Answer:

**Answer:**

**change in length is 3.397 cm**

**Explanation:**

Given data

long = 91 m = 9100 cm

coefficient for concrete (a) = 1.2 × 10−5 ( ◦C)−1

temperature = 56 F = (56× 5/9) ◦C

to find out

how much spacing is needed to allow

solution

we know allow space is given by this formula

change in length = coefficient for concrete × given length × temperature .............1

put all value in equation 1

change in length = 1.2 × 10−5 × 9100 × (56× 5/9)

change in length = 3.397 cm

**so change in length is 3.397 cm**

A 17.0 resistor and a 6.0 resistor are connected in series with a battery. The potential difference across the 6.0 resistor is measured as 15 V. Find the potential difference across the battery.

(a) Determine the electric field strength between two parallel conducting plates to see if it will exceed the breakdown strength for air (3 ? 106 V/m). The plates are separated by2.98 mm and a potential difference of 5575 V is applied. (b) How close together can the plates be with this applied voltage without exceeding the breakdown strength?

Which of the following wouldhave low electromagnetic energy? A. X-rays B. ultraviolet waves C. radio waves

What is the magnitude of the line charge density on the power line? Express your answer using two significant figures.

According to the second law of thermodynamics, it is impossible for ____________. According to the second law of thermodynamics, it is impossible for ____________. heat energy to flow from a colder body to a hotter body an ideal heat engine to have the efficiency of 99% an ideal heat engine to have non-zero power. a physical process to yield more energy than what is put in

(a) Determine the electric field strength between two parallel conducting plates to see if it will exceed the breakdown strength for air (3 ? 106 V/m). The plates are separated by2.98 mm and a potential difference of 5575 V is applied. (b) How close together can the plates be with this applied voltage without exceeding the breakdown strength?

Which of the following wouldhave low electromagnetic energy? A. X-rays B. ultraviolet waves C. radio waves

What is the magnitude of the line charge density on the power line? Express your answer using two significant figures.

According to the second law of thermodynamics, it is impossible for ____________. According to the second law of thermodynamics, it is impossible for ____________. heat energy to flow from a colder body to a hotter body an ideal heat engine to have the efficiency of 99% an ideal heat engine to have non-zero power. a physical process to yield more energy than what is put in

**Answer:**

V(peak voltage) is the highest voltage that the waveform will ever attain and the Vrms(root-mean-square) is the effective voltage of the total waveform representing the AC source.

**Answer:**

1838216 J

**Explanation:**

95 km/h = 26.39 m/s

40 km/h = 11.11 m/s

Initial kinetic energy

= .5 x 1600 x(26.39)²

= 557145.67 J

Final kinetic energy

= .5 x 1600 x ( 11.11)²

= 98745.68 J

Loss of kinetic energy

= 458400 J

Loss of potential energy

= mg x loss of height

= 1600 x 9.8 x 340 sin 15

= 1379816 J

Sum of Loss of potential energy and Loss of kinetic energy

= 1379816 + 458400

= 1838216 J

This is the work done by the friction . So this is heat generated.

To calculate the thermal energy dissipated from the brakes of a car, use the equation Q = Mgh/10, where Q is the energy transferred to the brakes, M is the mass of the car, g is the acceleration due to gravity, and h is the height of the hill. The temperature change of the brakes can then be calculated using the equation Q = mc∆T, where m is the mass of the brakes and c is its specific heat capacity.

The thermal energy dissipated from the brakes of a car can be calculated by converting the gravitational potential energy lost by the car into internal energy of the brakes. By using the equation Q = Mgh/10, where Q is the energy transferred to the brakes, M is the mass of the car, g is the acceleration due to gravity, and h is the height of the hill, we can calculate the thermal energy dissipated. From there, the temperature change of the brakes can be calculated using the equation Q = mc∆T, where m is the mass of the brakes and c is its specific heat capacity.

#SPJ11

B. infrared light, visible light, and UV light only

C. X-rays and gamma rays only

D. all regions of the spectrum

**Answer:**

**D. all regions of the spectrum**

**Explanation:**

I did some research ; )

The individual calcium atom has a positive and not negative, 2 charge

**Answer:**

The individual calcium atom has a positive, not negative, 2 charge.

**Explanation:**

Did the quiz also had it on the unit test on edgunity.

Hope this helps guys!

Brick is held at a position which is at height 2 m from the floor

Now it is released from rest and hit the floor after t = 4 s

Now the acceleration of the brick is given by

a)

Now in order to find the tension in the string

we can use Newton's law

part b)

Now for the pulley

moment of inertia=

m = 30 kg

R = 2 m

I =

I = 60 kg m^2

Now the angular speed just before brick collide with the floor

v = 1 m/s

Now we will have

L = angular momentum = I w =

L = 60 *

L = 30 kg m^2/s

(1) The **acceleration **of the **car **will **be **

(2) The **time **taken

(3) The **time **is taken by the **car **to slow **down **from 20m/s to 10m/s

(1) The **acceleration **of the car will be **calculated **as

Here

u= 14

(2) The **time **is taken for the **same acceleration **to 20

u=20

(3) The **time **is taken to **slow **down from **20m**/s to **10m**/s with the **same acceleration**

From **same **formula

v=10

u=20

Thus

(1) The **acceleration **of the **car **will **be **

(2) The **time **taken

(3) The **time **is taken by the **car **to slow **down **from 20m/s to 10m/s

To know more about** the Equation of the motion **follow

**(a) **

The car's acceleration is given by

where

v = 0 is the final velocity

u = 14 m/s is the initial velocity

t = 4 s is the time elapsed

Substituting,

where the negative sign means the car is slowing down.

**(b) 5.7 s**

We can use again the same equation

where in this case we have

is again the acceleration of the car

v = 0 is the final velocity

u = 20 m/s is the initial velocity

Re-arranging the equation and solving for t, we find the time the car takes to come to a stop:

**(c) **

As before, we can use the equation

Here we have

is again the acceleration of the car

v = 10 is the final velocity

u = 20 m/s is the initial velocity

Re-arranging the equation and solving for t, we find