Answer:

**Answer:**** The mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.**

**Explanation:**

**The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:**

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

**We are given:**

Mass of

Mass of

Mass of sample = 0.1153 g

**We know that:**

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

**For calculating the mass of carbon:**

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.3986 g of carbon dioxide, of carbon will be contained.

**For calculating the mass of hydrogen:**

In 18g of water, 2 g of hydrogen is contained.

So, in 0.0578 g of water, of hydrogen will be contained.

**To calculate the percentage composition of a substance in sample, we use the equation:**

**......(1)**

**For Carbon:**

Mass of sample = 0.1153 g

Mass of carbon = 0.1087 g

**Putting values in equation 1, we get:**

**For Hydrogen:**

Mass of sample = 0.1153 g

Mass of hydrogen = 0.0066 g

**Putting values in equation 1, we get:**

**Hence, the mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.**

Answer the in under 30 minutes and I will give brainliestAfter which event in Indonesia did one of the worst tsunamis form?a hurricanea volcanic eruptiona landslidean earthquake

Solve for x . 875 = 5 x 3 Express the answer to the hundredths place (i.e., two digits after the decimal point).

Identify the characteristics that describe how human proteins are assembled. Check all that apply.

Write the half-reaction for ribose conversion to CO2. Is it an oxidation- or reduction- half reaction

when the pressure that a gas exerts on a sealed container changes from 3.74 atm to ____ atm, the temperature changes from 394 K to 789 K

Solve for x . 875 = 5 x 3 Express the answer to the hundredths place (i.e., two digits after the decimal point).

Identify the characteristics that describe how human proteins are assembled. Check all that apply.

Write the half-reaction for ribose conversion to CO2. Is it an oxidation- or reduction- half reaction

when the pressure that a gas exerts on a sealed container changes from 3.74 atm to ____ atm, the temperature changes from 394 K to 789 K

**Answer:**

**400 Joules**

**Explanation:**

From the question,

The total kinetic energy of the water balling when hits the ground is given as

K.E = 1/2mv².................. Equation 1

Where K.E = Kinetic Energy of water ballon, m = mass of water balloon, v = velocity of water ballon

Given: m = 2 kilograms, v = 20 meters/second.

Substitute these values into equation 1

K.E = (2×20²)/2

K.E = 2×400/2

K.E = 400 Joules

**Answer:**

Covalent bond or common bond is one of the types of chemical bonds. This connection arises from electronic participation. In fact, atoms that need to receive electrons to achieve stable electron arrangement (noble gas electron arrangement or octagonal arrangement) share electrons in their valence layer with other atoms. In this case, the transfer of electrons from one atom to another does not take place, but only a pair of electrons, called a bonded or shared electron pair, belongs to the nucleus of two atoms.

Atomic Number : 35

Neutrons: 45

Charge; -1

35 yooooooooo...........

**Answer:**

**K.E. = 5.4362 × 10⁻¹⁹ J**

**Explanation:**

The expression for Bohr velocity is:

Applying values for hydrogen atom,

Z = 1

Mass of the electron () is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

= 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

Given, n = 2

So,

Kinetic energy is:

So,

**K.E. = 5.4362 × 10⁻¹⁹ J**

**Answer:**

Process B : constant pressure condition

Process A : constant volume condition

**Explanation:**

**In case of constant pressure, some of the energy is used to do work on the surrounding to keep pressure constant. Due to this, the total heat energy is less than in case of constant volume. In Case of constant Volume all of heat is available, produced in reaction because no work is done.**

If we look at our data,we will find that process B has energy 23.3 KJ which is less than process A, the energy of which is 25.9 KJ. It** means Process B is occurred at constant pressure condition and Process A has occurred at constant volume condition**

Answer:

Henderson Hasselbalch equation: pH = pKa + log [salt]/[acid]

You need to know the pKa for acetic acid. Looking it up one finds it to be 4.76

(a). pH = 4.76 + log [0.13]/[0.10]

= 4.76 + 0.11

= 4.87

(b) KOH + CH3COOH =>H2O + CH3COOK so (acid)goes down and (salt)goes up. Assuming no change in volume, you have 0.10 mol acid - 0.02 mol = 0.08 mol acid and 0.13 mol salt + 0.02 mol = 0.15 mol salt

pH = 4.76 + log [0.15]/[0.08]

= 4.76 + 0.27

= 5.03

The pH of the buffer with 0.11 mol acetic acid and 0.13 mol sodium acetate in 1.00 L is 4.91, calculated using the **Henderson**-Hasselbalch equation. The second part of the question regarding the pH change after the addition of '2' is unanswerable without further information on what is being added.

To answer the question of what the pH of the buffer solution containing 0.11 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L is, we can apply the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

Where [A-] is the concentration of the acetate ion and [HA] is the concentration of acetic acid. For acetic acid, the pKa is approximately 4.76. Since we have 0.11 mol of acetic acid and 0.13 mol of sodium acetate in 1.00 L solution, the concentrations are 0.11 M and 0.13 M respectively.

Substituting these values into the Henderson-Hasselbalch equation gives:

pH = 4.76 + log(0.13/0.11)

Calculating the log(0.13/0.11) yields approximately 0.15. Therefore:

pH = 4.76 + 0.15 = 4.91

The question "What is the pH of the buffer after the addition of 2?" seems to be incomplete, as it does not specify what '2' refers to. If '2' refers to adding 2 moles of a strong acid or base, for instance, the pH would change significantly and the buffer capacity might be exceeded. The exact effect on pH would depend on the nature of the substance added (acid or base) and its quantity. Without specifics, this part of the question cannot be accurately answered.

The concept of buffer capacity is relevant to discuss here. Buffer capacity refers to the amount of acid or base a buffer can absorb without a significant change in pH. Buffer solutions with higher molar **concentrations **of both the acid and the corresponding salt will have greater buffer capacity.

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