Answer:

**Answer:**

**a)the ball will leave the bat at an angle of 61.3° .**

b) the velocity at which it will hit the ground will be v = 27.1 m/s

**Explanation:**

Given,

v = 47.24 m

h = 0.42 m

t = 5.73 s

R = 130 m

a)We know that

R = v cosθ × t

cosθ =

**θ = 61.3° **

**the ball will leave the bat at an angle of 61.3° .**

b)Vx = v cos(θ) = 47.24 x cos 61.3 = 22.7 m/s

v = u + at

Vy = 47.24 x sin 61.3 - 9.81 x 5.73

= -14.8 m/s

v =

v =

v = 27.1 m/s

the velocity at which it will hit the ground will be v = 27.1 m/s

A ball having a mass of 500 grams is dropped from a height of 9.00 meters what is its kinetic energy when it hits the ground

Which two processes allow water to enter the atmosphere

A force of 240.0 N causes an object to accelerate at 3.2 m/s2. What is the mass of the object?

What happens to the pressure in all parts of a confined fluid if the pressure in one part is increased? The pressure in the other parts remains the same.The pressure everywhere increases by different amounts depending on the area of each part.The pressure everywhere increases by the same amount.The pressure everywhere decreases to conserve total pressure.

A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used as a filament in an incandescent light bulb. When the light bulb is connected to a battery, a current of 0.526 A is measured through the filament. (Note: tungsten has a resistivity of 4.9 × 10-8 Ω • m.). How many electrons pass through this filament in 5 seconds?

Which two processes allow water to enter the atmosphere

A force of 240.0 N causes an object to accelerate at 3.2 m/s2. What is the mass of the object?

What happens to the pressure in all parts of a confined fluid if the pressure in one part is increased? The pressure in the other parts remains the same.The pressure everywhere increases by different amounts depending on the area of each part.The pressure everywhere increases by the same amount.The pressure everywhere decreases to conserve total pressure.

A 580-mm long tungsten wire, with a 0.046-mm-diameter circular cross section, is wrapped around in the shape of a coil and used as a filament in an incandescent light bulb. When the light bulb is connected to a battery, a current of 0.526 A is measured through the filament. (Note: tungsten has a resistivity of 4.9 × 10-8 Ω • m.). How many electrons pass through this filament in 5 seconds?

is required at a speed of 7

m/s of a car. What is the?

banking angle

**Answer:**

The banking angle is 23.98 degrees.

**Explanation:**

We have,

Radius of a curve is 35 m

Speed of a car is 7 m/s

It is required to find the banking angle. At equilibrium, net force is equal to the centripetal force between vehicle and the road such that the banking angle is given by :

g is acceleration due to gravity

So, the banking angle is 23.98 degrees.

**Answer:**

a).

b).

c). Δ

**Explanation:**

ΔE=kinetic energy

a).

b).

c).

net work= EkA+EkB

What scientific practice is Rhonda performing

**Answer:he conducts the investigation to see the effect acidic water has on limestone**

**Explanation:**

**Given Information: **

diameter = d = 15 mm

Length = L = 20 mm

Axial load = P = 300 N

Eₚ = 2.70x10⁹ Pa

vₚ = 0.4

**Required Information: **

Change in length = ?

Change in diameter = ?

**Answer: **

Change in length = 0.01257 mm

Change in diameter = -0.003772 mm

**Explanation: **

Stress is given by

σ = P/A

Where P is axial load and A is the area of the cross-section

A = 0.25πd²

A = 0.25π(0.015)²

A = 0.000176 m²

σ = 300/0.000176

σ = 1697792.8 Pa

The longitudinal stress is given by

εlong = σ/Eₚ

εlong = 1697792.8/2.70x10⁹

εlong = 0.0006288 mm/mm

The change in length can be found by using

δ = εlong*L

δ = 0.0006288*20

**δ = 0.01257 mm**

The lateral stress is given by

εlat = -vₚ*εlong

εlat = -0.4*0.0006288

εlat = -0.0002515 mm/mm

The change in diameter can be found by using

Δd = εlat*d

Δd = -0.0002515*15

**Δd = -0.003772 mm**

Therefore, the change in length is** 0.01257 mm **and the change in diameter is** -0.003772 mm**

**Answer:**

**Explanation:**

The potential energy of a system of two charges is given by the expression

Q₁ and Q₂ are two charges and R is distance between the charges.

Given Q₁ = Q₂ = 3.7 X 10⁻⁶ , R = .8 and K = 9 x 10⁹

Putting these values in the equation we have,

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Potential energy = 154.01 x 10⁻³ J

This energy have been spent to bring these repelling two charges at this close distance . The energy spent have been stored as potential energy here which has been calculated.

**Explanation:**

The classic model of a black body made predictions of the emission at small wavelengths in open contradiction with what was observed experimentally, this led Planck to develop a heuristic model. This assumption allowed Planck to develop a formula for the entire spectrum of radiation emitted by a black body, which matched the data.