
εlat = vₚ*εlong
εlat = 0.4*0.0006288
εlat = 0.0002515 mm/mm
The change in diameter can be found by using
Δd = εlat*d
Δd = 0.0002515*15
Δd = 0.003772 mm
Therefore, the change in length is 0.01257 mm and the change in diameter is 0.003772 mm
Answer:
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Answer:
F = 10.8N
Explanation:
Given the mass m = 0.4kg, v1 = 25m/s, v2 = 12m/s and t =0.5s
From Newtown's second law of motion the average force can be found. This law states that the product of the force experienced by a body and the time t of the force acting on the body is equal to the change in momentum of the body. Mathematically it can be stated as follows
F×t = m(v2 – v1)
F = m(v2 – v1)/t = 0.4(25 – 12)/0.5 = 10.8N
Answer:
B Velocity
Explanation:
This means gravity makes the Moon accelerate all the time, even though its speed remains constant.
Explain why.
Answer: The density is greater at point C
Explanation: At that point
The convention current slowly cools off